Four more than twice a number x is 12. Write an equation that represents this situation. Determine the number x

Answers

Answer 1
Answer:

Answer:

2x+4=12

x=4

Step-by-step explanation:

Let's look at the way that this question is written in order to write the equation

"Four more than" this means that we need to add 4 to the next thing that is listed.

"Twice a number x" means 2x

Combining the last two gives us 2x+4

"Is 12" means =12

Combining everything gives us

2x+4=12

Now we can solve for x

2x+4=12\n\n2x=8\n\nx=4


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Victoria jogged a total distance of 4 1/3 miles during the months of June and July. If Victoria jogged only 1/6 of a mile everyday, which expression shows the number of days in which she went jogging?A) 4 1/3 x 6 = ?B) 4 1/3 / 6 =?C) 4 1/3 + 6 =?D) 4 1/3 - 6 =?
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5x+2+6x+9=10x+5 solve the equation.
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There are 2 parent chaperones for every 12 students at a field trip how many chaperones are needed for 120 students

Answers

20 chaperones are needed


The answer is 20.

120 / 12 = 10

This means that there are 10 sets of 12 students. Now multiply 10 by 2:

10 * 2 = 20

Good luck!

The sum of three consecutive numbers is 57. What is the largest of these numbers?18
19
20
21

Answers

x+x+1+x+2=57
3x+3=57
3x=54
x= 54/3
x= 18


x+1= 19
x+2= 20

Therefore 20 is the largest

Answer:

20

Step-by-step explanation:

just took the test

Plzzzzz helpppppp
Solve x + x + 2 + 2x = -2.
1
-1
0
-2

Answers

Answer:

The answer is b: -1

Step-by-step explanation:

x + x + 2 + 2x = -2

Collect like terms

x + x + 2x = -2 - 2

4x = -4

Divide both sides by 4

x = -4/4

x = -1

Answer:

as follows

Step-by-step explanation:

Find the area of this semi circle ...

Answers

Here's the equation for the area of a semicircle: A = (πr²)/2

Based on this, let's solve for this area in terms of π (pi):

A = π(10²)/2 = 100π/2 = 50π

The area of the semicircle, I believe, is 50π. Hope this helps, let me know if I messed up!

Answer: A=157


Step-by-step explanation: The area of a semi-circle can be found using the radius in the formula A=1/2\pir^2. We substitute the radius in the equation  A=1/2*3.14*10^2

First we do the exponents following pemdas.

A=1/2*3.14*10^2

A=1/2*3.14*100

Then we multiply.

A=1/2*3.14*100

A=1.57*100

A=157

The final answer is 157.

Hope this helps!

Use parentheses to make each number sentence true 1+2×3+4=21​

Answers

(1+2)(3+4)
1+2=3
3+4=7
7•3=21
There is an invisible multiplication sign between the two parentheses :).

Find the coordinates of the stationary points on each curve(in each equation).1.y=x^2+2x

2.y=4x^3+3x^2+2

3.y=2x+3+8/x

4.y=x^3-9x^2-21x+11

5.y=9x^2/3-2x+5

Please provide full working out, thanks.

Answers

1)
y=x²+2x

we have to calculate the first derived

y´=2x+2

we equal to "0" the first derived and find out the value of "X"
2x+2=0
x=-2/2=-1

we have to calculate de second derived
y´´=2>0  ⇒we have a minimun at x=-1

we calculate y
y=(-1)²+2(-1)=1-2=-1

Answer: we have a minimum at (-1,-1)

2)
y=4x³+3x²+2
we have to calculate the first derived

y´=12x²+6x

we equalize to "0" the first derived and find out the value of "X"
12x²+6x=0
6x(2x+1)=0

6x=0      ⇒x=0
2x+1=0  ⇒x=-1/2


we have to calculate de second derived
y´´=24x+6

y``(0)=24(0)+6=6  >0    ⇒we have a minimun at x=0
y``(-1/2)=24(-1/2)+6=-12+6=-6  ⇒we have a maximum at x=-1/2

we calculate y
if x=0, y=2
if x=-1/2;    y=4(-1/2)³+3(-1/2)²+2=9/4.

we have to equalize the second derived to "0" and find out the value of "x"
24x+6=0
x=-6/24=-1/4; in x=-1/4 we have an inflection point.

y=4(-1/4)³+3(-1/4)²+2=31/16

Answer: we have a minimum at (0,2), a maximum at (-1/2, 9/4) and a inflection point at (-1/4,  31/16).

3.
y=2x+3+8/x
y=(2x²+3x+8)/ x

we have to calculate the first derived

y´= [(4x+3)x-(2x²+3x+8)] / x²=(4x²+3x-2x²-3x-8) / x²=(2x²-8)/x²

we equal to "0" the first derived and find out the value of "X"
(2x²-8) / x²=0
2x²-8=0
x=⁺₋2

we have to calculate de second derived
y´´=[(4x)x²-2x(2x²-8)] / x⁴=(4x³-4x³+16x)/x⁴)=16/x³
y``(-2)=16/(-2)³=-2>0   ⇒ at x=-2 exist a maximum
y´´(2)=16/(2)³=2<0    ⇒ at x=2 exist a minimum
 

we calculate y
y(-2)=-4+3-4=-5
y(2)=4+3+4=11

Answer: we have a maximum at (-2,-5 ) and a minimun at (2,11)

4)
y=x³-9x²-21x+11

we have to calculate the first derived

y´=3x²-18x-21

we equal to "0" the first derived and find out the value of "X"
3x²-18x-21=0
x²-6x-7=0
x=[6⁺₋√(36+28)]/2=(6⁺₋8)/2
x₁=-1
x₂=7

we have to calculate de second derived
y´´=6x-18
y``(-1)=-6-18=-24<0  ⇒at x=-1 exist a maximum
y´´(7)=42-18=24>0  ⇒ at x=7 exist a minimum.

we calculate y
y(-1)=-1-9+21+11=22
y(7)=343-441-147+11=-234

We equalize the second derive to 0, and find out the value of "x"
6x-18=0
x=3 in x=3 exist an inflection point

y=27-81-63+11=-106
Answer: we have a minimum at (7,-234), a maximum at (-1,22) and an inflection point at (3,-106).

5)
y=9x²/³-2x+5

we have to calculate the first derived

y´=6x⁻¹/³-2

we equal to "0" the first derived and find out the value of "X"
6x⁻¹/³-2=0
x⁻¹/³=1/3
x¹/³=3
x=27


we have to calculate de second derived
y´´=-2x^(-4/3)
y´´(27)=-0.024<0  ⇒ at x=27 exist a maximum
we calculate y
y=32

Answer: we have a maximum at (27,32)