Find the product.

(7q - 5)(7q + 5)

Answers

Answer 1
Answer: (7q−5)(7q+5) =(7q+−5)(7q+5) =(7q)(7q)+(7q)(5)+(−5)(7q)+(−5)(5) =49q2+35q−35q−25 =49q2−25

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What is the formula for V=lwh for h

Answers

remember, you can do anythingn to an equaiton as long as you do it to both sides (except divide by zero)

solve for h
V=lwh
divide both sides by lw
V/(lw)=h
tada

What is the equation of the line passing through the points (–5, –2) and (3, 14) in slope-intercept form?

Answers

Answer:

2x-y+2= 0

Step-by-step explanation:

(-5,-2)=(x1, y1)

(3, 14) =(x2, y2)

now,

slope(m)= y2-y1 / x2-x1

=14+2 / 3+5

= 16 /8

=2 units

passing point = (-5,-2) = x1,y1

now,

eqn of the line can be represented as,

y -y1 = m (x-x1)

y +2 = 2 (x +5)

y+2 = 2x +10

y = 2x+10-8

0 = 2x+2-y

2x-y+2 =0 is the required eqn

Answer:

licker 90000000000000000

the area of a rectangle is 52 in². the length of the rectangle is 9 in. longer than the width. what is the width of the rectangle? 8 in. 6 in. 4 in. 3 in.

Answers

length, l = width, w + 9
l = w + 9

area = length * width 
52 = l * w
52 = (w+9) w
52 = w^2 + 9w
w^2 + 9w - 52 = 0
w^2 + 13w - 4w - 52 = 0
w (w + 13) - 4 (w + 13) = 0
(w + 13) (w - 4) = 0

length = 13 in
width = 4 in

A cylindrical container has a base area of 100 m2 and is 12m high. If the container is one-third filled with water, what's the volume of the water in the container?

Answers

The volume of a cylinder is given by the base area times height. (i.e. V = base area x height). Given that the given cylinder is one-third filled with water, the height of the water in the cylinder = 1/2 x height of the cylinder = 1/3 x 12 = 4 m. Therefore, the volume of water in the cylinder = base area of the cylinder x height of water in the cylinder = 100 x 4 = 400 cubic meter.

Answer:400m3

Step-by-step explanation:

Graph y=2x+3 and it's inverse

Answers

The red line is y=2x+3
The blue line is its inverse : y=(x-3)/2

If a flexible air-filled container has a volume of 40 cu ft on the surface, what would the volume be at 99 feet in sea water

Answers

The volume of flexible air filled container at 99 feet in sea water is 10 cu.ft.

What is Boyle's law?

Boyle's Law states that If the temperature is constant, the volume of a  gas is inversely proportional to the absolute pressure.

V 1/V2 =P2/P1

V2 = P1 x V1 /P2

Substitute 60 psi for P2, 14.7 psi for P1 and 40cu.ft for V1, we get the volume V2

V2 = 40 x 14.7 / 60

V2 = 9.8 cu.ft

Volume is approximately 10 cu.ft.

Thus, the volume of flexible air filled container at 99 feet in sea water is 10 cu.ft.

Learn more about Boyles law.

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Answer:

50 cu ft

Step-by-step explanation: