Answer:
(D) p = 50.55 (Round to the nearest hundredth).
Step-by-step explanation:
Given: Right triangle SIP such that i = 54 and s = 19.
To find: Which of the following statements are true, round to the nearest hundredth.
Solution: We have given that Right triangle SIP , i = 54 and s = 19.
By the Pythagoras theorem (IP)²+(SI)² = (SP)².
Plugging the values
(19)²+(p)² = (54)².
361+(p)² =2916
On subtracting both side by 361.
(p)²+ 361 - 361 =2916 -361
(p)² = 2555
Taking square root both sides .
√(p)² = .
p = 50.547
p = 50.55 (Round to the nearest hundredth).
Therefore, (D) p = 50.55 (Round to the nearest hundredth).
56
Step-by-step explanation:
to get 56 u have to flip it then mutiplie
What is the answer please!
Answer:
5
Step-by-step explanation:
Assuming the n+9 is in the denominator, start by cross multiplying.
multiply the n+9 by 2 and 4 by 7 to form the eqution 2n+18 = 28.
subtract the 18 from both sides to form the equation 2n = 10.
divide both sides by 2 to answer n = 5.
Another method is to think how to create equivalent fractions. to have 4/n+9 equal 2/7, the 2/7 is equivalent to 4/14. that means that n+9 is equivalent to 14, because the numerator are equal to each other. if n+9 = 14, then n = 5.
b- lana wants to use the printer to print 150 pages hows long will the take her
Answer:
B = (2, -5)
Step-by-step explanation:
The problem requirements mean ...
B - A = (2/3)(C - A)
B = A + (2/3)C - A
B = (1/3)A + (2/3)C = (A +2C)/3
B = ((-6, 1) +2(6, -8))/3 = (-6+12, 1-16)/3 = (6, -15)/3
B = (2, -5)
a. segment TU
b. segment TX
c. segment WT
d. segment WV
Answer:
26
Step-by-step explanation:
hope it helped !! :))