MATHEMATICS MIDDLE SCHOOL

100 POINTS HELP PLEASEEEE !!!HURRY!!!

Answers

Answer 1

Answer:

Question # 1 Solution

Answer:

$(h-f)(-8)=-229$

Step-by-step Solution:

Given

$h(r)=-4r^(2)+4$

$f(r)=2r-7$

$(h-f)(r)=h(r)-f(r)$

$(h-f)(r)=-4r^(2)+4-(2r-7)$

$(h-f)(r)=-4r^(2)+4-2r+7)$

We have to find $(h-f)(-8)$

So,

$(h-f)(-8)=-4(-8)^(2)+4-2(-8)+7)$

$(h-f)(-8)=-4(64)+4+16+7$

$(h-f)(-8)=-256+4+16+7$

$(h-f)(-8)=-229$

∴ $(h-f)(-8)=-229$

Question # 2 Solution

Answer:

∴ $(f.p)(9)=38979$

Step-by-step Solution:

Given

$f(s)=7s-2$

$p(s)=s^(3)-10s$

$(f.p)(s)=f(s).p(s)$

$(f.p)(s)=(7s-2)(s^(3)-10s)$

$(f.p)(s)=7s^4-2s^3-70s^2+20s$

We have to find $(f.p)(9)$

So,

$(f.p)(9)=7\left(9\right)^4-2\left(9\right)^3-70\left(9\right)^2+20\left(9\right)$

$(f.p)(9)=7\cdot \:9^4-2\cdot \:9^3-70\cdot \:9^2+20\cdot \:9$

$(f.p)(9)=9^4\cdot \:7-9^3\cdot \:2-9^2\cdot \:70+180$

$(f.p)(9)=45927-1458-5670+180$

$(f.p)(9)=38979$

∴ $(f.p)(9)=38979$

Question # 3 Solution

Answer:

$((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))$

Step-by-step Solution:

Given

$p(r)=r^(3)+6r$

$f(r)=11r+8$

We have to find $((f)/(p))(r)$

Using the formula

$((f)/(p))(r)=(f(r))/(p(r))$

$p(r)=r^(3)+6r$

$f(r)=11r+8$

$((f)/(p))(r)=(11r+8)/(r^(3)+6r)$

$((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))$

∴ $((f)/(p))(r)=(11r+8)/(r\left(r^2+6\right))$

Question # 4 Solution

Answer:

$(h-p)(k)=5k^2-3-k^3-8k$

Step-by-step Solution:

Given

$h(k)=5k^(2)-3$

$p(k)=k^(3)+8k$

We have to find $(h-p)(k)$

Using the formula

$(h-p)(k)=h(k)-p(k)$

$h(k)=5k^(2)-3$

$p(k)=k^(3)+8k$

$(h-p)(k)=5k^(2)-3-(k^(3)+8k)$

$(h-p)(k)=5k^2-3-k^3-8k$

∴ $(h-p)(k)=5k^2-3-k^3-8k$

Question # 5 Solution

Answer:

$((p)/(g))(11)=(1287)/(155)$

Step-by-step Solution:

Given

$p(b)=b^(3)-4b$

$g(b)=b^(2)+4b-10$

We have to find $((p)/(g))(11)$

$((p)/(g))(b)=(p(b))/(g(b))$

$((p)/(g))(b)=(b^(3)-4b)/(b^(2)+4b-10)$

$((p)/(g))(11)=(11^(3)-4(11))/(11^(2)+4(11)-10)$

$((p)/(g))(11)=(1287)/(155)$

∴ $((p)/(g))(11)=(1287)/(155)$

Question # 6 Solution

Answer:

$(f+g)(x)=x^2+20x-18$

Step-by-step Solution:

Given

$g(x)=x^(2)+11x-7$

$f(x)=9x-11$

We have to find $(f+g)(x)$

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=9x-11+(x^(2)+11x-7)$

$(f+g)(x)=9x-11+x^(2)+11x-7$

$(f+g)(x)=x^2+20x-18$

∴ $(f+g)(x)=x^2+20x-18$

Question # 7 Solution

Answer:

$h(10)+g(10)=-983$

Step-by-step Solution:

Given

$h(w)=-11w^(2)-7$

$g(w)=w^(2)+3w-6$

We have to find $h(10)+g(10)$

So,

$h(10)=-11(10)^(2)-7$

$h(10)=-1107$ .....[1]

and

$g(10)=10^(2)+3(10)-6$

$g(10)=124$ .....[2]

Adding Equation [1] and Equation [2]

$h(10)+g(10)=-1107+124$

$h(10)+g(10)=-983$

∴ $h(10)+g(10)=-983$

Question # 8 Solution

Answer:

$(f+g)(-3)=-6$

Step-by-step Solution:

Given

$g(b)=b^(2)+9b+10$

$f(b)=3b+11$

We have to find $(f+g)(-3)$

$(f+g)(b)=f(b)+g(b)$

$(f+g)(b)=3b+11+b^(2)+9b+10$

$(f+g)(-3)=3(-3)+11+(-3)^(2)+9(-3)+10$

$(f+g)(-3)=-6$

∴ $(f+g)(-3)=-6$

Question # 9 Solution

Answer:

$(f.h)(k)=33k^3+22k-12k^2-8$

Step-by-step Solution:

Given

$f(k)=-11k+4$

$h(k)=-3k^(2)-2$

We have to find $(f.h)(k)$

$(f.h)(k)=f(k).h(k)$

So,

$(f.h)(k)=(-11k+4).(-3k^(2)-2)$

$\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

∵ FOIL means (First, Outer, Inner, Last)

$(f.h)(k)=\left(-11k\right)\left(-3k^2\right)+\left(-11k\right)\left(-2\right)+4\left(-3k^2\right)+4\left(-2\right)$

$(f.h)(k)=33k^3+22k-12k^2-8$

∴ $(f.h)(k)=33k^3+22k-12k^2-8$

Question # 10 Solution

Answer:

$p(-8)-f(-8)=-581$

Step-by-step Solution:

Given

$p(s)=s^(3)+6s$

$f(s)=-2s+5$

We have to find $p(-8)-f(-8)$

So,

$p(-8)=(-8)^(3)+6(-8)$

$p(-8)=-560.....[1]$

and

$f(-8)=-2(-8)+5$

$f(-8)=21.....[2]$

Subtracting Equation [2] from Equation [1]

$p(-8)-f(-8)=-560-21$

$p(-8)-f(-8)=-581$

∴ $p(-8)-f(-8)=-581$

Keywords: function operation

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Answer 2

Answer:

Answer:

-2229

Step-by-step explanation:

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The distance of planet Jupiter from the Sun is approximately 7.8 ⋅ 108 kilometers, and the distance of planet Saturn from the Sun is 1.5 ⋅ 109 kilometers. About how many more kilometers is the distance of Saturn from the Sun than the distance of Jupiter from the Sun

Answers

Answer:

Option C is the correct answer,

Step-by-step explanation:

The distance of planet Jupiter from the Sun is approximately 7.8 x 10⁸ kilometers.

Distance from Jupiter to Sun = 7.8 x 10⁸ kilometers

The distance of planet Saturn from the Sun is 1.5 x 10⁹ kilometers.

Distance from Saturn to Sun = 1.5 x 10⁹ kilometers

Difference in distances = 1.5 x 10⁹ - 7.8 x 10⁸ = 15 x 10⁸ - 7.8 x 10⁸

Difference in distances = 7.2 x 10⁸ kilometers

Answer: Difference in distances = 7.2 x 10⁸ kilometers

Step-by-step explanation:

12 divided by 0.2 without a calculator

Answers

12 divided by 0.2 without a calculator is 60.

Find the area of the parallelogram.
cm2
(Simplify your answer.)

Answers

Answer:

187 cm^2

Step-by-step explanation:

Area of a parallelogram is base times height. 17 cm is the base and 11 cm is the height so, 17 cm times 11 cm equals 187 cm^2.

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Jodi rents a car for 2 weeks. It costs $210 for each week plus $0.10 per mile.Which equation represents the relationship between the number of miles traveled, m, and the total rental cost, r?
O A r = 2(210+ 0.10m)
B. r= 210 + 2 (0.10m)
C. r = 2 (210) (0.10m)
D. r= 2(210) +0.10m

Answers

The equation represents the relationship between the number of miles traveled, m, and the total rentalcost, r is r = 2(210) + 0.10m.

What is the equation?

An equation can be defined as a mathematical statement consisting of an equal symbol between two algebraic expressions that have the same value.

Jodi rents a car for 2 weeks.

It costs $210 for each week plus $0.10 per mile.

Let, the number of miles traveled, m, and the total rental cost, r.

The rent of the car for 2 weeks is;

$= 2 * 210$

The equation represents the relationship between the number of miles traveled, m, and the total rentalcost, r is;

r = the rent of the car for 2 weeks + the total rental cost

r = 2(210) + 0.10m

Hence, the equation represents the relationship between the number of miles traveled, m, and the total rentalcost, r is r = 2(210) + 0.10m.

Learn more about equation here;

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It c r=2 (210) (0.10m)

Using the right triangle below find the cosine of angle A.

Answers

For the given triangle, the cosine of angle A equals $(1)/(2)$ .

Step-by-step explanation:

Step 1; In the given triangle, the opposite side has a length of 9 units, the adjacent side has a length of 3√3 units while the hypotenuse of the triangle measures 6√3 units. To calculate the cosine of angle A we divide the adjacent side by the hypotenuse side.

cos A = $(adjacent side)/(hypotenuse)$ .

Step 2; Length of the adjacent side = 3√3 units.

Length of the hypotenuse side = 6√3 units.

cos A = 3√3 / 6√3

cos A = $(1)/(2)$ .

To check we also have A = 60° and cos 60° = $(1)/(2)$ .

Tori planted 3 packets of 31 seeds in her garden each seed grew and produced 23 flowers how many flowers total did tori grow

Answers

Answer: 2139 flowers

Step-by-step explanation:

3 packets of 31 seeds=93 seeds

Each seed grew 23 flowers

Tori planted 93×23 numbers of flowers

Answer:

2,139 Flowers

Step-by-step explanation:

Tori plants 3 packets of 31 seeds meaning a total of 93 seeds.

Each seed (93) grew and produced 23 flowers. 93x23=2,139 flowers

If each seed produced 23 flowers and each packet has 31 seeds then your answer is 2,139 flowers was the total Tori grew