MATHEMATICS HIGH SCHOOL

Verify the identity. Show your work.

(1 + tan2u)(1 - sin2u) = 1

Answers

Answer 1
Answer: I assume you mean (1 + tan^2u)(1 - sin^2u) = 1 so I solved it like that 

because tanu = sinu / cosu ⇒ tan^2u = sin^2u / con^2u

(1 + sin^2u/cos^2u)(1 - sin^2u) =
(cos^2u/cos^2u + sin^2u/cos^2u)(1 - sin^2u) =
((cos^2u + sin^2u)/(cos^2u)) (1 - sin^2u) =

and because cos^2u + sin^2u = 1 we'll have

(1/(cos^2u)) (1 - sin^2u) =
1/(cos^2u) - sin^2u/(cos^2u) =
(1 - sin^2u) / (cos^2u) =

notice that 1 - sin^2u is equal to cos^2u

cos^2u / cos^2u = 1

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Need to know if i answered this correctly Asap!! It's multiplying Matrices.

The sales tax in Bill's state is 6%. Bill bought a Scion having a sales tax of $820. What was the cost of the car? Round to the nearest dollar. A. $13,666 B. $13,668 C. $13,665 D. $13,667

Answers

tge answer is B I THINK

I have class in a half an hour and I still haven't solved all of the hw questions... please help guys I'll give 90 points and brainliest for the first correct answer with brief explanation: thank you SOOOOOOOOOO much!Given: E, F, Q, D∈k(O),O ∈ ED, m∠DFQ = 10°, measure of arc EF = 28° Find: Angles of △EFQ

Answers

Answer:

Angles of △EFQ:

m<EFQ = 100°

m<EQF = 14°

m<FEQ = 66°

Step-by-step explanation:

ED is the diameter of the circle O

so m<EFD = 1/2 (180) = 90°

Given m∠DFQ = 10°

△EFQ

m<EFQ = m<EFD + m∠DFQ = 10° + 90° = 100°

arc EF = 28°,

so m<EQF = 1/2 (28) = 14°

m<FEQ = 180 - ( 100° +  14°) = 66°

Answer:

m<EFQ = 100°

m<EQF = 14°

m<FEQ = 66°

Doris put $4000 in a 5­year CD paying 6% interest compounded monthly. After 2 years, she withdrew all her money, and as an early withdrawal penalty, she paid back all the interest she made during the first year. How much money was Doris left with? Show your work.

Answers

Answer:  Doris was left with $4216.93.

Step-by-step explanation:

Since we have given that

Principal amount = $ 4000

Rate of interest = 6%

He put $4000 in a 5 year CD paying 6% interest compounded monthly.

After 2 years, she withdrew all her money.

so, Amount after 2 years when it is compounded annually.

A=4000(1+(6)/(12* 100))^(12* 2)\n\nA=4000(1+0.005)^(24)\n\nA=4000(1.005)^(24)\n\nA=\$4508.64

As an early withdrawal penalty, she paid back all the interest she made during the first year.

Interest=4000[(1+0.005)^(12)-1]\n\nInterest=\$246.71

Amount left with Doris is given by

\$4508.64-\$246.71\n\n=\$4261.93

Hence, Doris was left with $4216.93.
for APEX it is going to be 4261.93

In a right triangle, angle C measures 40. the hypotenuse of the triangle is 10 inches long. what is the approximate length of the side adjacent to angle C

Answers

answer is 7.66"or 7.7"
cos40=x/10
calculate # 10*cos40
*note .. in your calculator don't forget to 'Degree'
[calculate]
10*cos40
answer is 7.7"

To solve the problem: "What is 3/4 of 12," you would _____ .

Answers

The value of the problem is given by the equation A = 9

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

A = ( 3/4 ) of 12

Substituting the values in the equation , we get

A = ( 3/4 ) x 12

On simplifying , we get

A = 3 ( 4/12 )

A = 3 x 3

A = 9

Therefore , the value of the problem is 9

Hence , the equation is A = 9

To learn more about equations click :

brainly.com/question/19297665

#SPJ2

Answer:

multiply

Step-by-step explanation:

Existen tres órdenes de producción en proceso. Las ordenes A y B juntas tienen 150 unidades; B y C juntas, 100 unidades, y A y C juntas, 150 unidades. ¿Cuánto tiene cada orden?

Answers

orders are a, b, c, lets write equations to represent the problem's info:
a + b = 150
b + c = 100
a + c = 150
so we have 3 unknowns and 3 equations, so we can solve.
Use the first equation:
a + b = 150
a = 150 - b
and substitute in the 3rd:
a + c = 150
150 - b + c = 150
then
b = c
and we can substitute that in the original equation:
b + c = 100
2b = 100
b = 50
c = 50
and substitute in the first equation:
a + b = 150
a = 150 - b = 150 - 50
a = 100
then a = 100, b = c = 50
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