MATHEMATICS MIDDLE SCHOOL

length of a room is 3 times its breadth and height is 4.6 m.if the total cost of carpeting the floor of a room at the rate of Rs. 60 per square meter is Rs. 4500,Find the total cost of papering the 4 walls at the rate of Rs. 6.

Answers

Answer 1

Answer:

The total cost of papering the 4 walls is Rs. 1104

Step-by-step explanation:

The given is:

The length of a room is 3 times its breadth
Its height is 4.6 m
The total cost of carpeting the floor of a room at the rate of Rs. 60 per square meter is Rs. 4500

We need to find the total cost of papering the 4 walls at the rate of Rs. 6

Assume that the breadth of the room is x m

∵ The length of the room is 3 times its breadth

∵ The breadth of the room is x m

∴ The length of the room is 3 x m

∵ The floor of the room is shaped a rectangle

- Area of the rectangle = length × breadth

∴ The area of the floor = (3 x) × (x) = 3 x²

∵ The rate of the carpeting is Rs. 60 per square meter

- Multiply the area of the floor by 60 to find the total cost of carpeting

∴ The total cost of carpeting = 3 x²(60) = 180 x²

∵ The total cost of carpeting the floor is Rs. 4500

- Equate the two sides of total cost to find x

∴ 180 x² = 4500

- Divide both sides by 180

∴ x² = 25

- Take √ for both sides

∴ x = 5

∴ The breadth of the room = 5 m

∵ The length of the room is 3 x

∴ The length of the room = 3(5) = 15 m

The four walls of the room has dimensions length × height , breadth × height , length × height , breadth × height ⇒ (each two opposite walls have same dimensions)

∵ The length = 15 m , breadth = 5 m , height = 4.6 m

∴ The area of the four walls = 2(15 × 4.6) + 2(5 × 4.6)

∴ The area of the four walls = 138 + 46

∴ The area of the four walls = 184 m²

∵ The rate per meter square of papering is Rs. 6

- Multiply the area of the four walls by 6 to find the total cost

of papering

∴ The total cost of papering = 184 × 6

∴ The total cost of papering = Rs. 1104

The total cost of papering the 4 walls is Rs. 1104

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Nina's garden is 4 1/5 meters long and 3/10 meter wide. what is the area of nina's garden

Answers

Area of rectangular garden = 21/5 $*$ 3/10 = 63/50 =1 $* \n$ 13/50 $m^(2)$ = 1.26 $m^(2)$

Consider Nina' s Garden is rectangular in shape

Length of the garden = 4 $*$ 1/5 = 21/5

Width of the garden = 3/10

Area of the rectangle is given by

Area = Length $*$ Width

So the area of the garden is given by

Area= 21/5 $*$ 3/10 = 63/50 =1 $* \n$ 13/50 $m^(2)$ = 1.26 $m^(2)$

For more information please refer to the link

brainly.com/question/24408520

Area= length * width

length = 4 1/5= 21/5 . Multiply the whole number with the denominator. 4*5= 20 . Add 20 with the numerator. 20+1=22

width= 3/10

21/5* 3/10 ( Multiply the denominators together). ( Multiply the numerators together).

21*3 / 5*10

= 63/50 meters^2 or in mixed number:1 13/50 meters^2

Answer : 63/50 meters^2 or in mixed number:1 13/50 meters^2

Jason baked 7 pans of brownies. He gave 1/4 of the brownies to his two sisters. How many pans of brownies did he give to his sister's?

Answers

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hope this helps

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Answers

No it not true 8÷5=0.625

Then you know that
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Answers

The first line as you know is the lowest value
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Answer:

A hope this helps!

Step-by-step explanation:

The box range is 22 to 29

The dividing line of the box is at 24 is the median

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The range of the whiskers is 14 to 26

The box range is 18 to 21

The dividing line of the box is at 19 is the median

Therefore, the range of the box plot for cars is the difference of the values at the ends of the whiskers, that is 33 - 21 = 8

The range for minivan = 26 - 12 = 14

Therefore, Josef's error is that, Josef confused the range and the interquartile range.

Here are the vertices of rectangle FROG: (-2,5),(-2,1),(6,5),(6,1). Find the perimeter of this rectangle. If you get stuck, try plotting the points on a coordinate plane. For the rectangle FROG, the perimeter is . Find the area of the rectangle FROG. For the rectangle FROG, the area is

Answers

The area and the perimeter of the rectangle FROG is evaluated as:

Area(FROG) = $32 \: \rm unit^2$
Perimeter(FROG) = $64\: \rm units$

How to find the area and the perimeter of a rectangle?

For a rectangle with length and width L and W units, we get:

Area of the rectangle = $L * W \: \rm unit^2$
Perimeter of the rectangle = $2(L + W) \: \rm unit^2$

What is the distance between two points ( p,q) and (x,y)?

The shortest distance(straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

$D = √((x-p)^2 + (y-q)^2) \: \rm units.$

The coordinates of the points of the rectangle FROG are given as:

F(-2,5), R(-2,1), G(6,5), and O(6,1) (from its plot, as given below)

FR and RO are length and width pair(we can call any one of them as length and other as width) of the considered rectangle as they are adjacent to each other.

We denote length of a line segment AB by |AB|

Thus, we get:

Length of the rectangle = |FR| = $√((-2-(-2))^2 + (1 - 5)^2 ) = 4$ units
Width of the rectangle = |RO| = $√((6-(-2))^2 + (1 - 1)^2 ) = √(64) = 8 \: \rm units$