Answer:
Step-by-step explanation:
I think what you are saying is represented by the diagram below.
The ball starts at A, rebounds from the far wall at a 45° angle and into the corner pocket at C.
You want the find the distance from A to C.
We can use the Law of Cosines to answer this question
Answer:
about 86 cm
Step-by-step explanation:
My understanding of the geometry is shown in the attached figure.
Since the angle of incidence is equal to the angle of reflection, the angle APP₂ will be 22.5°, and the vertical distance from the pocket P to the ball position B is ...
(PA +AB')sin(22.5°) = 220sin(22.5°) ≈ 84.19 . . . . cm
The horizontal distance PB is
(PA -AB)cos(22.5°) = 20cos(22.5°) ≈ 18.48 . . . . . cm
The distance PB is given by the distance formula ...
PB = √(84.19² +18.48²) ≈ 86.19 . . . . cm
The ball was initially about 86 cm from the corner pocket.
-112/7+9
Answer:
89.99
Step-by-step explanation:
The correct answer is:
D. y=75x+30
2)y=9/5x-5
Find the slope of a line perpendicular to each given line
1)y=-1/2x-2
2)y=-x-1