Here are the results of a regression of Car Deaths in the UK by month from Jan 1969 to Dec 1984 on a dummy variable: 0 = no seatbelt law, and 1 = seat belt law (the law was instituted in February 1983)Coefficients:Estimate Std. Error t value Pr(> | t |) (Intercept) 125.870 1.849 68.082 < 2e-16 *Seatbelts -25.609 5.342 -4.794 3.29e-06 * R-squared = 0.11a. Did the seat belt law make a difference? b. Is there a need to add more variables to the model? c. How would you justify your answer with numbers? d. What possible independent / predictor variables could you add to this model?

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

Hello!

The objective of this exercise is to test if the Y: "number of car deaths in one month" is affected by the variable X: "seat belt law"

The linear regression was estimated:

Coefficients: Estimate Std. Error t value Pr(> | t |)

(Intercept) 125.870 1.849 68.082 < 2e-16 *

Seatbelts -25.609 5.342 -4.794 3.29e-06 *

R-squared = 0.11

Then the estimated model is:

Yi= 125.870 - 25609Xi

a. Did the seat belt law make a difference?

Yes.

If the hypothesis is that the seat belt law reduces the number of car deaths:

H₀: β ≥ 0

H₁: β < 0

With α: 0.05

The p-value for the test is: 3.29e-06

The p-value is less than the significance level, the seat belt law modifies the average number of car deaths.

b. Is there a need to add more variables to the model?

Yes. According to the given model, the independent variable isn't good enough to explain the variability of the dependent variable, i.e. most of the variability of the dependent variable is given by the errors.

The investigator needs to add new variables or change the model to determine one that is a better predictor of the dependent variable.

c. How would you justify your answer with numbers?

To see if the independent variable is a good predictor of the dependent variable you have to look at the coefficient of determination. This coefficient gives you an idea of how much of the variability of the dependent variable is explained by the independent variable under the estimated model.

The value of R²= 0.11 or 11% means that only 11% of the variability of the number of car deaths is due to the seat belt law.

It looks like the variable "seat belt law" isn't a good regressor.

d. What possible independent/predictor variables could you add to this model?

X: "increasing of traffic controls"

X: "decreasing the speed limits"

X: "opening road safety courses in the communities"

I hope it helps!


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A student is trying to solve the set of two equations given below:Equation A: x + z = 6
Equation B: 3x + 2z = 1

Which of the following is a possible step used in eliminating the z-term?
Multiply equation A by −2.
Multiply equation B by 2.
Multiply equation A by 3.
Multiply equation B by 3.

Answers

a possible step used in eliminating the z-term is "multiply equation A by −2."

x + z = 6
3x + 2z = 1

x + z = 6 / *(-2)
3x + 2z = 1


-2x - 2z = -12
3x+ 2z = 1

-2x + 3x -2z +2z = -12 +1
x = -11

-11 + z = 6
z = 6 + 11
z = 17

Answer:Multiply equation A by -2 is correct everyone

Step-by-step explanation:

I just took the test and checked;)

2. The U.S public health service calculates that service health care costs have increased from $43 →> $46.5 -> $49.8 -> $53.63 per patient during the last four years, what has been the cost per patient over the four-year period?​

Answers

To calculate the cost per patient over the four-year period, we need to add up the costs for each year and then divide by the number of years.

The costs per patient for the four years are:

Year 1: $43

Year 2: $46.5

Year 3: $49.8

Year 4: $53.63

To find the total cost over the four years, we add up these costs:

$43 + $46.5 + $49.8 + $53.63 = $193.93

Now, we divide the total cost by the number of years (which is 4) to find the average cost per patient over the four-year period:

$193.93 / 4 = $48.48

Therefore, the cost per patient over the four-year period is approximately $48.48.

Final answer:

The cost per patient over the four-year period is $193.16.

Explanation:

To find the cost per patient over the four-year period, we need to calculate the percent increase for each year and then multiply the percent increase by the previous year's cost. Here are the steps:

  1. Calculate the percent increase for each year:
    • From $43 to $46.5: ($46.5 - $43) / $43 * 100% = 8.14%
    • From $46.5 to $49.8: ($49.8 - $46.5) / $46.5 * 100% = 7.10%
    • From $49.8 to $53.63: ($53.63 - $49.8) / $49.8 * 100% = 7.70%
  2. Multiply the percent increase by the previous year's cost for each year:
    • Year 1: $43 * (1 + 8.14%) = $46.57
    • Year 2: $46.5 * (1 + 7.10%) = $49.85
    • Year 3: $49.8 * (1 + 7.70%) = $53.74
  3. Add the costs for each year: $43 + $46.57 + $49.85 + $53.74 = $193.16

Therefore, the cost per patient over the four-year period is $193.16.

Learn more about healthcare costs here:

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A patient is given a 50 mg dose of medicine the medicines affective Ness decreases every hour at a constant rate of 40% what is the exponential decay function that models this scenario how much medicine will be left in the patient's system after two hours

Answers

The following formula is used to find the answer.
                                       D = 50 mg (0.6^n)
D is the dosage 
n is at any hour 
Using this formula and solving the equation for it, the answer is 18.

A birthday cake was cut into equal pieces, and 10 pieces were eaten. Thefraction below shows how much cake was left over. According to the fraction,
into how many pieces was the cake cut?
1
11
A. 1
B. 10
C. 21
O D. 11
TO

Answers

The answer is D, 11.

Do phone surveys provide adequate coverage of households with respect to one particular parameter? The parameter is the proportion of households without children. If telephone surveys provide adequate coverage of households, then p , the proportion of households without children in the set of all future samples reached by phone, must be equal to the proportion of households without children in the population of all households. Suppose that Thomas, a market analyst, contacts a simple random sample of 300 households as part of a national telephone survey. Of the households contacted, 129 households, or 43 %, have no children and 57 % have at least one child. The most recent census indicates that 48 % of all households have no children and 52 % have at least one child.

Answers

Complete  Question

The complete question is shown on the first uploaded image

Answer:

Based on the result of his test , Thomas should fail to reject null hypothesis at a significance level of  0.01. Thomas sufficient evidence  to conclude that  the proportion of  households without children in the set of all future samples reached by phone is not equal to the proportion of households without children in the population of all households.

Step-by-step explanation:

From the question we see that the p-value is greater than the level of significance (0.01 )so we fail to reject the null hypothesis.

This means that Thomas has  sufficient evidence to conclude that the proportion of households without children in the set of all future samples reached by phone is not equal to the proportion of households without children in the population of all households.

What is the domain of h?A) -5≤h(x)≤4
B) The h(x) values -4,-2,2,4, and 6
C) The h(x) values -5,-4,0,2, and 4
D) -4≤h(x)≤6 ​

Answers

Answer:

C

Step-by-step explanation:

  • The domain is all the x numbers for each point
  • So -5,-4,0,2,4