Answer:
We cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds
Step-by-step explanation:
We cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds because we do not know the number of possible outcomes, the events , sample space or the sample size. Probability is calculated with frequency or occurrences or how much certainty there is.It is a number between 0 and 1. 1 indicates certainty and 0 indicates impossibility. Without a range or frequency how can we depict the possibility or impossibility of an occurrence of 200 pounds.
You cannot calculate the probability that a randomly selected passenger weighs more than 200 pounds without sufficient data on the weight distribution of the population. Weight can widely vary due to individual factors, making it hard to have a definitive measurement. Accurate data and appropriate statistical methods are necessary.
The process of calculating the probability that a randomly selected passenger weighs more than 200 pounds would be seemingly simple deductive reasoning. However, it's impossible without access to sufficient data that provides information about the population's weight distribution. Since people's weights are variable and oftentimes private information, it would not be straightforward to obtain accurate and representative data.
For instance, while we can calculate the probability of drawing a certain card from a deck because we know the total number of cards and the number of each type of card, determining the likelihood of a randomly chosen passenger weighs over 200 pounds requires knowledge of the weight distribution of all potential passengers.
Moreover, weight can vary significantly among individuals due to factors like age, gender, health status, and so on. This makes it a continuous variable, meaning it's also affected by dimensions like decimal form and scientific notation when measuring. We'd need accurate data and appropriate statistical methodologies to consider all possible weight ranges and their frequencies for a reliable calculation of such probability.
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Answer:
Step-by-step explanation:
The movement of the minute hand of the clock is circular. This means that a complete movement of the minute hand of the clock is the same as the angle formed at the center of the circle. The sum of the angles at a point is 360 degrees. The minute hand travels 360 degrees in a 60 minutes. It means that the degrees travelled in a minute is
360/60 = 6 degrees
The hour hand travels 360 degrees in 60 minutes. Therefore, the angle that the hour hand travels in 1 minute is
360/6 = 6 degrees
The minute hand of a clock travels 6° in 1 minute. The hour hand travels 0.5° in 1 minute.
To answer this question, we first need to consider what a full rotation is. A complete circle, one full rotation, is 360°. The minute hand of a clock completes one full rotation, or 360°, every hour or 60 minutes.
In 1 minute, the minute hand would have covered 1/60 of a full rotation. To calculate this in degrees, we multiply 360° by 1/60, which gives us 6°. Therefore, the minute hand of a clock travels 6° in one minute.
The hour hand moves more slowly. It takes 12 hours to complete a full rotation or 360°. In 1 minute, the hour hand covers, 360° divided by (12 hours x 60 minutes), which gives us 0.5°. Therefore, the hour hand of a clock moves 0.5° in 1 minute.
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Answer:
a) For this case we can use the definition of weighted average given by:
And if we replace the values given we have:
b)
c)
Step-by-step explanation:
Assuming the following question: "One sample has a mean of M=8 and a second sample has a mean of M=16 . The two samples are combined into a single set of scores.
a) What is the mean for the combined set if both of the original samples have n=4 scores"
For this case we can use the definition of weighted average given by:
And if we replace the values given we have:
b) what is the mean for the combined set if the first sample has n=3 and the second sample has n=5
Using the definition we have:
c) what is the mean for the combined set if the first sample has n=5 and the second sample has n=3
Using the definition we have:
Answer:
P2 affirms P1 and the conclusion is in the same direction.
P1--->P2--->C
This argument is valid.
Step-by-step explanation: using the syllogism rules.
Premises 1 (P1) = Some foreign emissaries are persons without diplomatic immunity,
Premises 2 (P2) = so some persons invulnerable to arrest and prosecution are foreign emissaries
Conclusion (C) = because no persons with diplomatic immunity are persons vulnerable to arrest and prosecution.
From the argument:
P1 uses "some", that means it's not "all" foreign emissaries person that does not have diplomatic immunity. This means that some other foreign emissaries have diplomatic immunity
P2 uses "some", that means it's affirms to that part of P1 which states that some foreign emissaries have diplomatic immunity.
The conclusion is valid because the part of P2 which states that some foreign emissaries are vulnerable to arrest, which affirms with P1 which states that Some foreign emissaries are persons without diplomatic immunity. That means no persons with diplomatic immunity are persons vulnerable to arrest and prosecution. This conclusion literally means that if you don't have diplomatic immunity, you are vulnerable to arrest and prosecution.
Therefore;
P2 affirms P1 and the conclusion is in the same direction.
P1--->P2--->C
This argument is valid.
Based on the graph of the linear function (in blue) and parabolic function (in red), the corresponding output values include the following;
(f∘g)(2) = -1.
(g∘f)(2) = 1.
(f∘f)(2) = 0.
(g∘g)(2)= 4.
(f + g)(4) = 7.
(f/g)(2) = DNE.
In Mathematics and Geometry, a function composition is an operation (∘) that combines two functions f(x) and g(x), in order to produce a composite function h(x) = (g∘f)(x), such that h(x) = g.
In this exercise, we would determine the corresponding output values for each of the composite functions by using the substitution method as follows;
(f∘g)(2) = f(g(2))
f(g(2)) = f(0)
f(0) = -1.
Part 2.
(g∘f)(2) = g(f(2))
g(f(2)) = g(1)
g(1) = 1.
Part 3.
(f∘f)(2) = f(f(2))
f(f(2)) = f(1)
f(1) = 0.
Part 4.
(g∘g)(2) = g(g(2))
g(g(2)) = g(0)
g(0) = 4.
Part 5.
(f + g)(4) = f(4) + g(4)
f(4) + g(4) = 3 + 4
f(4) + g(4) = 7.
Part 6.
(f/g)(2) = f(2)/g(2)
f(2)/g(2) = 1/0
f(2)/g(2) = DNE.
Read more on composite function here: brainly.com/question/30660139
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Step-by-step explanation:
g(g(2))
= g(0)
= 4