Answer:
sample output
Enter f0 = 440
440.0,466.1637615180899, 493.8833012561241,
523.2511306011974, 554.3652619537443
Explanation:
import math // math library
def RaiseToPower(): // RaiseToPower method
r = math.pow(2,1/12) //r = 2^(1/12)
f0 = float(input('Enter f0 : ')) //input from user
//a key has a frequency,sy f0
print(f0,end=' ') //Display statement
for n in range(1,5): //Iterate the loop up to the next 4 higher key Hz
n = f0 * math.pow(r,n) //calculate the fn value
print(fn,end=' ') //Display statement
RaiseToPower() //Call RaiseToPower method
Answer:try redoing everything step by step and see if that solves it
Explanation:
Answer:
Following are the code to the given question:
user_num = int(input())#defining a variable user_num that takes input from user-end
x = int(input())#defining a variable x that takes input from user-end
for j in range(3):#defining for loop that divides the value three times
user_num = user_num // x#dividing the value and store integer part
print(user_num)#print value
Output:
2000
2
1000
500
250
Explanation:
In the above-given program code two-variable "user_num and x" is declared that inputs the value from the user-end and define a for loop that uses the "j" variable with the range method.
In the loop, it divides the "user_num" value with the "x" value and holds the integer part in the "user_num" variable, and prints its value.
Answer:
Return are predicted in the modern microprocessor as, branch predictor is the modern method for the processor for the prediction. The basic function of the branch predictor is improving in the pipeline instruction. It is basically the important part for implement the execution and the pipe lining. And the return predicted uses the call by reference technique for the data in instruction.
Answer:
The program to the given question as follows:
Program:
import java.util.*; //import package for user input.
public class Main //defining class Main
{
public static void main(String[] as) //defining main method
{
final double over_time_factor = 1.5; //define final variable
double number_Of_hours,wages,total_Wages=0; //defining variables
System.out.println("Enter hours and wages rate:"); //print message
Scanner obc = new Scanner(System.in); //creating Scanner class object for user input
number_Of_hours = obc.nextDouble(); //taking input
wages = obc.nextDouble(); //taking input
if(number_Of_hours>40) //check condition if number_Of_hours greter then 40
{
total_Wages=40*wages+(number_Of_hours-40)*wages*over_time_factor; //calculate value
}
else //else part
{
total_Wages = number_Of_hours*wages; //calculate total_Wages
}
System.out.println("Total Wages: $"+total_Wages); //print value
}
}
Output:
Enter hours and wages rate:
12
3
Total Wages: $36.0
Explanation:
In the above java program, the package is first imported into the user input and then the class is defined and inside this, the main method is defined, that defines a double type final variable "over_time_factor" is defined that holds a value "1.5", Then double type variable is defined that are " number_Of_hours, wages, and total_Wages", in which first two variables are used for taking input from the user and the third variable is used to calculate their values. After taken input from the user, the conditional statement is used that can be defined as follows:
A potential cause of this issue with FTP is that the server is not able to resolve the client IP address.
FTP is an acronym for file transfer protocol and it can be defined as a type of server that is designed and developed to store and provide files for download and sharing between two or more users on a computer system.
In this scenario, the user is most likely experiencing issues when trying to transfer files through the file transfer protocol (FTP) because the server is not able to resolve the client IP address, which is the address of the recipient of the file.
Read more on FTP here: brainly.com/question/20602197
Answer:
The program written in Python is as follows:
See Explanation section for line by line explanation
for n in range(100,1000):
isum = 0
for d in range(1,n):
if n%d == 0:
isum += d
if isum == n * 2:
print(n)
Explanation:
The program only considers 3 digit numbers. hence the range of n is from 100 to 999
for n in range(100,1000):
This line initializes sum to 0
isum = 0
This line is an iteration that stands as the divisor
for d in range(1,n):
This line checks if a number, d can evenly divide n
if n%d == 0:
If yes, the sum is updated
isum += d
This line checks if the current number n is a double-perfect number
if isum == n * 2:
If yes, n is printed
print(n)
When the program is run, the displayed output is 120 and 672