The rate of change of angulardisplacement is defined as angular velocity. The angular velocity will be 22.41rad/s.
The rate of change of angular displacement is defined as angular velocity. Its unit is rad/sec.
ω = θ t
Where,
θ is the angle of rotation,
tis the time
ω is the angular velocity
The given data in the problem is;
u is the initialvelocity=0
α is the angularacceleration = 4.0 rad/s²
t is the time period=
n is the number of revolution = 10 rev
From Newton's second equation of motion in terms of angular velocity;
Hence the angular velocity will be 22.41 rad/s.
To learn more about angularvelocity refer to the link
Answer:
= 22.41rad/s
Explanation:
First, we know that:
a = 4 rad/s^2
S = 10 rev = 62.83 rad
Now we know that:
where is the final angular velocity, the initial angular velocity, a is the angular aceleration and S the radians.
Replacing, we get:
Finally, solving for :
= 22.41rad/s
Answer:
E=930.84 N/C
Explanation:
Given that
I = 1150 W/m²
μ = 4Π x 10⁻⁷
C = 2.999 x 10⁸ m/s
E= C B
C=speed of light
B=Magnetic filed ,E=Electric filed
Power P = I A
A=Area=4πr² ,I=Intensity
E=930.84 N/C
Therefore answer is 930.84 N/C
To find the magnitude Em of the electromagnetic waves at the top of the earth's atmosphere, we use the intensity of electromagnetic wave and solving the equation Em = sqrt(2Icμo), we can find the magnitude of Em in units of N/C.
To find the magnitude Em of the electromagnetic waves at the top of the Earth's atmosphere, we use the fact that the power received per unit area is the intensity I of the electromagnetic wave. According to the given information, this intensity is 1150 W/m2. The relationship between the intensity and electromagnetic fields is given by the equation I = 0.5 * E²/c * μo. Solving for Em, we get Em = sqrt(2Icμo), where μo = 4π × 10-7 T N/A² is the permeability of free space and c = 2.99792 × 10⁸ m/s is the speed of light.
Subbing in the given values, we can compute Em as:
Em = sqrt[2 * 1150 W/m² * 2.99792 × 10⁸ m/s * 4π × 10-7 T N/A²]
This computation will give the strength of the electric field at the top of the earth’s atmosphere in units of N/C.
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Answer:
The acceleration of the ball is 200 m/s^2
Answer:
A
Explanation:
200 m/s squared
Answer:
a) 10.29° upstream
b) t=338.7s
Explanation:
If the river is 1km wide and the destination point is 0.5km away downstream, then the angle and distance the the boat has to travel is:
The realitve velocity of the boat respect to the water is:
where β is the angle it has to be pointed at.
From the relative mvement equations:
where
From this equation we get one equation per the x-axis and another for the y-axis. If we square each of them and add them together, we will get 2 equations:
Solving for V:
V = 3.3m/s and V=-1.514m/s Replacing this value into one of our previous x or y-axis equations:
The amount of time:
Answer:
A light-year is the distance light travels in one year.
Answer:
Explanation:
a unit of astronomical distance equivalent to the distance that light travels in one year, which is 9.4607 × 1012 km (nearly 6 million million miles).
Answer and Explanation:
Doppler effect : According to Doppler effect whenever there is a relative motion between the source and observer then there is an increase or decrease in frequency of sound light or waves.
REASON OF DOPPLER EFFECT : Doppler effect is mainly due to the sudden change in pitch of the sound
EXAMPLE OF DOPPLER EFFECT : The best example of Doppler effect is when an ambulance passes and when it comes closer then the frequency of the siren increases and when it goes away its frequency decreases.