PHYSICS HIGH SCHOOL

A gas has an initial volume of 24.6 L at a pressure of 1.90 atm and a temperature of 335 K. The pressure of the gas increases to 3.50 atm, and the volume of the gas increases to 31.3 L.

Answers

Answer 1
Answer: The problem can be solved by using the formula associated with the gas laws. It is as follows:

PV/T

Given:

P1 = 1.9 atm
V1 = 24.6 L
T1 = 335 K 

P2 = 3.5 atm
V2 = 31.3 L 
T2 = ?

Substituting the given:

P1V1/T1 = P2V2/T2
(1.9 * 24.6)/335 = (3.5 * 31.3)/T2
T2 = 785.18 K

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Light travels 300,000,000 m/s, and one year has approximately 32,000,000 seconds. A light year is the distance light travels in one year. State this distance in centimeters.

Answers


       (3 x 10⁸ meter/sec) x (100 cm/meter) x (3.2 x 10⁷ sec/year)

   =  (3 x 10⁸ x 100 x 3.2 x 10⁷)  (meter-cm-sec) / (sec-meter-yr)

   =   (      9.6 x 10¹⁷       )                (  cm/yr  )

How does electricity flow?A.)from low potential to high potential
B.)from conductor to insulator
C.)from high potential to low potential
D.)from series circuit to parallel circuit

Answers

The answer is C.) High to low is the same thing as positive to negative.
Hope this helps!
C.) electricity always flows from high to low

A piece of a newly synthesized material of mass 25.0 g at 80.0◦C is placed in a calorimeter containing 100.0 g of water at 20.0◦C. If the final temperature of the system is 24.0◦C, what is the specific heat capacity of this new material? 1. 1.20 J/g ◦C 2. 7.46 J/g ◦C 3. 4.76 J/g ◦C 4. 0.30 J/g ◦C 5. 0.84 J/g ◦C

Answers

Answer:

1.Cp₁ = 1.2 J/g.⁰C

Explanation:

For new material:

m₁  = 25 g

T₁ = 80⁰C

specific heat of water = Cp₁

For water :

m₂ = 100 g

T₂ = 20⁰C

The final temperature T=24⁰C

We know that specific heat of water Cp₂ = 4.187 kJ/kg.K

The heat lost new material = Heat gain by Water

m₁ Cp₁ ( T₁ - T ) = m₂ Cp₂ (T- T₂)

25 x Cp₁ (80- 24 ) = 100 x 4.817 (24 - 20 )

Cp₁  x 56 = 4 x 4.187 x 4

C_(p1)=(4* 4.187* 4)/(56)\ kJ/kg.K

Cp₁ = 1.19 kJ/kg.K

Cp₁ = 1.2 J/g.⁰C

the three small spheres shown in (figure 1) carry charges q1 = 3.50 nc , q2 = -7.50 nc , and q3 = 2.05 nc .

Answers

Answer:

It seems you're describing a scenario with three small spheres, each carrying a different electric charge:

1. Sphere 1: Charge \(q_1 = 3.50 \, \text{nC}\)

2. Sphere 2: Charge \(q_2 = -7.50 \, \text{nC}\)

3. Sphere 3: Charge \(q_3 = 2.05 \, \text{nC}\)

If you have a specific question or if there's a particular calculation or scenario you'd like to explore with these charges, please provide more details, and I'll be happy to assist you further.

Firearms are typically found in which way

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Gunshots Are Found By Fingerprints Or Gunshot Residue Hope It Helps☺️

The weight of a body in earth is 29N. Find the mass?

Answers

Hi!

The weight force is given by: F = mg (mass x gravity)

Then, we have:
29 = m * 9.8
29/9.8 = m
m = 2.95 kg

;)
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