CHEMISTRY MIDDLE SCHOOL

Which substance is use to increase the rate of catalyst?​

Answers

Answer 1
Answer:

Answer:

A catalyst is a substance that can be added to a reaction to increase the reaction rate without getting consumed in the process. ... Enzymes are proteins that act as catalysts in biochemical reactions. Common types of catalysts include enzymes, acid-base catalysts, and heterogeneous (or surface) catalysts.

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Which condensed structural formula represents an unsaturated compound?(1) CH3CHCHCH3 (3) CH3CH3
(2) CH3CH2CH3 (4) CH4

Answers

(1) CH3CHCHCH3.................


(1) CH3CHCHCH3 because it contains a double bond.

Beverly and Carl are in a race. Their graphs show the data Which best describes the race?A. Even though for a majority of the race they accelerated at the same rate, Carl won because his initial acceleration was greater than Beverly’s
B. Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s.
C.Beverly accelerated at a greater rate for the entire race.
D. Carl accelerated at a greater rate for the entire race

Answers

The correct option is B.

Acceleration is defined as the rate of velocity of a body per unit time; that is, acceleration is given by the ratio of velocity and time. Looking at the graph given above, it can be seen that, the two runners started with different initial velocity; Beverly started with the initial velocity of 15 m/s while Carl started with the initial velocity of 10 m/s. For the rest of the race, the two runners maintains similar acceleration but Beverly won because her initial velocity was higher.
The correct answer is B
i just finished the test. hope this helps

Which compound is classified as a hydrocarbon?(1) butanal (3) 2-butanol
(2) butyne (4) 2-butanone

Answers

Answer: The correct answer is Option 2.

Explanation:

Hydrocarbons are defined as the compounds which have a covalent bond present between hydrogen and carbon atoms. For Example: CH_4 is a hydrocarbon. H_2O,CO_2 are not considered as hydrocarbons.

For the given options:

Option 1: butanal

The chemical formula for this compound is CH_3CH_2CH_2CHO

This is not considered as a hydrocarbon because a covalent bond is present between carbon and oxygen atom.

Option 2: butyne

The chemical formula for this compound is CH\equiv CCH_2CH_3

This is considered as a hydrocarbon because covalent bonds are present between carbon and hydrogen atoms only.

Option 3: 2-butanol

The chemical formula for this compound is CH_3CH(OH)-CH_2CH_3

This is not considered as a hydrocarbon because a covalent bond is present between carbon and oxygen atom.

Option 4: 2-butanone

The chemical formula for this compound is CH_3C(O)-CH_2CH_3

This is not considered as a hydrocarbon because a covalent bond is present between carbon and oxygen atom.

From the above information, the correct answer is Option 2.
(2) butynu........................

11. The density of liquid chloroform is 1.48 g/mL. What is its density in units of lb/in?(2.54 cm = 1 in., 2.205 lb = 1 kg)

Answers

The density of the liquid chloroform is 0.0535 lb/in³.

The given parameters:

  • Density of the liquid, = 1.48 g/mL

The density of the liquid chloroform in pounds per cubic inches (lb/in³) is calculated by multiplying with the appropriate equivalent units as demonstrated below;

\rho = 1.48 \ (g)/(mL) * (1 \ mL)/(cm^3) * ((2.54cm)^3)/((1\ in)^3) * (1 \ kg)/(1000 \ g) * (2 .205 \ lb)/(1 \ kg) = 0.0535 \ lb/in^3

Thus, the density of the liquid chloroform in pounds per cubic inches is determined to be 0.0535 lb/in³.

Learn more about conversion of density here: brainly.com/question/13858006

Answer:

5.35*10^-2\ lb/in^3

Explanation:

Given density of chloroform is 1.48 g/mL

We need to find the density in lb/in^3

Also, we have given 2.54 cm = 1 in and 2.205 lb = 1 kg

We know 1ml=1cm^3

Also, 2.54 cm = 1 in

2.54^3\ cm^3=1\ in^3\n16.38\ cm^3=1\ in^3\n16.38\ cm^3=16.38\ ml=1\ in^3

And 1000 g = 1 kg

1\ g=(1kg)/(1000)\n\n1\ kg=2.205\ lb\n\n1\ g=(2.205\ lb)/(1000)=2.205*10^(-3)\ lb

Now we will plug

1\ ml=(1)/(16.38)\ in^3 \n\nAnd\ 1\ g=2.205*10^-3\ lb

So,

1.48\ (g)/(ml)=1.48* 2.205*10^(-3)(lb)/((in^3)/(16.38) )\n \n=1.48*2.205*16.38*10^(-3)(lb)/(in^3)\n =5.35*10^(-2)(lb)/(in^3)

How are chemical and physical changes alike?

Answers

They are both changing things. There is a change in the mixture/substance

Tutorial queshers Set 1| Why does molecule become a chiral if has a Plane of symmetry even through it has stereocenter​

Answers

Answer:

Here's what I get.

Explanation:

Consider the molecule shown below.

It has two chiral centres, labelled R and S, and an internal mirror plane that makes the right and left halves of the molecule mirror images of each other.

If we pass a beam of plane-polarized light through the sample, the R portion of the molecule will rotate the light in a certain direction.

However, the S portion will rotate the light by the same amount in the opposite direction.

The two effects cancel each other, so the molecule has no net effect on plane-polarized light.

Even though the molecule has two chiral centres, it is achiral because it has an internal plane of symmetry.
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