Calculate the average rate of change for the given graph from x = –2 to x = 0 and select the correct answer below.please and thank you

Answers

Answer 1

Answer:

Keywords:

average rate of change, parabola, interval, points

For this case we have to find the average rate of change of a parabola in the interval from $x = -2$ to $x = 0$ . To do this, we need two points for the parabola pass, and apply the following formula:

$AVR = \frac {f (x_ {2}) - f (x_ {1})} {x_ {2} -x_ {1}}$

We have the following points, taking into account that $y = f (x)$ :

$(x_ {1}, f (x_ {1})) = (- 2, -1)\n(x_ {2}, f (x_ {2})) = (0, -1)$

Substituting:

$AVR = \frac {-1 - (- 1)} {0 - (- 2)}\nAVR = \frac {-1 + 1} {0 + 2}\nAVR = 0$

So, the average rate of change for the given graph is 0 in the given interval

Answer:

$AVR = 0\ from\ x = -2\ to\ x = 0$

Answer 2

Answer:

Answer:

Average rate of change(A(x)) of f(x) over the interval [a, b] is given by:

$A(x) = (f(b)-f(a))/(b-a)$

As per the statement:

From the given graph as shown :

At x = -2

then;

f(-2) = -1

At x = 0

then;

f(0) = -1

To find the average rate of change for the given graph from x = –2 to x = 0 .

Substitute the given values we have;

$A(x) = (f(0)-f(-2))/(0+2)$

⇒ $A(x) = (-1-(-1))/(2)$

⇒ $A(x) = (-1+1)/(2)$

⇒ $A(x) =0$

Therefore, the average rate of change for the given graph from x = –2 to x = 0 is, 0

Related Questions

Question number 1 is attached below.
The school has budgeted $2000 for an end- of year party at the local park.the cost to rent the park is $150.how much can the student council spend per student on food if each of thde 225 students recieives a $3.50 gift?PLEASE HELP ID UNDERTSAND.....
Y=2/3x+5 in standard form
What is 1/10 of an income of $97.50?
Explain how slope is used to determine if a triangle is a right triangle.

Write these expressions in exponential form. Example: 12 to the power of 2 x 12 to the power of 6= 12 to the power of 2 +61. 11 to the power of 16 x 11 to the power of 1=

2. a to the power of 6 x a to the power of 8 =

3. (-2) to the power of 12 x (-2) to the power of 1=

4. 1.1 to the power of 7 x 1.1 to the power of 9 =

5. 3 to the power of 4 x 5 to the power of 2 =

Answers

Step-by-step explanation:

1. 11 to the power of 16 x 11 to the power of 1

$11^(16)*11^1=11^(16+1)=11^{17$

2. a to the power of 6 x a to the power of 8

$a^6*a^8=a^(6+8)=a^(14)$

3. (-2) to the power of 12 x (-2) to the power of 1

$(-2)^(12)*(-2)^1=(-2)^(12+1)=(-2)^(13)$

4. 1.1 to the power of 7 x 1.1 to the power of 9

$1.1^7*1.1^9=1.1^(7+9)=1.1^(16)$

5. 3 to the power of 4 x 5 to the power of 2

Assumed it is both 3 or 5, we take 3

$3^4*3^2=3^(4+2)=3^6$

Please help me !! Answer both correctly for a brainliest and also a thanks ! Don't answer if you don't know it .

Answers

1. Exponential
2000 times 2= 4000 (60)
4000 times 2= 8000 (120)
8000 times 2= 16000 (180)
16000 times 2= 32000 (240)
2. pull a 2x out of everything
answer is b

Attached it how i did it!
~Good Luck~!

Jimmy’s age is one year less than the sum of the ages of his siblings Serena and Tyler. Which equation represents Jimmy’s age?A. look at the picturex represents Tyler’s age, y represents Serena’s age, and z represents Jimmy’s age
B. look at the picturex represents Jimmy’s age, y represents Tyler’s age, and z represents Serena’s age
C. look at the picturex represents Serena’s age, y represents Jimmy’s age, and z represents Tyler’s age
D. look at the picturex represents Jimmy’s age, y represents Serena’s age, and z represents Tyler’s age

Answers

i think it is d because the questions says: j-1+s+t

ABCD is a rectangle. Find the length of each diagonals.

AC = c over 3
BD = 4 - c

Answers

Diagonals are congruent

|AC| = |BD|

$(c)/(3)=4-c\ \ \ |multiply\ both\ sides\ by\ 3\n\n\not3^1\cdot(c)/(\not3_1)=3(4)-3c\n\nc=12-3c\ \ \ |add\ 3c\ to\ both\ sides\n\n4c=12\ \ \ \ |divide\ both\ sides\ by\ 4\n\n\boxed{c=3}\n\n|AC|=|BD|=(3)/(3)=1$

Write an equation of the line that has each pair of intercepts:X-intercept:-3, Y-intercept:6 How do I do this?

Answers

$x-intercept:-3 = \ (-3,0)\n\n y-intercept:6= \ (0,6)\n \nFirst \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \n \n m= (y_(2)-y_(1))/(x_(2)-x_(1) ) \n \nm=(6-0)/(0+3) = (6)/(3)=2 \n \n Use \ point \ form \ of \ a \ line\ with \ one \ point: \n \n y-y_(1) =m(x-x _(1)) \n\ny-0 = 2(x-(-3))\n\ny=2(x+3)\n\ny=2x+6$

1) The points (-2,5) and (2,3) lie on the same line. Write the equation of the line in slope-intercept form. Type your answer in as y=mx+b. 2) The slope of a line is -12, and the line passes througin the point (0,8). Write the equation for the line in slope intercept form. Type your answer in as y=mx+b.

Answers

Answer:

1) The equation of the line is y = $(-1)/(2)$ x + 4

2) The equation of the line is y = -12x + 8

Step-by-step explanation:

The slope-intercept form of the linear equation is y = m x + b, where

m is the slope of the line, m = Δy/Δx (chang of y/change of x)

b is the y-intercept (value y at x = 0)

Let us solve the two questions

∵ points (-2, 5) and (2, 3) lie on the same line

→ Find the slope m

∵ Δ x = 2 - (-2) = 2 + 2 = 4

∵ Δ y = 3 - 5 = -2

∴ m = $(-2)/(4)=(-1)/(2)$

∴ The slope of the line is $(-1)/(2)$

→ Substitute the value of m in the form of the equation above

∴ y = $(-1)/(2)$ x + b

→ To find b substitute the x and y in the equation by the coordinates

of a point on the line

∵ Point (-2, 5) lies on the line

∴ x = -2 and y = 5

∵ 5 = $(-1)/(2)$ (-2) + b

∴ 5 = 1 + b

- Subtract 1 from both sides

∴ 5 - 1 = 1 - 1 + b

∴ 4 = b

→ Sustitute it in the equation

∴ y = $(-1)/(2)$ x + 4

The equation of the line is y = $(-1)/(2)$ x + 4

∵ The slope of the line is -12

∴ m = -12

∵ The line passes through point (0, 8)

∵ b is the value of y at x = 0

∴ b = 8

→ Substitute the values of m and b in the form of the equation above

∴ y = -12x + 8

The equation of the line is y = -12x + 8

Final answer:

The equations of the lines are y=-0.5x+4 and y=-12x+8 respectively. For the first line, the slope is computed using provided points and the y-intercept is calculated using one of the points and the slope. For the second line, we use provided slope and point to write the equation.

Explanation:

Firstly, let's deal with the first part of the question. To write the equation of the line, we first need to calculate the slope. The slope (m) is calculated as (y2-y1)/(x2-x1). Using the points (-2,5) and (2,3) we find m=(3-5)/(2-(-2))= -2/4 = -0.5. The y-intercept (b) is the y value when x = 0. To find b, let's use the point (-2,5) and the slope in the equation y=mx+b. We get 5=(-0.5)*-2+b, hence b= 5-1= 4. So line equation is y=-0.5x+4.

For the second part of the question, we know that the slope (-12) and it passes through the point (0,8). So the y-intercept is 8 when x=0. Therefore, the equation of this line is y=-12x+8.

Learn more about Line Equations here:

brainly.com/question/35689521

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