How can researching travel time, routes and weather conditions benefit drivers who are planning a road trip?
Answers
Explanation:
They will be alerted of the traffic conditions. They can choose the route according to the weather condition. They will be aware if there is any road construction going on or accident happened. These awareness will save their time and avoid delays. their journey can be more comfortable and less trouble some.
Explanation:
Researching these options time, routes and weather conditions and even more gives the driver ample information about the journey, and places the driver in better position for decision making, with this information and data afore hand he can decides the best route to take should there be any gridlock, he even decides where or not to embark on the journey based on the prevailing weather conditions,
Regarding time of the journey he is well disposed for proper planning and scheduling.
Related Questions
if we're interested in knowing the rate at which light energy is received by a unit of area on a particular surface we're really trying to figure out the
What was one result of the second great awakening
Which sequence doesthe energy transformation in an automobile engine.
A 60 W light bulb at 120 V is left on in your house to prevent burglary, and the power charges 10 cents per kilowatt-hour, how much will it cost to leave the bulb on for 30 days?
b. the height of high tides varies with the phases of the moon.
c. spring tides and neap tides affect the phases of the moon.
d. the moon revolves around the Earth every 14 days.
Please select the best answer from the choices provided
Answers
Answer:
D
Explanation:
Because neap and spring tides happen twice a month during new moon and full moon .It occurs twice in a month which is 14 days
Answer:
i think it is d
Explanation:
Answers
At the beginning of a basketball game, a referee tosses the ball straight
up with a speed of 4.6 m/s. a player cannot touch the ball until after it reaches its maximum height and begins to fall down. what is the minimum time that a player must wait before touching the ball? s
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kinemaic equation
v=u-at
0=4.6-9.81xt
t=4.6/9.81 ... about half a second
Answers
1 / (5 per second) = 0.2 second .
The wavelength is irrelevant to the period. But since you
gave it to us, we can also calculate the speed of the wave.
Wave speed = (frequency) x (wavelength)
= (5 per second) x (1cm) = 5 cm per second
b. high frequency, short wavelength
c. low frequency, short wavelength
d. high frequency, long wavelength
Answers
Fun fact: gamma rays have the shortest wavelength and highest frequency in the EM Spectrum. Their high energy levels causes abnormalities in cell division (which is basically known as cancer). Xrays and UV does too so there are safety stuff that goes on with regards to those (like lead shielding for xray scans and sunscreen from UV rays).
Answer: B: High frequency, short wavelength
Explanation: Well, if its a higher frequency it carries more than a low frequency, and when its a short wavelength, it doesn't take up as much energy for it to move, so it makes it larger amounts of energy, hope this helps!
Answers
When the igneous rock is deep underground for many years, it will form into metamorphic rock under extreme pressure and temperature. It could also form into magma when it melts deep beneath the layers of earth or it could form sediments when subjected to weather erosion.
(b) 612W
(c) 64W
(d) 109W
(e) 403W
Answers
Answer:
The correct option is;
(c) 64W
Explanation:
Here we have the Coefficient Of Performance, COP given by
The heat change from 23° to 6°C for a mass of 10 kg/h which is equivalent to 10/(60×60) kg/s or 2.78 g/s we have
= m·c·ΔT = 2.78 × 4.18 × (23 - 6) = 197.39 J
Therefore, plugging in the value for in the COP equation we get;
which gives
Since we were working with mass flow rate then the power input is the same as the work done per second and the power input to the refrigerator = 63.674 J/s ≈ 64 W.
The power input to the refrigerator is approximately 64 W.
Answer:
Win = 64 W ... Option C
Explanation:
Given:-
- The water is cooled in the refrigerator with delta temperature, ΔT=(23 - 6 )
- The flow rate of the refrigerated water is flow ( m ) = 10 kg/h
- The COP of the refrigerator is = 3.1:
Find:-
the required power input to this refrigerator is
Solution:-
- The COP - The coefficient of performance of a refrigerator is a quantity that defines the efficiency of the system. The COP is given as:
COP = QL / Win
Where,
QL : The rate of heat loss
Win : The input power required
- The rate of heat loss can be determined from first law of thermodynamics.
Qin - Wout = flow (m)*c*ΔT
Where,
Qin = - QL ... Heat lost.
c : The heat capacity of water = 4,200 J / kg°C
- There is no work being done on the system so, Wout = 0
-QL = flow (m)*c*ΔT
-QL = ( 10 / 3600 )*4200*( 6 - 23 )
QL = 198.33 W
- The required power input ( Qin ) would be:
Win = QL / COP
Win = 198.33 / 3.1
= 63.97 W ≈ 64 W