Ten slips of paper labeled from 1 to 5 are placed in a hat. The first slip of paper is not replaced before selecting the second slip of paper.What is the probability of selecting a number less than 3 then a number greater than 4?

3/50

1/15

3/100

1/10

Answers

Answer 1

Answer:

Answer:

The probability of given event = $(1)/(15)$

Step-by-step explanation:

Ten slips of paper labeled from 1 to 10 are placed in a hat. The first slip of paper is not replaced before selecting the second slip of paper.

We have to find the probability of selecting a number less than 3 and then a number greater than 4.

Probability of an event = $(number of favourable events)/(total number of events)$

The probability of selecting number less than 3 = $(2)/(10)$ = $(1)/(5)$

The probability of selecting number greater than 4 = $(3)/(9)$ = $(1)/(3)$

Total probability = $(1)/(5)* (1)/(3)$ = $(1)/(15)$

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Use the elimination method to solve the system of equations. Choose the correct ordered pair. 3x - y = -1
3x + 3y = 27

Answers

6x-3y=27 --> 3*(2x-y = 9)
3x-y=13 Doesn't factor

How to see if matrix is one to one calculator

Answers

Answer:

look at the pivots (the leading 1's of the rows)

Step-by-step explanation:

Then, look at the pivots (the leading 1's of the rows). If we have a pivot in every column, then the nullspace of the matrix (and hence the kernel of T) is zero-dimensional. So, T is one-to-one if and only if the REF has pivot in every column.

Final answer:

To check if a matrix is one-to-one using a calculator, you need to enter the matrix values into the calculator, find the reduced row echelon form (RREF) of the matrix, and if the RREF is the identity matrix, the matrix is one-to-one.

Explanation:

In Linear Algebra, a matrix is considered one-to-one if each input vector from a given set of vectors gives a unique output vector. In other words, no two different input vectors can yield the same output vector. To check whether a matrix is one-to-one using a calculator, you’re essentially checking if the transformation represented by the matrix is injective. Here are the steps:

Enter the values of your matrix into the calculator.
Find the reduced row echelon form (RREF) of the matrix. You can do this by row reducing the matrix.
If the RREF of the matrix is the identity matrix, then the matrix is one-to-one. This means that every column of the matrix will have a leading 1, with zeros everywhere else in that column and row.

Note: These steps can often be performed on a calculator that has capabilities for matrix operations, like a TI-83 or TI-84.

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A principal of $4900 is invested at 8.5% interest, compounded annually. how much will the investment be worth after 7 years? Round to the nearest dollar

Answers

The investment will be worth $8,674 after 7 years.

The sum of 1/9 2/3 and 5/18 is what

Answers

So first we have to find a common denominator, in this case it is simple because 18 works. So now we have to make 1/9 into ?/18, to do this we multiply 1/9 by 2, so now we have 2/18 + 2/3 + 5/18. To make 2/3 into ?/18 we have to multiply by 6, so now we have 2/18 + 12/18 + 5/18. Now you add all the numerators (top numbers) together and we get 19/18, which is the same as 1 1/18

ANSWER: 19/18 or 1 1/18.

Feel free to ask any questions about my explanation if you need it(:

The sum of the fractions $(1)/(9),(2)/(3),\frac{5}{{18}}$ is $\boxed{\frac{{{\mathbf{19}}}}{{{\mathbf{18}}}}}$ .

Further explanation:

Given:

The given fractions are $(1)/(9),(2)/(3),\frac{5}{{18}}$ .

Step by step explanation:

Step 1:

First we make the denominator same of the given fraction.

The equivalent fraction of $(1)/(9)$ can be calculated as,

$\frac{{1 * 2}}{{9 * 2}} = \frac{2}{{18}}$

The equivalent fraction of $(2)/(3)$ can be calculated as,

$\frac{{2 * 3}}{{3 * 3}} = (6)/(9)$

The equivalent fraction of $\frac{5}{{18}}$ can be calculated as,

$\frac{{5 * 1}}{{18 * 1}} = \frac{5}{{18}}$

Step 2:

We know the sum of the given fractions and the sum of the equivalent fractions would be same.

Now find the sum of the equivalent fraction to find the sum of the given fractions $(1)/(9),(2)/(3),\frac{5}{{18}}$ as,

$\begin{aligned}\frac{2}{{18}} + \frac{{12}}{{18}} + \frac{5}{{18}} &= \frac{{2 + 12 + 5}}{{18}} \n&= \frac{{19}}{{18}} \n\end{aligned}$

Therefore, the sum of the fractions $(1)/(9),(2)/(3),\frac{5}{{18}}$ is $\frac{{19}}{{18}}$ .

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Answer details:

Grade: Middle school

Subject: Mathematics

Chapter: Fractions

Keywords: sum, equivalent, fraction, denominator, numerator, number, division, multiplication, addition, difference, product, natural number

A midwestern music competition awarded 35 ribbons. The number of blue ribbons awarded was 3 less than the number of white ribbons. the number of red ribbons was 2 more than the number of white ribbons. How many of each kind of ribbon was awarded....white?, blue?, red?

Answers

35 total ribbons

x = white ribbons
x-3 = blue ribbons
x+2 = red ribbons

35= x+x-3+x+2
35= 3x -1
36 =3x
12 = x
12 white ribbons
9 blue ribbons
14 red ribbons

12+14+9 = 35

White 12
Blue 9
Red 14
I did it without paper so I'm not sure but it works :D

Which shows one way to determine the factors of x3 + 5x2 – 6x – 30 by grouping?