A recipe uses 1 1/4 cups of oil to make 20 servings. If the same amount of oil is used for each serving, how many servings can be Made with one gallon of oil ?

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

1 1/4 (or 1.25) cups to 20 servings = 1 gallon (16 cups) to x servings

 1.25        16

--------- = --------  cross multiply

 20           x

(1.25)(x) = (20)(16)

1.25x = 320

x = 320/1.25

x = 256 servings <===


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Which values from the specified set make up the solution set of the inequality?5w-10>20; {5,6,7,8}

select each correct answer

A.) 5
B.) 6
C.) 7
D.) 8

PLEASE HELP

Answers

So, the solution of the given inequality is all values greater than 6

So, Option C and D are correct.

Step-by-step explanation:

We need to find which values from the specified set make up the solution set of the inequality: 5w-10>20; \{5,6,7,8\}

Solving the inequality first:

5w-10>20

Adding 10 on both sides

5w-10+10>20+10

5w>30

Divide both sides by 5

w>6

So, the solution of the given inequality is all values greater than 6

So, in the given solution set 7 and 8 are values greater than 6

So, Option C and D are correct.

Keywords: Solving inequalities

Learn more about Solving inequalities at:

#learnwithBrainly

The GCF two numers is a composite number. Always, sometimes or never true?

Answers

Answer:

Sometimes

Step-by-step explanation:

A Composite number is the number which is not prime except 1. Hence, it has factors other than 1 and itself.

GCF is a greatest common factor i.e. the greatest factor that divides two numbers.

The GCF of two numbers can be composite number.

Example:

GCF of 8 and 24 = 8 which is a composite number.

GCF of 6 and 21 = 3 which is not a composite number.

Thus, GCF two numbers is sometimes a composite number.

The GCF of two numbers is sometimes a composite number. 

What is 1600 divided by 70?

Answers

1600 ÷ 70 = 160 ÷7 = 22.85 :))
i hope this is helpful 
have a nice day 

Let A={0,1,2,3,4,6} and B={2,4,6,8} find 
a.)AnB             b.)AUB

Answers

A=\{0,1,2,3,4,6\}\ and\ B=\{2,4,6,8\} \n\n a)\ \ \ A\ \cap\ B =\{2,4,6\} \n\nb)\ \ \ A\ \cup\ B=\{0,1,2,3,4,6,8\}
A\cap B=\{2,4,6\}\n A\cup B=\{0,1,2,3,4,6,8\}

What is the reciprocal of 15?

Answers

Reciprocal is just so to say flipping the number so think of this as 15/1 and just flip it, your answer is 1/15

Simplify -sin^2x-cos^2x-tan^2x+cot^2x+sec^2x-csc^2x+2

Answers

 

\displaystyle\n\text{simplify: } -\sin^2x-\cos^2x-\tan^2x+\cot^2x+\sec^2x-\csc^2x+2\n\n\text{We use the formulas:}\n1)~~\sin^2x+\cos^2x=1\n\n2)~~\tan x=(\sin x)/(\cos x) ~~~~~~~3)~~\cot x= (\cos x)/(\sin x)\n \n4)~~\sec x=(1)/(\cos x) ~~~~~~~~5)~~\csc x=(1)/(\sin x)\n \n\text{Answer:}\n\n-\sin^2x-\cos^2x-\tan^2x+\cot^2x+\sec^2x-\csc^2x+2=\n\n=-(\sin^2x+\cos^2x)- (\sin^2x)/(\cos^2x)+(\cos^2x)/(\sin^2x)+\sec^2x-\csc^2x+2=


\displaystyle\n=-1- (\sin^2x)/(\cos^2x)+(\cos^2x)/(\sin^2x)+ (1)/(\cos^2x)- (1)/(\sin^2x) +2=\n\n=-(\sin^2x )/(\cos^2x)+(\cos^2x)/(\sin^2x)+ (1)/(\cos^2x)- (1)/(\sin^2x) +2-1=\n\n=(-\sin^4x+\cos^4x)/(sin^2x\cos^2x)+(\sin^2x-\cos^2x)/(\sin^2x\cos^2x)+1=\n\n=(\cos^4x-\sin^4x)/(\sin^2x\cos^2x)-(\cos^2x-\sin^2x)/(\sin^2x\cos^2x)+1=\n\n=((\cos^2x+\sin^2x)(\cos^2x-\sin^2x))/(\sin^2x\cos^2x)-(\cos^2x-\sin^2x)/(\sin^2x\cos^2x)+1=


\displaystyle\n=((1)\cdot(\cos^2x-\sin^2x))/(\sin^2x\cos^2x)-(\cos^2x-\sin^2x)/(\sin^2x\cos^2x)+1=\n\n=\underbrace{(\cos^2x-\sin^2x)/(\sin^2x\cos^2x)-(\cos^2x-\sin^2x)/(\sin^2x\cos^2x)}_(=~0)\,+\,1=0+1=\boxed{\boxed{\bf1}}



Answer: actually it is very complicated to explain but the answer is 1