MATHEMATICS MIDDLE SCHOOL

WHOEVER GETS IT FAST AND CORRECT GETS 20 POINTSA 16 ounce package of brown rice costs $1.44. What is the price per ounce?
A) 6¢
B) 9¢
Eliminate
C) 11¢
D) 14¢

Answers

Answer 1

Answer: Isn’t it 9c?
Because $1.44/16 is 9

Answer 2

Answer:

Answer:6€

Step-by-step explanation:

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Krista's softball team played 35 games this season and lost only 7 of them.What percent of their games did Krista's team lose?
Five more than twice a number is 17

22 lbs = how many oz

Answers

22 lbs = x oz

1 lb = 16 oz

22 × 16 = 352

22 lbs = 352 oz

the answer is 352 oz
and for every pound there are 16 ounces

Convert 15 out of 20 into a decimal

Answers

Simplify 15/20 into 3/4

then 3 divided by 4= 0.75

the answer is 0.75

Howdy there! ;) The answer to your question is 0.75. I got the answer because you divide 15 and 20( 15/20) So simplify if you want to. 15/5=3 20/5=4 equals 3/4 there are 4 25's in a hundred 25,50,75,100 so since 3/4 is three then it would be 0.75.

Hope I helped! :D

Using the given points and line, determine the slope of the line. (-3, 0) and (2, 7) slope = -7/5 slope = -5/7
slope = 5/7
slope = 7/5

Answers

(-3, 0) and (2, 7)

slope = (7 - 0) /(2 +3)

slope = 7/5

Answer

slope = 7/5

The pre-image point B(-4, 3) is translated to B'(-1, 1). What was the translation used?A. ( x + 3, y + 2)
B. ( x - 3, y - 2)
C. ( x + 3, y - 2)
D. ( x - 3, y + 2)

Answers

the answer is C. youre welcome

Answer:

C. ( x +3, y -2)

Which are acceptable names for the plane?Choose all answers that are correct.

A.
plane AU

B.
plane JAU

C.
plane R

D.
plane ABC

Answers

answers is d,and c but i am not positive

The temperature at 6:00 a.m. was ‐3.5°C. From 6:00 to 7:00, the temperature increased 2.5°C. From 7:00 to 8:00, it decreased by 0.25°C, and from 8:00 to 11:00, the temperature dropped 3.25°C. Which expression shows the temperature in °C at 11:00 a.m.?

Answers

The expression that shows the temperature in °C is $-3.5+2.5+(-0.25)+(-3.25)$ .

Step-by-step explanation:

Step 1:

The initial temperature at 6.00 am was $-3.5$ °C.

Step 2:

From 6.00 to 7.00 am, the temperature increased by another 2.5°C, so the temperature at 7.00 am was $(-3.5 + 2.5)$ °C.

Step 3:

From 7.00 to 8.00 a.m, the temperature decreased by another 0.25°C, so the temperature at 8.00 am was $(-3.5+2.5+(-0.25))$ °C.

Step 4:

From 8.00 to 11.00 a.m, the temperature dropped by another 3.25 °C, so the temperature at 11.00 am was $(-3.5+2.5+(-0.25)+-(3.25))$ °C which is represented by the fourth option.