When constructing parallel lines with a compass and straightedge, how should you start the construction?

Answers

Answer 1

Answer: that would build a line parallel to and passing through a given point outside the line. Building a straight line passing through the given point perpendicular to the given line. Then build a straight line passing through the given point perpendicular constructed perpendicular. Obtained in this direct and will be required.

Answer 2

Answer:

Answer:

You should start the construction by creating a line that intersects the given line with your straightedge.

Step-by-step explanation:

You should start the construction by creating a line that intersects the given line with your straightedge.

Related Questions

Find five rational numbers between - 1⁄3 and 1⁄3 (both are fractions : negative one third and positive one third)
Which Statement is true?A. |-8| < |8|B. |-2| > 1C. |-7| = -7D. |12| > |-15|
How do you solve this? 18 " n=21
If you help me get this right i will give you brainly, and 5 stars!
Write an expression that represents "the product of a number and 12".

Pls I need help !!!!!!!

Answers

Answer:

-3 -4

Step-by-step explanation:

Bc it's why not ...... ummmmmmm

A movie theater has 24 screens. The ratio of action films tp other films currently showing on all screens 1:2. How many action films are currently showing?

Answers

Answer: Currently 8 action films are being shown

Step-by-step explanation:

Step 1

Ratio of action film to other films = 1:2

which means 1 action movie would be shown for every 2 other films

Total ratio = 1+2 = 3

Step 2

Number of action films shown = ratio of action film/ total ratio x 24 screens

= 1/3 x 24 = 8

Number of other films shown = ratio of other films/ total ratio x 24 screens

= 2/3 x 24 = 16

Currently 8 action films and 16 other films are being shown

Joey is buying plants for his garden. He wants to have at least twice as many flowering plants as nonflowering plants and a minimum of 36 plants in his garden. Flowering plants sell for $8, and nonflowering plants sell for $5. Joey wants to purchase a combination of plants that minimizes cost. Let x represent the number of flowering plants and y represent the number of nonflowering plants. What are the vertices of the feasible region for this problem?
(0, 0), (0, 36), (24, 12)
(0, 36), (24, 12)
(0, 36), (24, 12), (36, 0)
(24, 12), (36, 0)

Answers

(24, 12) and (36, 0). The least amount of flowering plants occurs when x=2y, and the largest amount occurs when y=0. These two points satisfy both conditions and both sum to 36.

Answer: (24, 12), (36, 0)

Step-by-step explanation:

Let x be the number of flowering plants and y be the number of non- flowering plants.

According to the question, we need to minimize the cost of plants.

$Minimize:8x+5y$

Subject to the constraints,

$2y\leq\ x\nx+y\geq36$

To find the feasible region find the points of the equation to plot it on graph.

For the first equation $2y=x$ , at x=0 y=0 and at x=4, y=2

For the second equation $x+y=36$ , at x=0 y=36 and at x=36, y=0

Thus points for eq (1) are (0,0) and (4,2) and points for equation (2) are (0,36) and (36,0).

Now, plot it on graph, we get the shaded feasible region as shown in the graph.

and we can see the vertices of the feasible region = (24, 12), (36, 0)

If 3a - 2 = 10, what is the value of 8a + 1?

Answers

Answer:

8a+1=33

Step-by-step explanation:

you can solve 3a-2=10 by simplifying to 3a=12, so a=4. Then you replace the a in 8a+1 with 4 to get 32+1, which is 33

Answer:

Step-by-step explanation:

3a-2= 10

3a=12

a=4

in this equation a=4 so you substitute that value into the other equation

8(4) +1=33

1. What is the volume of the prism that can be constructed from this net? 2. What is the volume of this figure?
3. What is the volume of this figure?
4. What is the volume of the prism that can be constructed from this net?

Answers

1. V = lwh
V = (8)(4)(5)
V = (32)(5)
V = 160 units³

2. V = lwh + lwh
V = (4)(2)(1) + (3)(1)(1)
V = (8)(1) + (3)(1)
V = 8 + 3
V = 11 units³

3. V = leh + s³
V = (9)(3)(4) + (3)³
V = (27)(4) + 27
V = 108 + 27
V = 135 units³

4. V = lwh
V = (3)(7)(2)
V = (21)(2)
V = 42 units³

Evaluate the log without a calculator ( Show your work )

$log_(25) (1)/(5)$