Answer:
We will use the following approach to solve the problem:
Explanation:
1. We will identify the largest pancake in the given stack of pancakes, then insert the spatula below that pancake and flip the entire stack consisting of that largest identified pancake and all other pancakes on the top of it. Now the largest pancake will be on the top of the stack. Now insert the spatula at the bottom of stack and flip. In this way the largest pancake will become the bottommost pancake.
Now identify the next second largest pancake and repeat above process, keep on relating that until all are sorted.
This requires almost 2n-3 flips in worst case. ( For n pancakes). So the time complexity is O(n)
2n because one flip is required to bring pancake at top, then in 2nd flip it goes to bottom.
-3 because, the stack becomes sorted once the 2nd last pancake comes to the top. So next three steps are never required.
B) we want to find stack of n pancakes, that take omega (n) steps.
For that to happen, in worst case ( 2n-3 )>= cn , taking c=1
2n-3 >= n , => n >=3
So for n greater than or equal to 3 the condition holds.
B) ring
C) bus
D) all of the above
Answer:
ring
Explanation:
Answer:
21 times
Explanation:
Following are the description of output:
Answer:
Explanation:
Top-down design allows a programmer to take a complex idea, break it down into high-level tasks which can be further broken down into more detailed sub-tasks (Evans, Martin, & Poatsy, 2018). The larger a program gets, the more important it is to have a clear design. It is easier to fix an error during the design phase than the coding phase. If the design is flawed, a programmer can end up having to delete or rewrite large portions of code. Reworking large portions of a design is preferable to rewriting large portions of code. Even small programs can become overwhelming with a number of tasks to perform. Hierarchy Chart (hierarchical diagram) shows the breakdown of a system to its lowest manageable parts. It is a top-down modular design tool, constructed of rectangles (that represents the different modules in a system) and lines that connect them. The lines explain the connection and/or ownership between the different modules among the system just like in an organizational chart. main purpose is to describe the structure and hierarchy of an entity. This entity could be a strategy, event, software program, and so on. The hierarchy chart is suitable in any situation that aims to present the organized structure of a material or an abstract entity.
Answer:
I highly recommened you use ggl charts.
Explanation:
It's free. ALL YOU NEED IS AN GGL ACCOUNT. You can also choose many types of graph you want.
Answer:
See explaination
Explanation:
Taking a look at the The Logic function, which states that an output action will become TRUE if either one “OR” more events are TRUE, but the order at which they occur is unimportant as it does not affect the final result. For example, A + B = B + A.
Alternatively the Most significant bit which is also known as the alt bit, high bit, meta bit, or senior bit, the most significant bit is the highest bit in binary.
See the attached file for those detailed logic functions designed with relation to the questions asked.
Answer:
See explaination
Explanation:
class Episode{
//Private variables
private String title;
private int seasonNumber;
private int episodeNumber;
//Argumented constructor
public Episode(String title, int seasonNumber, int episodeNumber) {
this.title = title;
this.seasonNumber = seasonNumber;
this.episodeNumber = episodeNumber;
}
//Getter and setters
public String getTitle() {
return title;
}
public void setTitle(String title) {
this.title = title;
}
public int getSeasonNumber() {
return seasonNumber;
}
public void setSeasonNumber(int seasonNumber) {
this.seasonNumber = seasonNumber;
}
public int getEpisodeNumber() {
return episodeNumber;
}
public void setEpisodeNumber(int episodeNumber) {
this.episodeNumber = episodeNumber;
}
public boolean comesBefore(Episode e){
//Check if titles' match
if(this.title.equals(e.getTitle())){
//Compare season numbers
if(this.seasonNumber<e.seasonNumber){
return true;
}
//Check if season numbers match
else if(this.seasonNumber==e.getSeasonNumber()){
return this.episodeNumber<e.getEpisodeNumber();
}
}
return false;
}
atOverride // replace the at with at symbol
public String toString() {
return title+", season "+seasonNumber+", episode "+episodeNumber;
}
}
class Main{
public static void main(String[] args) {
Episode e = new Episode("Friends",1,1);
System.out.println(e);
Episode e2 = new Episode("The Wire",3,5);
System.out.println(e2);
System.out.println(e.getTitle()+" comes before "+e2.getTitle()+" = "+e.comesBefore(e2));
}
}