Answer:
HOCH2CH2CH2OH.
Explanation:
HOCH2CH2CH2OH is more soluble in water than CH3CH2CH2OH because propandiol have two alcoholic group attached to it hence, it can form more efficient hydrogen bonding with water whereas the hydrogen bonding in CH3CH2CH2OH would be less prominent as it has only one alcoholic group.
Answer:
HOCH2CH2CH2OH
Answer:
-196 kJ
Explanation:
By the Hess' Law, the enthalpy of a global reaction is the sum of the enthalpies of the steps reactions. If the reaction is multiplied by a constant, the value of the enthalpy must be multiplied by the same constant, and if the reaction is inverted, the signal of the enthalpy must be inverted too.
2S(s) + 3O₂(g) → 2SO₃(g) ΔH = -790 kJ
S(s) + O₂(g) → SO₂(g) ΔH = -297 kJ (inverted and multiplied by 2)
2S(s) + 3O₂(g) → 2SO₃(g) ΔH = -790 kJ
2SO₂(g) → 2S(s) + 2O₂(g) ΔH = +594 kJ
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2S(s) + 3O₂(g) + 2SO₂(g) → 2SO₃(g) + 2S(s) + 2O₂(g)
Simplifing the compounds that are in both sides (bolded):
2SO₂(g) + O₂(g) → 2SO₃(g) ΔH = -790 + 594 = -196 kJ
The enthalpy of the reaction where sulfur dioxide is oxidized to sulfur trioxide is -395 kJ.
The calculation of the enthalpy change of the reaction in which sulfur dioxide is oxidized to sulfur trioxide involves Hess's Law, which states that the enthalpy change of a chemical reaction is the same whether it takes place in one step or several steps. This can be solved by comparing the enthalpy changes given in the two reactions presented.
First, consider the reactions given:
2S(s) + 3O₂(g) → 2SO₃(g), ΔH = -790 kJ
S(s) + O₂(g) → SO₂(g), ΔH = -297 kJ
From these reactions, it is seen that the first reaction can be re-written as:
2SO₂(g) + O₂(g) → 2SO₃(g), ΔH = -790 kJ
However, this reaction contains two moles of SO₂ whereas the reaction in question only requires one mole. Thus, the enthalpy change for the reaction becomes: ΔH = -790 KJ / 2 = -395 kJ.
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B.an acid-base neutralization reaction to produce oxygen gas
C.a displacement reaction involving two metals
D.a combustion reaction involving burning a metal in oxygen
In this reaction, reactant HgO decomposed into more than one products and reaction is called decomposition. Hg in HgO has oxidation number of +2 whereas oxidation number of Hg in product side is zero( zero because Hg is in its elemental form) so Hg is reduced. Hence option A is correct.
Decomposition can be defined as the “to break down” of complex substance or organic matter into a simpler inorganic matter.
It is one of the essential processes of the ecosystem, decomposition is a metabolic process which take up raw materials in the form of complex compounds, processing it and then converting it into simpler compounds.
some of the Bacteria, fungi and a few other microorganisms are involve in the process of decomposition as feed on dead organisms to survive.
in this process decaying and dead animals and plants serve as the raw materials undergo breakdown process and produces nutrients, carbon dioxide, and water; Microbes which involve in this process collectively known as saprophytes.
For more details regarding decomposition, visit
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Answer:- Law of definite proportions.
Explanations:- The chemical composition of a compound is always constant means it contains the same elements in exactly same proportions by mass. This is called "Law of definite proportions."
Molecular formula of water is . It has two hydrogen atoms and one oxygen atom. Atomic mass of H is 1.008 and that of oxygen atom is 15.999.
Molar mass of water = 2(1.008) + 15.999 = 18.015
mass percentage of H = = 11.2%
mass percentage of O = = 88.8%
These percentages are always fix, no matter from where the sample of water is collected.
Cu(s) + S(s) CuS(s)
C6H12O6(s) + 6O2(g) 6CO2(g) + 6H2O(g)
5C2O42-(aq) + 2MnO4-(aq) + 16H+(aq) 10CO2(g) + 2Mn2+(aq) + 2H2O(l)
Ag+(aq) + I-(aq) AgI2(s)
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Answer : Option A) .
Explanation : The reaction of hydrogen gas with iodine in solid phase will react most rapidly at standard conditions.
A rapid chemical reaction is one where reactants react fast with each other to give the products at the standard temperature and pressure conditions.
In the given choices Iodine is highly reactive as it belongs to the halogen group and also atomic hydrogen is very reactive in nature, when both combine it gives hydrogen iodide which is much stable in nature than the reactants.
when one mole of hydrogen reacts with one mole of iodine it produces 2 moles of hydrogen iodide.
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