CHEMISTRY HIGH SCHOOL

In the pie chart below, which of the following represents the amount of Earth's water located in the oceans?A pie chart with part A representing 2%, part B representing .8%, part C representing .2% and part D representing 97%.

A only
A and B
C only
D only

Answers

Answer 1

Answer: D Only . 97% is ocean

Answer 2

Answer:

Answer:

D Only . 97% is ocean

Explanation:

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What is true about the metals in group 1A, 2A, 3A?a)all form ions with negative charges
b)all have ions with a 1+ charge
c)gain electrons when they form ions
d)lose electrons when they form ions

Answers

D, becuase they have toatal no of valence electron as their group nmber and we know the metals are those who have 1,2,3 electrons in their outermost

A student determines that according to the reaction N2(g) + 3H2(g) --> 2NH3(g), if 34g of nitrogen gas is reacted with excess hydrogen, 41g of ammonia can be produced. When the actual reaction was complete, only 38g of ammonia formed. Determine the percent yield for the reaction.

Answers

Answer:

The percent yield of this reaction is 92.7 %

Explanation:

Step 1: Data given

Mass of nitrogen gas (N2) = 34.0 grams

Mass of ammonia (NH3 produced = 41.0 grams

Molar mass of N2 = 28.0 g/mol

Molar mass of NH3 = 17.02 g/mol

Actual yield of ammonia = 38 grams

Step 2: The balanced equation

N2(g) + 3H2(g) → 2NH3(g)

Step 3: Calculate moles

Moles = mass / molar mass

Moles N2 = 34.0 grams / 28.0 g/mol

Moles N2 = 1.214 moles

Step 4: Calculate moles NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 1.214 moles N2 we'll have 2* 1.214 = 2.428 moles NH3

Step 5: Calculate mass NH3

Mass NH3 = moles * molar mass

Mass NH3 = 2.428 moles * 17.02 g/mol

Mass NH3 = 41 grams

Step 6: Calculate percent yield for the reaction

Percent yield = (actuald yield / theoretical yield) * 100 %

Percent yield = (38 grams / 41 grams ) * 100 %

Percent yield = 92.7 %

The percent yield of this reaction is 92.7 %

Answer:

$Y=92\%$

Explanation:

Hello,

In this case, by considering the given chemical reaction, with given mass of nitrogen, one could compute the theoretical yield of ammonia as shown below and considering their 1 to 2 molar relationship in the chemical reaction:

$m_(NH_3)^(theoretical)=34gN_2*(1molN_2)/(28gN_2)*(2molNH_3)/(1molN_2)*(17gNH_3)/(1molNH_3) \nm_(NH_3)^(theoretical)=41.3gNH_3$

In such a way, the percent yield is obtained as shown below:

$Y=(m_(NH_3)^(actual))/(m_(NH_3)^(theoretical)) *100\%=(38g)/(41.3g) *100\%\n\nY=92.0\%$

Best regards.

Which change occurs when a barium atom loses two electrons?(1) It becomes a negative ion and its radius decreases.(2) It becomes a negative ion and its radius increases.(3) It becomes a positive ion and its radius decreases.(4) It becomes a positive ion and its radius increases.

Answers

Changes Occurs when a Barium Atom - Option 3

When a barium atom loses two electrons it becomes a positive ion and its radius decreases. Barium (Ba) has atomic number 56 so it has 2 electrons in first shell of an atom to become stable according to duplet rule. Then other 52 electrons revolve in the shells according to octet rules.

Another 2 electrons are in the outermost shell. To become stable electrons lose to form barium ions (Ba+2). Hence, by losing 2 electrons the outermost shell will be diminished so its radius decreases and by losing electrons it becomes positive ions.

Answer:

The correct answer is option 3, It becomes a positive ion and its radius decreases

Explanation:

As per the Octet rule, Barium has 2 electrons in its outermost shell. When it loses the two electron it gains two positive charge i.e Ba2+. As the barium loses the two electron from its outermost shell, the outermost shell becomes vacant and thus is no more considered as a part of atomic geometry of the barium atom and since the outermost shell is considered negligible the radius of barium atom reduces automatically.

Which of the following can be used to neutralize an ammonia (NH3) solution?

Answers

It really depends on your options.
Since NH3 solution is a weak base, the option that neutralizes a base is an acid. So find an acid among your options, and here are some examples: HNO3, HCl, etc.

It would have been much better if you had attached some options to choose. But I think I've got what you mean. I bet that solution is HCl.

The temperature at which a liquid becomes a solid is the: a. boiling point
b. density
c. freezing point
d. solubility

Answers

The answer is "c" because solidification or freezing is the term used for the process in which a liquid becomes a solid. Freezing is an exothermic process that also is an example of a phase transition

GIVING BRAINLIEST!!! A student observes a beaker of room temperature water resting on a table. She states that the beaker of water does not have any energy. Which statement below is accurate regarding her observation?a. She is correct because the beaker of water is not moving.

b. She is incorrect because the beaker of water has thermal energy.

c. She is incorrect because all water contains hydrogen and oxygen.

d. She is correct because the beaker of water is at room temperature.

Answers

Answer:

Explanation:

im thinking because the water is a room temperature there shouldnt be anm immence amount og heat energy for it to have a good amount of energy tho i could be wrong because its not moving it could have no energy.

Answer: please tell me i have this exact thing on a test rn i need the answer

Explanation:

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