Chocos is a dish made from wheat, sugar, and cocoa. Bertha is making a large pot of chocos for a party. Wheat(w) cost $5 per pound, sugar(s) costs $3 per pound, and cocoa(c) costs $4 per pound. She spends $48 on 12 pounds of food. She buys twice as much cocoa as sugar.

Answers

Answer 1

Answer:

The question is incomplete, complete question is;

Chocos is a dish made from wheat, suguar, and cocoa. Bertha is making a large pot of chocos for a party. Wheat (w) costs $5 per pound, sugar (s) costs $3 per pound, and cocoa (c) costs $4 per pound. She spends $48 on 12 pounds of food. She buys twice as much cocoa as sugar. How much wheat, sugar, and cocoa will she use (in pounds) in her dish?

Answer:

She uses 3 pounds of wheat, 3 pounds of sugar and 6 pounds of cocoa in her dish.

Step-by-step explanation:

Given,

Total amount of spent money = $ 48

Total quantity of ingredients = 12 pounds

Let the quantity of wheat, sugar and cocoa she buys be x, y z pounds respectively.

$\therefore x+y+z=12\ equation 1\nand\ 5x+3y+4z=48\ equation2$

And according to question, quantity of cocoa is 2 times of sugar.

$\therefore z=2y$

Now substituting the value of z in equation 1and 2, we get;

$x+y+2y=12\nx+3y=12\ equation3$

$5x+3y+4*2y=48\n5x+3y+8y=48\n5x+11y=48\ equation\ 4$

Now multiply equation 3 by 5 and then subtract equation 4 from it.

$5(x+3y)=5*12\n(5x+15y=60)-(5x+11y=48)\n4y=12\ny=(12)/(4)=3$

$\therefore z=2y=2*3=6$

And substituting the value of y in equation 3, we get;

$x+3y=12\nx+3*3=12\nx+9=12\nx=12-9=3$

Thus the amount she uses is 3 pounds of wheat, 3 pounds of sugar and 6 pounds of cocoa in her dish.

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Answers

Answer:

2/7

Step-by-step explanation:

So we multiply 3 by 2, and get 6.

Then we multiply 1 by 4, and get 4.

Next we give both terms new denominators -- 4 × 2 = 8.

So now our fractions look like this:

6/8 - 4/8

6 − 4 = 2

So the answer is:

2/8

What do you have to multply 3/8 by to get 1