MATHEMATICS MIDDLE SCHOOL

The formula F = 1.8C + 32 allows you to find the Fahrenheit (F) temperature for a given Celsius (C) temperature. Solve the equation for C to produce a formula for finding the Celsius temperature for a given Fahrenheit temperature

Answers

Answer 1

Answer:

Answer:

The formula to calculate the Celsius temperature for a given Fahrenheit temperature is:

$C=(F-32)/(1.8)$

Step-by-step explanation:

Given formula:

$F=1.8C+32$

where $F$ represents temperature in Fahrenheit and $C$ represents temperature in Celsius.

To solve the equation for $C$ .

Solution:

We have,

$F=1.8C+32$

Subtracting both sides by 32.

$F-32=1.8C+32-32$

$F-32=1.8C$

Dividing both side by 1.8

$(F-32)/(1.8)=(1.8C)/(1.8)$

$(F-32)/(1.8)=C$

∴ $C=(F-32)/(1.8)$

Using the above formula, we can calculate the Celsius temperature for a given Fahrenheit temperature.

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Hi Thx I'm new here

Answers

A is True

B is true

C is false

D is false

I hope that's help:0

Jared is putting a new deck off the kitchen. The deck will be 94.45 inches deep. He will use 16 boards that are each 5.7 inches wide. He has to leave a small space between the boards. If the 15 spaces between the boards are all equal, how wide will they be?

Answers

16 boards that are 5.7 inches wide each make a total of 91.20 inches.

16
x 5.7
112
+800
91.2 inches

Since the deck itself is 94.45 inches deep, we can subtract 91.2 from the number:

94.45
-91.20
3.25 inches.

Finally, we divide 3.25 by 15, since that's the amount of spaces we want and they have to be equal:

3.25/15= .21667

We'll round that to two numbers, so we'll end up with .22.

Your final answer is .22 inches wide for each space.

-4.3g=25.8 what is the awnser

Answers

$-4.3g=25.8\ \ \ \ |divide\ both\ sides\ by\ (-4.3)\n\ng=(25.8)/(-4.3)\n\ng=-(258)/(43)\n\n\huge\boxed{g=-6}$

$\sf - 4.3g = 25.8 \n \n Divide \ both \ sides \ by \ - 4.3 \n \n (- 4.3g)/(- 4.3) = (25.8)/(-4.3) \n \n \huge = g = - 6$

What are the vertex and x-intercepts of the graph of y= x2 - 6x - 7?Selectone answer for the vertex and one for the x-intercepts.
A. x-intercepts: (1,0), (7,0)
B. Vertex: (3,-16)
C.Vertex: (-3,20)
D. Vertex: (3, 20)
E. x-intercepts: (-1,0). (7.0)
F. x-intercepts: (1.0), (-7,0)

Answers

The vertex and $x-$ intercepts of the graph of $y= x^2 - 6x - 7$ will be $(3,-16)$ and $(7,-1)$ , respectively.

What are vertex and $x-$ intercepts of the graph?

A vertex in a quadratic equation is the minimum or maximum point of the equation and an $x-$ intercept of a graph is the point at which the graph intersects the $x-$ axis.

Vertex form, $y=a(x-h)^2+k$

We have,

$y= x^2 - 6x - 7$

Now,

Find the $x-$ intercept and to find $x-$ intercept put $y=0$ ;

i.e. $y= x^2 - 6x - 7$

$0= x^2 - 6x - 7$

$x^2 - 6x - 7=0$

Now using Mid-term split method find value of $x$ ;

$x^2 - 7x+1x - 7=0$

$x(x - 7)+1(x - 7)=0$

$(x - 7)(x +1)=0$

$(x - 7)=0$ ⇒ $x=7$

$(x +1)=0$ ⇒ $x=-1$

So, these are the $x-$ intercept $(7,-1)$ of the expression.

Now find the vertex using the above given formula;

$y=a(x-h)^2+k$

Rewrite in vertex form

$y= x^2 - 6x - 7$

Add and subtract $(-3)^2$ in given expression;

$y= x^2 - 6x + (-3)^2 -7 - (-3)^2$

$y = x^2 - 6x + 9 -7 - 9$

$y = x^2 - 6x + 9 -16$

Now convert quadratic part of equation in $(a-b)^2$ ;

$y = (x-3)^2-16$

Now compare it with $y=a(x-h)^2+k$

We get, $h=3,\ k=-16$

So, these are the vertex $(3,-16)$ of expression.

Hence, we can say that the vertex and $x-$ intercepts of the graph of $y= x^2 - 6x - 7$ will be $(3,-16)$ and $(7,-1)$ , respectively.

To know more about vertex and $x-$ intercepts of the graph click here

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The answer is B and E

15. The annual rental charge for office furniture that Budget Blinds uses is $862.50. Insurance andusage charges come to 1.5% of the total. What is Budget's monthly payment?

Answers

Answer:

The Budget's monthly payment is $72.95.

Step-by-step explanation:

The annual rental charge of Budget Blinds = $862.50

Insurance and usage charges = 1.5% of $862.50

So, the charges are $(1.5)/(100) * 862.5 = 12.93$

Hence, the additional charge is $12.93

So, the total payment yearly = $862.50 + $12.93 = $875.43

So, the monthly payment = $875.43 / 12

= $72.95

Hence, the Budget's monthly payment is $72.95.

A football player weighed 170 2/3 pounds in May. During the summer, he gained 25 5/12 pounds. During the first week of fall practice, he lost 10 1/4 pounds, and during the second week he lost another 3 1/2 pounds. How much did he weigh at that point?A: 182 1/3 lb
B: 181 1/2 lb
C: 182 5/12 lb
D: 183 2/3 lb

Help please?

Answers

We need to find the weight of a person at a certain period of time.

The weight of the person at the required time is A. $182(1)/(3)\ \text{lb}$

Initial weight of person = $170(2)/(3)$ pounds.

Weight gained = $25(5)/(12)$ pounds

Weight lost = $10(1)/(4)+3(1)/(2)$ pounds

So, weight of the person is

$170(2)/(3)+25(5)/(12)-(10(1)/(4)+3(1)/(2))\n =170+(2)/(3)+25+(5)/(12)-(10+(1)/(4)+3+(1)/(2))\n =195+(8+5)/(12)-13-(1+2)/(4)\n =182+(13)/(12)-(3)/(4)\n =182+(13-3)/(12)\n =182+(10)/(12)\n =182+(1)/(3)=182(1)/(3)$

The weight of the person at the required time is A. $182(1)/(3)\ \text{lb}$

Learn more:

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Answer:

182 1/3 lbs

MAY: weight = 170 2/3

Summer: gained 25 5/12

New weight : 170 2/3 + 25 5/12

Get a common denominator of 12

170 2/3 *4/4 + 25 5/12

170 8/12 + 25 5/12 = 195 13/12

The he lost 10 1/4 during the first week of fall practice

195 13/12 - 10 1/4

We need to get a common denominator of 12

195 13/12 - 10 1/4*3/3

195 13/12 - 10 3/12

185 10/12

The he lost another 3 1/2 pound during the second week

185 10/12 - 3 1/2

We need to get a common denominator of 12

185 10/12 - 3 1/2 * 6/6

185 10/12 - 3 6/12

182 4/12

Simplify the fraction

182 1/3 lbs

Hope this helps!

have a great day! :))))))

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The formula F = 1.8C + 32 allows you to find the Fahrenheit (F) temperature for a given Celsius (C) temperature. Solve the equation for C to produce a formula for finding the Celsius temperature for a given Fahrenheit temperature

Answers

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What are vertex and intercepts of the graph?

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What are vertex and $x-$ intercepts of the graph?