Two right triangles are graphed on a coordinate plane. One triangle has a vertical side of 3 and a horizontal side of 7. The other triangle has a vertical side of 9 and a horizontal side of 21. Could the hypotenuses of these two triangles lie along the same line? (4 points) Yes, because they are both right triangles Yes, because they are similar triangles No, because they are not similar triangles No, because one is larger than the other Description
Answers
Answer: Yes, because they are similar triangles
Step-by-step explanation:
Let ABC be the right triangle with vertical side of 3 and a horizontal side of 7.
And, right angle at B,
Then, AB = 3, BC = 7 ⇒ AC = √58
Again let, DEF be the right triangle with vertical side of 9 and a horizontal side of 21.
And, right angle at E,
Then, DE = 9, EF = 21 ⇒ DF = 3√58
Thus, in triangles ABC and DEF,
Therefore,
By the property of similar triangles,
Since, in both triangles horizontal sides BC and EF are on X-axis,
Therefore,
The second one is correct
Answer:
Yes
explanation: they are similar triangles
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$350 at 3% for 10 years
3 1/6 as a improper fraction
What two numbers add to +5 and have a product of -3?
Answers
Answer:
No, it is not a valid inference because his classmates do not make up a random sample of the students in the school
Step-by-step explanation:
NO
NA
2 4 6 8 10 12 14 16 18 20
Which ordered pair could represent the coordinates of point K? (2016)
A. (6,0)
B. (2,3)
C. (1.5, 0)
D. (7.5, 5)
Answers
The coordinates of point K in a proportional relationship, we determine the constant of proportionality and multiply is by the x-value to find the y-value. Option B, (2,3), is the correct coordinate pair.
To find the coordinates of point K, we need to determine the constant of proportionality between the x-values and the y-values.
The constant of proportionality is found by dividing the y-value by the x-value at any point on the line. Here, we can choose point N at (18,12).
So, the constant of proportionality is 12/18 = 2/3. To find the y-value of point K, we can multiply the x-value of K by the constant of proportionality: 2/3 * x = y.
Let's check the options. For option A, (6,0), y = 2/3 * 6 = 4.
However, the y-value of point N is 12, so this option is incorrect. Continuing with the same process for options B, C, and D, we find that the only option that satisfies the proportional relationship is option B, (2,3).
Learn more about Proportional Relationship here:
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Answer:
D or (7.5, 5)
Step by step explanation:
18 = x
12 = y
(18, 12)
18/7.5
= 2.4
12/5
= 2.4
2.4 = 2.4
The answer is D since its equivalent to (18,12)
Answers
Answer:
Missing Coefficient is -8
Step-by-step explanation:
We are given, _y² - [ -5y - y( -7y -9) ] - [ -y(15y + 4) ] = 0
We have to find missing value.
let missing value be a
ay² - [ -5y - y( -7y - 9) ] - [ -y(15y + 4) ] = 0
ay² - [ -5y + 7y² + 9y ] - [ -15y² - 4y ] = 0
ay² - [ 7y² + 4y ] + 15y² + 4y = 0
ay² - 7y² - 4y + 15y² + 4y = 0
ay² - 7y² + 15y² + 4y - 4y = 0
( a - 7 + 15 )y² = 0
RHS can be written as
( a - 7 + 15 )y² = 0.y²
Now comparing coefficient of both sides we get,
a - 7 + 15 = 0
a + 8 = 0
a = -8
Therefore, Missing Coefficient is -8
Hope this helps! (:
Answers
Step-by-step explanation: To simplify the expression 25/30 + 10/30, we first need to find a common denominator. The least common multiple of 30 and 30 is 30 itself, so we can multiply all the fractions by 30. This gives us:
(25/30)(30/30) + (10/30)(30/30) = 75/90 + 10/90
Next, we add the fractions:
75/90 + 10/90 = 85/90
Therefore, 25/30 + 10/30 = 85/90.
Answer:
Step-by-step explanation:
25/30+10/30
Reduce the fraction
30
25
to lowest terms by extracting and canceling out 5.
6
5
+
30
10
Reduce the fraction
30
10
to lowest terms by extracting and canceling out 10.
6
5
+
3
1
Least common multiple of 6 and 3 is 6. Convert
6
5
and
3
1
to fractions with denominator 6.
6
5
+
6
2
Since
6
5
and
6
2
have the same denominator, add them by adding their numerators.
6
5+2
Add 5 and 2 to get 7.
6
7
Answers
Answers
Answer:
Multiples and Submultiples of Volts.
Multiples and submultiples are prefixes and sufixes which are used to express a higher or lower number of a magnitude.
From least to greatest.
Multiples are: deka, hecto, kilo, mega, giga, tera, peta, exa, zetta, yotta.
Submultiples are: deci, centi, mili, micro, nano, pico, femto, atto, zepto, yokto.
Multiples of volts are:
dekavolts:
hectovolts:
kilovolts:
megavolts:
gigavolts:
teravolts:
petavolts:
exavolts:
zettavolts:
yottavolts:
Submultiples of volts are:
decivolts:
centivolts:
milivolts:
microvolts:
nanovolts:
picovolts:
femtovolts:
attovolts:
zeptovolts:
yoktovolts: .
MV =MegaVolt (1 MV = 1000000 V)
KV = KiloVolt (1 KV = 1000 V)
V = Volt (1V = 1 V) :))
mV = miliVolt (1V = 1000 mV)
μV = microVolt (1V) = 1000000 μV