Find the slope of the line graphed below.
Find the slope of the line graphed below. - 1

Answers

Answer 1
Answer:

Answer:

The answer to your question is m = - (4)/(7)

Step-by-step explanation:

Process

1.- Find two points of the line (red points)

   A ( 4, -5)  and B (- 3 , -1)

2.- Find the slope using the formula

    m = (y2 - y1)/(x2 - x1)

  Substitution

   m = (-1 + 5)/(-3 - 4)

   m = - (4)/(7)


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ron baby sat 2 hours each night for 10 nights . she earned a total of $ 180 babysitting .ron wants to caculate her hourly rate . how much did ron earn per hour

Answers

Hello Raanee!

First, you would mulitply 2*10 which equals to 20.

Next, you divide your answer by 180, so you will divide 180/20 which equals to 9.

Thus, Ron earns 9 dollars an hour, so your answer is 9 dollars.

Cheers!
-Blizzard

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Which numbers from the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10), if any, will solve this equation?2x + 3 = 5x - 3

Answers

Answer:

2

Step-by-step explanation:

2(2)+3=7

5(2)-3=7

Answer:

2

Step-by-step explanation:

2 multiplied by 2 is 4+3=7 and 5x2=10-3=7

This is worth 25 points

Answers

Answer:

Jesus loves you

Today only, a table is being sold at a 35% discount. The sale price is $624. What was the price yesterday.

Answers

Answer:

$624

Step-by-step explanation:

brainlyest please:)

The price of an Item has risen to $108 today. Yesterday it was $80. Find the percentage increase.

Answers

Answer:

74%

Step-by-step explanation:

If JL =120, what are the lengths of JK and KL

Answers

The length of JK is 42 and the length of KL is 69

Calculating Length

From the question, we are to determine the length of JK and KL

From the given information,

JK = 4x + 6

KL = 7x + 15

In the diagram,

JL = JK + KL

120 = 4x + 6 + 7x + 15

120 = 11x + 21

120 - 21 = 11x

99 = 11x

x = 99/11

x = 9

∴ JK = 4x + 6  = 4(9) + 6

JK = 36 + 6

JK = 42

and

KL = 7x + 15 = 7(9) + 6

KL = 63 + 6

KL = 69

Hence, the length of JK is 42 and the length of KL is 69

Learn more on Calculating length here: brainly.com/question/26034806

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