MATHEMATICS HIGH SCHOOL

Indra baked and frosted a rectangular cake to sell at a bake sale for the Model UN club. The cake, including frosting, was 4 inches high, 16 inches wide, and 12 inches long. She centered the cake on a circular tray. The circular tray had a radius of 10 inches. What is the area, to the nearest square inch, of the tray that is not covered by the cake?A. 100
B. 114
C. 122
D. 314
E. 192

Answers

Answer 1

Answer:

Answer:

C. 122

Step-by-step explanation:

Given,

Dimension of the cake:

Length = 12 in Width = 16 in Height = 4 in

We have to find out the area of the tray that is not covered by the cake.

Indra centered the cake on a circular tray.

Radius of the tray = 10 in.

So area of the tray is equal to π times square of the radius.

Framing in equation form, we get;

Area of tray = $\pi* r^2=3.14*{10}^2=3.14* 100=314\ in^2$

Since the cake is placed in circular tray.

That means only base area of cake has covered the tray.

Base Area of cake = $length* width=12* 16=192\ in^2$

Area of the tray that is not covered by the cake is calculated by subtracting area of base of cake from area of circular tray.

We can frame it in equation form as;

Area of the tray that is not covered by the cake = Area of tray - Base Area of cake

Area of the tray that is not covered by the cake = $314-192=122\ in^2$

Hence The area of the tray that is not covered by the cake is 122 sq. in.

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Un técnico de reparaciones de electrodomésticos cobra 25 € por la visita, más 20 € por cada hora de trabajo. A) Escribe la expresión algebraica (fórmula) que nos da el dinero que le tenemos que pagar en total de acuerdo con el tiempo que esté trabajando

Answers

Answer:

x= 25+20y

Step-by-step explanation:

De acuerdo a la situación planteada, la expresión algebraica debe indicar que 25€ que es el valor por la visita más 20€ multiplicado por el número de horas trabajadas es igual al dinero total que se debe pagar. La expresión es:

x= 25+20y, donde

x= valor total a pagar

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At 7 A.M the temperature was 4 .At 9A.M it was a degrees warmer. What was the temperature at 9 A.M

Answers

It was 5 degrees at 9 am

Answer:

5 I’m guessing

Step-by-step explanation:

If it’s a degrees warmer and to the right of a number line is warm in weather then it would be 5.

Simplify the following expression (6x2 + 8x - 3) - (3x2 - 6)

Answers

Answer:

3x^2 +8x +3

Step-by-step explanation:

(6x^2 + 8x - 3) - (3x^2 - 6)

Distribute the minus sign

(6x^2 + 8x - 3) - 3x^2 + 6

Combine like terms

3x^2 +8x +3

Mike started a savings account by depositing $9. Each month he deposits more money than the month before. At the end of 41 months, he has saved $9,389.00. How much more does he deposit each month

Answers

We have to calculate how much more money does Mike deposit each month. This can be done using the formula for the arythmetic sequence; S n = n/2 * ( a1 + an ). Here: a 1 = 9, n = 41 and a n = a 1 + ( n-1 ) d = 9 + 40 d. So : 9,389 = 41/2 * ( 9 + 9 + 40 d ); 9,389 = 41 / 2 * ( 18 + 40 d ); 9,389 = 41 * ( 9 + 20 d ) ; 9,389 = 369 + 820 d; 820 d = 9,389 - 369; 820 d = 9,020; d = 9,020 : 820; d = 11. Answer: He deposits $11 more each month.

Answer:

$11.00 or 11

same thing :)

*plug all other answer choices inside formula as d to check your answer*

Step-by-step explanation:

we need to use the arithmetic sequence formula

$S_n=(n)/(2) [2a_1+(n-1)d]\n$

$a_1=9\nn=41\nd=11 \n\nS_4_1=(41)/(2)[ (2)(4)+(41-1)(11)] \n\nS_4_1=(41)/(2) [8+(40)(11)]\n\n\S_4_1=(41)/(2) (18+440)\n\nS_4_1=(41)/(2) (458)\n\nS_4_1=20.5 (458)\n\nS_4_1=9,389$

He deposit 11 each month is right because the sum of the series ( $S_n$ ) is 9,389 and he saved 9,389 at the end of the 41 months.

Need help please!!!!!!!

Answers

Answer:

First Option {-2 , 0 , 2}

Step-by-step explanation:

A critical point occurs when the derivative is 0 or undefined.

The function in the question is undefined at x = 2 and at x = -2 because if we put x = 2 or x = -2 the denominator becomes 0 hence anything divided by 0 is undefined, and the derivative equals 0 at x = 0 so the critical points are

{-2 , 0 , 2}

Use the quotient rule to find the derivative of the function then equal it to zero

$y=(x^2-1)/(x^2-4)\n\n(dy)/(dx)=((x^2-4)(2x)-(x^2-1)(2x))/((x^2-4)^2)\n\n0=((x^2-4)(2x)-(x^2-1)(2x))/((x^2-4)^2)\n\n0=2x^3-8x-2x^3+2x\n0=-6x\nx=0$

I believe it’s the last one
Mark brainliest if satisfied

Find the value of a−b/c−b if a=32, b=8, c=30. Write your answer as a simplified mixed number.Need soon thanks!

Answers

Answer: 1 1/11 or 12/11

Step-by-step explanation: a-b= 32-8 which equals 24. Then it would be c-b which is 30-8 which equals to 22. Then it would be 24/22. You can divide by two on both sides, which would be 12/11. Then as a mixed number, it would be 1 1/11.

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