Suppose a spacecraft orbits the moon in a very low, circular orbit, just a few hundred meters above the lunar surface. The moon has a diameter of 3500 km, and the free-fall acceleration at the surface is 1.6m/s2. How fast is this spacecraft moving? A. 53 m/s
B. 75 m/s
C. 1700 m/s
D. 2400 m/s

Answers

Answer 1

Answer:

Spacecraft will be moving in 1700 m/s.

Option C

Explanation:

The diameter of the moon is 3500 km and the free fall acceleration at the surface is given as $1.6\ \mathrm{m} / \mathrm{s}^2$

The radius will be half of the diameter of the moon that can be written as:

$r_{\text {moon }}=1.75 * 10^(6)$

By the application of the equation for orbit speed, we get

$\begin{aligned}&v_{\text {orbit}}=√(r * q)\n&v_{\text {orbit}}=\sqrt{\left(1.75 * 10^(6)\right) *\left(1.6\ \mathrm{m} / \mathrm{s}^(2)\right)}\n&v_{\text {orbit}}=1700\ \mathrm{m} / \mathrm{s}\end{aligned}$

Answer 2

Answer:

Final answer:

The spacecraft is moving at approximately 1700 m/s.

Explanation:

The speed of the spacecraft can be calculated using the formula for the orbital speed of an object:

V = sqrt((G * M) / r)

Where V is the velocity, G is the gravitational constant (approximately 6.67 x 10^-11 N m²/kg²), M is the mass of the moon (approximately 7.35 x 10^22 kg), and r is the radius of the moon plus the altitude of the spacecraft.

Plugging in the known values, we have:

V = sqrt((6.67 x 10^-11 N m²/kg²) * (7.35 x 10^22 kg) / (3.5 x 10^6 m + 200 m))

Calculating the square root of this expression gives us approximately 1700 m/s.

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A disk-shaped space station 175 m in diameter spins uniformly about an axis perpendicular to the plane of the disk through its center. How many rpm (rev/min) must this disk make so that the acceleration of all points on its rim is g/2?
Which of the following is an example of simple harmonic motion? A. A ball bouncing on a sidewalk B. Calculating the angle of elevation for a building C. A police car shining a spotlight into buildings as it drives by D. The height of the water in Monterey Bay
When vibrational motion in an object increases, which is a true statement? A. Kinetic energy, temperature, and thermal energy increase. B. Kinetic energy, temperature, and thermal energy decrease. C. Kinetic energy and temperature decrease; thermal energy increases. D. Kinetic energy and temperature increase; thermal energy decreases.

The Otto-cycle engine in a Mercedes-Benz SLK230 has a compression ratio of 8.8.Part A. What is the ideal efficiency of the engine? Use γ=1.40.
Part B. The engine in a Dodge Viper GT2 has a slightly higher compression ratio of 9.6. How much increase in the ideal efficiency results from this increase in the compression ratio?

Answers

Answer:

58.1%

59.533%

1.433%

Explanation:

$(V_1)/(V_2)$ = Compression ratio

$\gamma$ = Specific heat ratio = 1.4

Efficiency in the Otto cycle is given by

$\eta=1-(1)/(\left((V_1)/(V_2)\right)^(\gamma-1))\n\Rightarrow \eta=1-(1)/(\left(8.8\right)^(1.4-1))\n\Rightarrow \eta=0.581$

The ideal efficiency of the engine is 58.1%

$\eta=1-(1)/(\left((V_1)/(V_2)\right)^(\gamma-1))\n\Rightarrow \eta=1-(1)/(\left(9.6\right)^(1.4-1))\n\Rightarrow \eta=0.59533$

The ideal efficiency of the engine is 59.533%

Increase in efficiency is 59.533-58.1 = 1.433%

A car enters the freeway with a speed of 6.4 m/s and accelerates uniformly for 3.2 km in 3.5 min. How fast (in m/s) is the car moving after this time?

Answers

Answer:

24.1 m/s

Explanation:

Using newton's equation of motion,

s = (v+u)t/2 .............................. Equation 1

Where s = distance, v = Final velocity, u = initial velocity, t = time.

making v the subject of the equation,

v = (2s/t)-u........................... Equation 2

Given: s = 3.2 km= ( 3.2×1000) m = 3200 m , t = 3.5 min = (35× 60 ) s = 210 s, u = 6.4 m/s.

substitute into equation 2

v = (2×3200/210)-6.4

v = 24.076 m/s

v ≈ 24.1 m/s

Aristotle supported which of these views? The Sun and all the planets revolve around Earth. The speed of a free-falling object is independent of its weight. Earth and other planets revolve around the Sun. Every action has an equal and opposite reaction. The fifth element, ether, does not exist in heavenly bodies. NextReset

Answers

Final answer:

Aristotle supported geocentrism, the view that the Sun and all the planets revolve around the Earth. He did not support the concept of free-fall speed being independent of weight, a concept later verified by Galileo. Aristotle also proposed the existence of a fifth element, ether, in heavenly bodies.

Explanation:

Aristotle, the ancient Greek philosopher, supported the view that the Sun and all the planets revolve around the Earth. This model is known as Geocentrism or Ptolemaic system. His belief was widely accepted until the Copernican revolution in the 16th century, which provided a heliocentric model. The heliocentric model, the belief that the Earth and other planets revolve around the Sun, was questioned by Aristotle.

Furthermore, Aristotle did not support the view that the speed of a free-falling object is independent of its weight. This idea was later verified by Galileo. Also, the idea of every action having an equal and opposite reaction is associated with Newton's third law of motion, a concept that emerged much later than Aristotle's time. Lastly, Aristotle did propose the existence of a fifth element, ether, that he believed existed in the heavenly bodies. Hence, he did not support the view that ether does not exist in heavenly bodies.

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Aristotle believed the earth was the centre of the solar system, with the sun, moon and planets 'orbiting' it on 'celestial spheres'.

In fact the idea Aristotle had was that this explained something about the nature of the universe. He noticed that when you push an object, it slows down and stops. Therefore he divided the universe into 'earth-like stuff' which preferred to remain stationary, and 'heavenly stuff' which preferred to be in motion. Newton showed this idea to be false when he effectively unified motion and being at rest - if you move at a constant velocity (like in a very large ship) you can't tell if you're moving at a constant velocity or whether you are at rest

If you were to throw flour on the man in the photo, the flour would stick to the man's chest everywhere but on his scar. Why?

Answers

Explanation:

Flour typically sticks to surfaces due to adhesive forces, and it's more likely to stick to areas with moisture or oils on the skin. If the scar on the man's chest lacks moisture or oils (which is common for scars), the flour may have difficulty adhering to that specific area. However, it could stick to the surrounding skin where there might be more moisture or natural oils.

As we move above up from one trophic level to another in an energy pyramid, what happens to the energy?a. It decreases from one trophic level to another.
b. It remains the same for each trophic level.
c. It increases from one trophic level to another.

Answers

As we move above up from one trophic level to another in an energy pyramid, what happens to the energy?

a. It decreases from one trophic level to another.
b. It remains the same for each trophic level.
c. It increases from one trophic level to another.

As we move above up from one trophic level to another in an energy pyramid, the energy level decreases from one trophic level to another. The answer is letter A.

17. Alyssa just bought a new set of string lights for her bedroom. She decided to use the lights to outline her mirror. The lights are on a series circuit. If Alyssa were to buy more lights so that they can go all around her bedroom, what will happen to following quantities?:a. The resistance of the entire circuit will (increase/decrease).
b. The current through each bulb will (increase/decrease).
c. The voltage available to each bulb will (increase/decrease).

Answers

a. The resistance will increase

b. The current will decrease

c. The voltage through each bulb will

Explanation:

a. For a series of resistors, the equivalent resistance is given by

$R=R_1+R_2+...+R_n$

so, we see that adding more resistors in series, will increase the total resistance.

b. In a series circuit, the current through each bulb is the same for each bulb, and it is equal to the current flowing in the circuit, which is given by Ohm's law

$I=(V)/(R)$

where V is the voltage supplied by the battery and R the total resistance of the circuit. Since the voltage provided by the battery, V, does not change, while the total resistance R increases, the current I will increase.

c. The voltage through each bulb is given by

$V=R_i I$

where R_i is the resistance of the individual resistor and I is the current. Since the value of R_i does not change, while I (the current) has decreased, the voltage available to each bulb, V, will decrease.

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