The green ribbon is 96 cm long and if 67 cm of the green ribbon is used to wrap a present, the amount left is 29 cm
An equation is an expression that shows the relationship between numbers or variables.
Let x represent the length of the green ribbon.
The green ribbon is 38 cm longer than the blue ribbon, hence:
x = 58 cm + 38 cm
x = 96 cm
The green ribbon is 96 cm long.
If 67 cm of the green ribbon to wrap a present, the amount left is:
Amount left = 96 cm - 67 cm = 29 cm
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Answer:
a) green ribbon is 96cm long
b) 29cm is left
Step-by-step explanation:
a) length of green ribbon = 58cm + 38cm = 96cm
b) length of green ribbon left = 96cm - 67cm = 29cm
Answer:
The graph has two zeros namely 3 and 1.
Step-by-step explanation:
Consider the given equation of graph
According to the Fundamental Theorem of Algebra
For a given polynomial of degree n can have a maximum of n roots.
Thus, for the given equation the degree of polynomial is 2 , thus the function can have maximum of 2 roots.
We know at roots the value of function is 0 that is f(x) = 0,
Substitute f(x) = 0 , we get,
This is a quadratic equation,
We first solve it manually and then check by plotting graph.
Quadratic equation can be solved using middle term splitting method,
here, -4x can be written as -x-3x,
Using zero product property,
or
or
Thus, the two zero of f(x) are 3 and 1.
We can also see on graph attached below that the graph has two zeros namely 3 and 1.
Answer:
2 roots
2 zeros
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
Quad means four
Hence
Every quadrilateral is a four sides figure
the answer is 'true'.....all quadrilaterals are four sided figures. Infact four sided polygons or four sided figures are called quadrilaterls
Answer:
108 pounds of mulch.
64 pounds of gravel.
Step-by-step explanation:
Let x be the amount of mulch sold and y be the amount of gravel sold.
We have been given that a supplier sells 2 1/4 pounds of mulch for every 1 1/3 pounds of gravel.
We can represent this information as:
We are also told that the supplier sells 172 pounds of mulch and gravel combined. We can represent this information as:
From equation (1) we will get,
Substituting this value in equation (2) we will get,
Now let us have a common denominator.
Therefore, the supplier sold 64 pounds of gravel.
Upon substituting y=64 in equation (2) we will get,
Therefore, the supplier sold 108 pounds of mulch.