MATHEMATICS COLLEGE

Giving a test to a group of students, the grades and gender are summarized below. Round your answers to 4 decimal places. A B C Total
Male 16 13 6 35
Female 2 3 8 13
Total 18 16 14 48
If one student is chosen at random:
1. Find the probability that the student was female AND got a "B".
2. Find the probability that the student was male AND got a "A".
3. Find the probability that the student got a B.

Answers

Answer 1

Answer:

Answer:

1). 0.1667

2). 0.3333

3). 0.3333

Step-by-step explanation:

1). Probability that the student was female and got a 'B'

= $\frac{\text{Number of female students who got B}}{\text{Total number of students}}$

= $(3)/(48)=(1)/(16)$

= 0.1667

2). Probability that the student was male and got an 'A'

= $\frac{\text{Number of male students who got A }}{\text{Total number of students}}$

= $(16)/(48)$

= $(1)/(3)$

= 0.3333

3). Probability that the student got a B = $\frac{\text{Number of students who got B}}{\text{Total number of students}}$

= $(16)/(48)$

= $(1)/(3)$

= 0.3333

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Answers

Answer:35652846437467

Step-by-step explanation:simple math

Step-by-step explanation:

1.23

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HELPPPPPPPP MEEEEEEE

Answers

Answer: The first choice should be correct

Step-by-step explanation:

Well I hope this is correct

Option C or they are alternate interior angles is correct.

When two lines are crossed by another line (called the Transversal): Alternate Interior Angles are a pair of angles on the inner side of each of those two lines but on opposite sides of the transversal

A regular polygon has an interior angle of 172º.
Find the number of sides of this polygon.

Answers

Answer:

45 sides

Step-by-step explanation:

If each of the interior angles is 172 degrees, then each of the exterior angles is 8 degrees. Since the sum of the exterior angles of any polygon is 360 degrees, there are 360 / 8 = 45 exterior angles and 45 sides.

Determine if the function is odd, even or neither. Explain your answer

Answers

Answer:

Even

Step-by-step explanation:

The picture is the explanation.

I hope this helps.

The inside diameter of a randomly selected piston ring is a randomvariable with mean value 12 cm and standard devtiation of .04cm. a. If Xbar is the sample mean diameter form a random sample of=16 rings, where is the sampling distrbution of Xbar centered andwhat is the standard deviation of the Xbar distribution?

b. Answer the questions above for a sample of size n=64

c.find the probability that the average diameter of pistonrings from a sample size 16 is more than 11.95cm

d. For which of the above two random saples is Xbar morelikely to be within .01cm of 12cm? Explain.

Answers

Using the normal distribution and the central limit theorem, it is found that:

a) The sampling distribution is approximately normal,centered at 12 cm and with a standard deviation of 0.01 cm.

b) The sampling distribution is approximately normal,centered at 12 cm and with a standard deviation of 0.005 cm.

c) 100% probability that the average diameter of piston rings from a sample size 16 is more than 11.95 cm.

d) Due to the lower standard error, the sample of 64 is more likely to be within 0.01 cm of 12 cm.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = (X - \mu)/(\sigma)$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = (\sigma)/(√(n))$ .

In this problem:

Mean of 12 cm, thus $\mu = 12$
Standard deviation of 0.04 cm, thus $\sigma = 0.04$ .

Item a:

Sample of 16, thus $n = 16$ and $s = (0.04)/(√(16)) = 0.01$

The sampling distribution is approximately normal,centered at 12 cm and with a standard deviation of 0.01 cm.

Item b:

Sample of 64, thus $n = 64$ and $s = (0.04)/(√(64)) = 0.005$

The sampling distribution is approximately normal,centered at 12 cm and with a standard deviation of 0.005 cm.

Item c:

This probability is 1 subtracted by the p-value of Z when X = 11.95, thus:

$Z = (X - \mu)/(\sigma)$

By the Central Limit Theorem:

$Z = (X - \mu)/(s)$

$Z = (11.95 - 12)/(0.01)$

$Z = -5$

$Z = -5$ has a p-value of 0.

1 - 0 = 1.

100% probability that the average diameter of piston rings from a sample size 16 is more than 11.95 cm.

Item d:

Due to the lower standard error, the sample of 64 is more likely to be within 0.01 cm of 12 cm.

A similar problem is given at brainly.com/question/24663213

Answer:

The answer is below

Step-by-step explanation:

Given that:

mean value (μ) = 12 cm and standard deviation (σ) = 0.04 cm

a) Since a random sample (n) of 16 rings is taken, therefore the mean (μx) ans standard deviation (σx) of the sample mean Xbar is given by:

$\mu_x=\mu=12\ cm\n\sigma_x=(\sigma)/(√(n) )=(0.04)/(√(16) )=0.01$

The sampling distribution of Xbar is centered about 12 cm and the standard deviation of the Xbar distribution is 0.01 cm

b) Since a random sample (n) of 64 rings is taken, therefore the mean (μx) ans standard deviation (σx) of the sample mean Xbar is given by:

$\mu_x=\mu=12\ cm\n\sigma_x=(\sigma)/(√(n) )=(0.04)/(√(64) )=0.005\ cm$

The sampling distribution of Xbar is centered about 12 cm and the standard deviation of the Xbar distribution is 0.005 cm

c) n = 16 and the raw score (x) = 11.95 cm

The z score equation is given by:

$z=(x-\mu_x)/(\sigma_x) =(x-\mu)/(\sigma/√(n) ) \nz=(11.95-12)/(0.04/√(16) )\n z=-5$

P(x > 11.95 cm) = P(z > -5) = 1 - P(z < -5) = 1 - 0.000001 ≅ 1 ≅ 100%

d) for n = 64, the standard deviation is 0.01 cm, therefore it is more likely to be within .01cm of 12cm

Complete the following statement. 3(4 x 8) (3 x4) (_)

Answers

Answer:

Step-by-step explanation:

(8*4)3=96

3*4=12

12*8=96

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