MATHEMATICS MIDDLE SCHOOL

Joseph uses 30 grams of sugar and 24 grams of butter.a) how many times the amount of sugar is the amount of butter?
b) how many times the amount of butter is the amount of sugar?

Answers

Answer 1

Answer:

Answer:

(a ) 1.25 times.

(b) 0.8 times.

Step-by-step explanation:

We have been given that Joseph uses 30 grams of sugar and 24 grams of butter.

(a) To find the amount of sugar is how many times the amount of butter, we need to find 30 is what part of 24.

$(30)/(24)=(5)/(4)=1.25$

Therefore, the amount of sugar is 1.25 times the amount of butter.

(b) To find the amount of butter is how many times the amount of sugar, we need to find 24 is what part of 30.

$(24)/(30)=(4)/(5)=0.8$

Therefore, the amount of butter is 0.8 times the amount of sugar.

Answer 2

Answer:

Answer:

check step by step

Step-by-step explanation:

A) 30 divided by 24

B) 24 divided by 30

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A number (n) is equal to 60 decreased by 3 times the number. what is the value of n?

Answers

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Determine the equations of the vertical and horizontal asymptotes, if any, for g(x)=x-2/x^2+4x+3 A.x=-1,x=3
B.x=-1,x=-3,y=0
C.x=1,x=-3,y=0
D.x=-1,x=-3

Answers

Answer:

B. x = -1, x = -3, y = 0

Step-by-step explanation:

$g(x)=(x-2)/(x^2+4x+3)\n\nvertical\ asymptote:\n\nx^2+4x+3=0\nx^2+x+3x+3=0\nx(x+1)+3(x+1)=0\n(x+1)(x+3)=0\iff x+1=0\ \vee\ x+3=0\n\n\boxed{x=-1\ \vee\ x=-3}\n\nhorizontal\ asymptote:\n\n\lim\limits_(x\to\pm\infty)(x-2)/(x^2+4x+3)=\lim\limits_(x\to\pm\infty)(x^2\left((1)/(x)-(2)/(x^2)\right))/(x^2\left(1+(4)/(x)+(3)/(x^2)\right))=\lim\limits_(x\to\pm\infty)((1)/(x)-(2)/(x^2))/(1+(4)/(x)+(3)/(x^2))=(0)/(1)=0\n\n\boxed{y=0}$

M+-2/3=-1/3 what is m?

Answers

$m + - (2)/(3) = - (1)/(3) \n \n m - (2)/(3) = - (1)/(3) \ / \ simplify \n \n m = - (1)/(3) + (2)/(3) \ / \ add \ (2)/(3) \ to \ each \ side \n \n m = (1)/(3) \ / \ simplify \n \n Answer: \fbox {m = 1/3} \ or \ \fbox {m = 0.3333}$

M+ -2/3= -1/3
⇒ M+ (-2/3)= -1/3
⇒ M= -1/3+ 2/3
⇒ M= 1/3

Final answer: M= 1/3~

Solve the Equation.

x^2= 150

Urgent!

Answers

So to "unpack" this equation remember the inverse of exponential functions is square root.

x^2 = 150

to simply just use a radical, $√(150)$ = 12.24744...

Final answer:

The solutions to the mathematical equation x^2 = 150 are x = 12.25 and x = -12.25.

Explanation:

To solve the equation x^2 = 150, we have to find the value of x. The first step is to take the square root of both sides. The square root of x^2 is x, and the square root of 150 equals approximately ±12.25. So, the answer is:

x = ±√150

x = ±12.25

Thus, the solutions for the equation x^2 = 150 are x = 12.25 and x = -12.25.