The required number of girls in the school assembly is 1380.
Given,
There were 1200 boys at a school assembly. The ratio of boys to girls at the assembly was 20:23. Number of girls in the assembly line is to be determined
The ratio can be defined as the proportion of the fraction of one quantity towards others. e.g.- water in milk.
Representation of ratio of two values a and b, ratio = a:b.
Let the number of girls in the school assembly be x.
There were 1200 boys at a school assembly. The ratio of boys to girls at the assembly was 20:23. So the ratio can be written as,
1200 : x = 20 : 23
1200 / x = 20 / 23
x = 1200 * 23 / 20
x = 60 * 23
x = 1380
Here, the number of girls in the school assembly is 1380.
Thus the required number of girls in the school assembly is 1380.
Learn more about ratio here:
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I believe the answer is 1,600 girls
B) -74
C) 7
D) 9
If the quadratic equation x^2 + 18x +74=0 is rewritten in the form (x-p)²= Q. Then the value of Q is 7.
It is a polynomial that is equal to zero. Polynomial of variable power 2, 1, and 0 terms are there. Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.
Given
The quadratic equation .
If the quadratic equation is rewritten in the form
Add and subtract 9² in the equation.
We know the formula
Then equation will be
Add 7 both the sides, then
Thus the value of Q is 7.
More about the quadraticequation link is given below.
Step-by-step explanation:
The given quadratic equation:
To find, the value of Q = ?
Adding both sides 81, we get
⇒ - 2(x)8 +
= 81 - 74
Using the algebraic identity,
⇒ is the form of
Here, P = 9 and Q = 7
Thus, the value of Q "option C) 7" is correct option.
The partial products of 35×7 are 35 and 210. They are obtained by multiplying 7 by 5 and 7 by 30 respectively. The sum of these partial products gives the final product of 245.
In Mathematics, the process of multiplication can be broken down into steps called partial products. When you are multiplying 35 by 7, you could break this down into two steps based on the digits of the number 35 which are 30 and 5. First, multiply 7 by 5 (the one place of 35) to get 35. Secondly, multiply 7 by 30 (the tens place of 35) to get 210. These are your partial products, 35 and 210. When added together, they give the product of the original multiplication problem, 245.
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Answer: 3/10
Step-by-step explanation:
3/10 • 100 = 30%
Answer:
12y +16yi
Step-by-step explanation:
The thing about complex numbers is that you can treat them as binomials and use all of the things you know about multiplying and factoring polynomials.
Here, we assume you have ...
(5 +2yi)(4 -3i) -(5 -2yi)(4 -3i)
The factor (4 -3i) can be factored out, so you have ...
= ((5 +2yi) -(5 -2yi))(4 -3i)
= (4yi)(4 -3i)
= 16yi -12yi²
At this point, the definition of i comes into play, and you replace i² with -1.
= 12y +16yi
F. |x + 3| = 5
G. |x − 3| = 5
H. |x + 5| = 3
J. |x − 5| = 3
K. |x + 5| = −3