Look at the diagram below.The diagram on the left represents ______. The diagram on the right represents ______.
A.
the specific heat of a system; the heat of vaporization of a liquid
B.
the release of heat by a system; the absorption of heat by a system
C.
the absorption of heat by a system; the release of heat by a system
D.
the heat of vaporization of a liquid; the specific heat of a system

Answer:

The gas above it or boiling

Explanation:

Answer: the correct answer is option(d).

Explanation:

Energy required ,Q= ?

Mass of water , m = 17 grams

Temperature difference or = 15 °C

Specific heat value of water = 4.186 J/g °C

From the given value the , nearest value to to our calculated answer is 1067 J that option (b).

Hence, the correct answer is option (d).

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Explanation:

The observations are as follows:  Initially with the plates in the dark, no electrons pass between the plates and no current flows.   As we shine light on the plates, going from low energy red to high energy blue, suddenly current begins to flow.  How?

Einstein explained the result be describing the light waves as packets of energy.  He called the packets of energy photons.  Each photon has a specific energy, the shorter the wavelength, the higher the energy.  When a high-energy photon hits the plate (such as a green or blue), the photon has enough energy to knock out an electron and then the electron, being negative, will fly to the positive side.  At this point, current flows.

The lower energy photons are unable to know out the electrons and no energy can flow.

The exciting thing to note is the treatment of energy as a particle or a packet, it is consistent with the fact energies are not additive.  If we can bump electrons with light at 600 tera-hertz , we can�t just use 300 tera-hertz for twice the time and still expect to bump electrons.

What if the photon has greater than the threshold energy required to pop out an electron?  The extra energy just goes into the kinetic energy of the electron.  This relationship can be described by the following equation.

hf = w + KE

where hf is the energy of the photon.

w is the energy required to bump an electron.

KE is the kinetic energy of the electron.

If the photon has less energy than w, no electron is emitted.

Final answer:

Increasing the brightness of light for red, yellow, orange, and green colors can cause a metal to absorb more energy and potentially undergo physical or chemical changes such as expansion or emitting light of a certain color.

Explanation:

Increasing the brightness of the light for the colors red, yellow, orange, and green will affect the metal in different ways depending on the specific metal being used. Generally, metals will absorb some of the energy from the light and convert it into heat. This increase in heat can cause the metal to expand, change its color, or undergo other physical or chemical changes.

For example, when a metal is exposed to bright light, it may heat up and expand, leading to changes in its shape or dimensions. Additionally, depending on the metal and its properties, the increased brightness of light can lead to certain metals absorbing specific wavelengths of light, which can cause the metal to emit photons and exhibit a characteristic color.

In summary, increasing the brightness of light for red, yellow, orange, and green colors can cause a metal to absorb more energy and potentially undergo physical or chemical changes such as expansion or emitting light of a certain color.

Learn more about Effects of increased light brightness on metals here:

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