MATHEMATICS HIGH SCHOOL

If cos Θ = negative two over five and tan Θ > 0, what is the value of sin Θ? negative square root / 21 negative square root / 21 over 5 square root / 21 over 5 square root of 21 over 2

Answers

Answer 1

Answer:

Answer: The correct option is (B) negative square root 21 over 5.

Step-by-step explanation: Given that for an angle $\theta$ ,

$\cos \theta=-(2)/(5),~~~\tan \theta>0.$

We are to find the value of $\sin \theta.$

We know that

Cosine is negative in Quadrant II and Quadrant III.

Tangent is positive in Quadrant 1 and Quadrant III.

So, the given angle $\theta$ lies in the Quadrant III.

We will be using the following trigonometric identity:

$\cos^2\theta+\sin^2\theta=1.$

We have

$\cos \theta=-(2)/(5)\n\n\n\Rightarrow √(1-\sin^2\theta)=-(2)/(5)\n\n\n\Rightarrow 1-\sin^2\theta=(4)/(25)\n\n\n\Rightarrow \sin^2\theta=1-(4)/(25)\n\n\n\Rightarrow \sin^2\theta=(21)/(25)\n\n\n\Rightarrow \sin \theta=\pm(√(21))/(5).$

Since the angle $\theta$ lies in Quadrant III and sine is negative in that quadrant, so

$\sin\theta=-(√(21))/(5).$

Thus, option (B) is correct.

Answer 2

Answer:

Answer:

$sin\theta=-(√(21))/(5)$ Option B is the correct option.

Step-by-step explanation:

It is given in the question $cos\theta =-(2)/(5)$ and $tan\theta >0$

We have to calculate the value of $sin\theta$

We can see in the figure attached since cos∅ = -2/5

Here negative sign is showing that angle theta is lying either in quadrant 2nd or 3rd.

And $tan\theta >0$ is showing as angle is either in quadrant 1 or 3rd.

Therefore it is confirm that angle is lying in quadrant 3 where sine is always negative.

Therefore $sin\theta=-(√(21))/(5)$ will be the answer.

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Activity 4: Factor Then solve1. x^2+7x=0
2. 6s^2+18s=0
3. t^+8t+16=0
4. x^2-10x+25=0
5. h^2+6h=16
6. x^2-14=5x
7. 11r+15=-2r^2
8. x^2-25=0
9. 81-4x^2=0
10. 4s^2+9=12s

PLEAAASE HELP ME!

Answers

very complex, you should ask each individual question, or give more points
general strategy:
get 1 side to equal 0
factor
set each factor to 0
solve

1. factor out the x and set each to zero
x(x+7)=0
x=0

x+7=0
subtract 7
x=-7
x=0 or -7

2. factor out the 6s
6s(s+3)=0
6s=0
s=0

s+3=0
subtract 3
s=-3
s=-3 or 0

3. I'm assuming that the equation was supposed to be t^2+8t+16 so
find what 2 numbers multiply to get 16 and add to get 8
the numbers are 4 and 4
factor
(x+4)(x+4)=0
x+4=0
subtract 4
x=-4

4. find what 2 numbers multipy to get 25 and add to get -10
the numbers are -5 and -5
factor
(x-5)(x-5)=0
set each to zero
x-5=0
add 5
x=5

5. subtract 16 from both sides
h^2+6h-16=0
find what 2 numbers multiply to get -16 and add to get 6
the numbers are -6 and 10
factor
(h-6)(h+10)=0
set each to zero
h-6=0
add 6
h=6

h+10=0
subtract 10
h=-10
h=-10 or 6

6.subtract 5x from both sides
x^2-5x-14=0
find what 2 numbers multiply to get -14 and add to get -5
the numbers are -7 and 2
factor
(x-7)(x+2)=0
set each to zero
x-7=0
add 7
x=7

x+2=0
subtract 2
x=-2
x=-2 or 7

7.add 2r^2 to both sides
2r^2+11r+15=0
difficult so multiply 2 and 15 and get 30
not factor and find what 2 numbers multiply to get 30 and add to get 11
the numbers are 5 nd 6
split 11 up into 5 and 6
2r^2+6r+5r+15=0
group and factor
(2r^2+6r)+(5r+15)=0
factor
2r(r+3)+5(r+3)=0
reverse distribute
(2r+5)(r+3)=0
set each to zero
2r+5=0
subtract 5
2r=-5
divide 2
r=-5/2

r+3=0
subtract 3
r=-3
r=-3 or -5/2

8. this is a difference of 2 perfect squares in which if you have
x^2-y^2 that factors out of (x-y)(x+y) so
x^2-25=0
x^2-5^2=0
(x-5)(x+5)=0
set each to zero
x-5=0
add 5
x=5

x+5=0
subtract 5
x=-5
x=-5 or 5

9. differnce of 2 perfect squares
81-4x^2=0
9^2-(2x)^2=0
(9-2x)(9+2x)=0
set each to zero
9-2x=0
add 2x to both sides
9=2x
divde 2
9/2=x

9+2x=0
subtract 9 from both sidees
2x=-9
divide 2
x=-9/2
x=-9/2 or 9/2

10. subtract 12s from both sides
4s^2-12s+9=0
multiply 4 and 9 and get 36
find what 2 numbers multiply to get 36 and add to get -12
the numbers are -6 and -6
split up the -12s into -6s and -6s
4s^2-6s-6s+9=0
group
(4s^2-6s)+(-6s+9)=0
factor
2s(2s-3)+(-3)(2s-3)=0
reverse distribute
(2s-3)(2s-3)=0
set each to zero
2s-3=0
add 3
2s=3
divide 2
s=3/2

ANWERS:
1. x=0 or -7
2. s=-3 or 0
3. x=-4
4. x=5
5. h=-10 or 6
6. x=-2 or 7
7. r=-3 or -5/2
8. x=-5 or 5
9. x=-9/2 or 9/2
10. s=3/2

Subtract the quotient of 15 ÷ 3 from the sum of 33 and 7.

Answers

35
because 40-5=35 and 15\3=5 and 33+7=40

What is the median number for the numbers 4,8,10,5,9

Answers

$First,\ put\ them\ in\ numerical\ order\ (least\ to\ greatest):\n\n4;\ 5;\ 8;\ 9;\ 10\n\nThe\ median\ is\ a\ middle\ number:\ your\ median\ is\ \boxed{8}$

Hello There!

Median: The middle number when all the numbers are listed in oder from least to greatest.

To find the median, place the numbers in order from least to greatest.

In this case, the numbers would be 4, 5, 8, 9, 10

The middle number would be 8 so the median for this set of numbers is 8.

Which operation should you do first 8 +3(7×4)-5÷2

Answers

Alsways do

P
E
M
D
A
S

do what in parenthesis first

u should do what is in parentheses first because if u do PEMDAS, you do whatever u see first, and since theres parentheses, u do whats it inside of th

I don't know how to do this :(

Answers

The answer would be A. ( 1, 0.75 )

Explanation:
According to "PEMDAS" you need to do the parenthesis first and then exponents. Since there is only one thing in the parenthesis and it doesn't require any further actions to be made, you would move on to exponents.
The parenthesis and exponent part is asking you to raise 1/2, or 0.5 to the x power. The x in the equation equals the x in the coordinates that are your answer choices. Basically, you're just raising 0.5 to the value of the x in the coordinates.
After this, you multiply the number that you got by 1.5. Since in the equation it said that y = the result, whatever you got would be the y value.
So the value of x is the one that you plugged in, and y is the result.

DEMONSTRATION:
A. 0.5 * 1 (x) = 0.5
0.5 * 1.5 = 0.75
x = 1, y = 0.75

B. 0.5 * -2 = -1
-1 * 1.5 = -1.5
x = -2, y = -1.5
However the answer option is wrong because according to it y = 3

HELP I WILL GIVE 50 POINTS AND BRAINLIEST TO WHOEVER ANSWERS FIRST Graph y>1−3x.

Answers

Answer:

The last graph

Step-by-step explanation:

This is because when there is a greater than sign, the line on the graph is dotted and the shaded area is facing upwards. I try to remember that when there is a greater than sign or a greater than or equal to sign, the shaded area faces up towards the sky.

Hope this helps. Please inform me if my answer is wrong.

Answer:

The last graph is correct

Step-by-step explanation:

Hello,

First of all, you need to identify the line y = -3x + 1

This is a line so two points are enough to identify it.

-3*0+1 = 1 so (0,1) is a point of this line and

-3*1 + 1 = -2 so (1,-2) is another point of this line.

I attached a graph of this line.

Now, the inequality is y > 1-3x

It means that we are looking for the part of the plan which is (strictly) above this line.