What is the volume of this equation?A four- sided pyramid with base edge of 5 ft and h = 4 ft

Answers

Answer 1

Answer:

Answer:

Volume ≈ 33.33 cubic feet

Step-by-step explanation:

The question is:

Find the volume of a right square pyramid with base square edges measuring 5 feet each and a height of the pyramid be 4 feet.

So, the base is a square with side length 5 feet.

And the height of the pyramid is 4 feet.

The volume of a pyramid is given by the formula:

$V=(a^2 h)/(3)$

Where

a is the square base side length (given as 5)

h is the height of the pyramid (given as 4)

Now we substitute and find the value:

$V=(a^2 h)/(3)\nV=((5)^2 (4))/(3)\nV=33.33$

The volume is around 33.33 cubic feet

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Answers

$(x+1)/(3) = (x+5)/(x) \n \n 3(x+5)=x(x+1) \n \n 3x+15=x^2+x \n \n 3x+15-x^2-x=0 \n \n -x^2+2x+15=0 \n \n \boxed{\boxed{ \Delta=b^2-4ac}} \n \n \Delta=2^2-4\cdot(-1)\cdot15 \n \Delta=4+60\n \Delta=64 \n \n \boxed{\boxed{\text{X}_(1,2)= (-b\pm √(\Delta) )/(2a) }} \n \n \n \boxed{\text{X}_(1)= (-b - √(\Delta) )/(2a) = (-2-8)/(-2) = (10)/(2) = 5} \n \boxed{\text{X}_2= (-b+ √(\Delta) )/(2a) = (-2+8)/(-2) = (6)/(2)=3 }$