#1. A research group interested in understanding the effect of listening to classical music on learning mathematics conducted a study. One hundred students were randomly assigned to one of two groups. The first group listened to classical music as they learned a new lesson. The second group learned the same lesson with no music playing. Both groups were tested on the new material to determine how much they learned. The results for the two groups were compared. What kind of study is this?A. This is an observational study because students were randomly assigned to groups.

B. This is an observational study because a treatment was applied to both groups.

C. This is an experiment because a treatment was applied to a group.

D. This is an experiment because students were able to choose which group to join.



#3. ......Angie, a student in an advanced statistics course, was given an algebra test and she scored 80%. Is this an accurate predictor of how well students in the algebra class will perform on the test?

A. Yes, because Angie is representative of the population in the algebra class

B. Yes, because Angie scored high on the test so it must be easy

C. No, because Angie is not representative of the population in the algebra class

D. No, because Angie scored too high on the test

Answers

Answer 1
Answer: The correct answer to the first situation would be letter C. The situation was an experiment because a treatment was applied to the group (which in this case, is the experimental group).

The correct answer to the next question would be letter C. Angie is NOT are representative of the population in the algebra class.

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PLZ HELP!! The question is attached!

Given:- KLMN is a trapezoid
- KL = MN
- LN = √(89)
- LH: altitude
- LM = 3
- KN = 13
Find: m∠LKN
See attached image.

Answers

Answer:

45 degrees

Step-by-step explanation:

If KL = MN, and LM =3 and KN = 13, then HN = 13 - (13-3)/2 = 8

LN =  sqrt(HN^2 + LH^2) -->

LN = sqrt89 sqrt(8^2 + LH^2) -->

89 = 64 + LH ^2 -->

25 = LH^2 -->

LH = 5

Because HN  = 8, HK = 13 - 8 = 5

That makes both legs equal, which makes m∠LKN = 45 degrees

The angle  m∠LKN is equal to 45 degrees.

To understand more, check below explanation.

Trapezoid :

It is given that,

KL = MN, LM =3 , KN = 13 and LN =√(89)

So that, HN = 13 - (13-3)/2 = 13 - 5 = 8

    LN =  \sqrt{(HN)^(2)+(LH)^(2)  }\n\n√(89) = \sqrt{(8)^(2)+(LH)^(2)  }\n\n89=64+(LH)^(2) \n\nLH=√(25)=5

Since,  HN  = 8. So that,  HK = 13 - 8 = 5

In a triangle, if two sides are equal. Then, opposite angle of both sides are also equal.

In triangle LKH,   LH = HK = 5 and \angle H=90

So that,     m∠LKN = 90/2 = 45 degree.

Hence, the angle  m∠LKN is equal to 45 degrees.

Learn more about the trapezoid here:

brainly.com/question/1463152

3/4 (6x + 1) - 3x = 1/4 (2x - 1)

Answers

3/4 (6x + 1) - 3x = 1/4 (2x - 1) . The purpose of this question is to solve for x.

\mathbf{x = (-4)/(13)}

Given that:

  • 3/4 (6x + 1) - 3x = 1/4 (2x - 1)

When calculating algebraic expression, we take note of integers in bracket first, then we collect the like terms in order to find the value of x.

\mathbf{(3)/(4) (6x + 1) - 3x =(1)/(4) (2x - 1) }

Let's multiply both sides by 4 to eliminate the fraction.

\mathbf{((3)/(4) * 4) (6x + 1) - 3x =((1)/(4) * 4 ) (2x - 1) }

\mathbf{(3) (6x + 1) - 3x =(1 ) (2x - 1) }

  • Open brackets;

18x + 3  - 3x = 2x - 1  

  • By rearrangement;

18x - 3x + 3 = 2x - 1

15x + 3 = 2x - 1

  • Collect like terms

15x - 2x = - 3 - 1

13x = - 4

  • Divide both sides by 13

\mathbf{(13x)/(13) = (-4)/(13)}

\mathbf{x = (-4)/(13)}

Learn more about algebraic expressions here:

brainly.com/question/11227332?referrer=searchResults

3/4*(6x+1)-3*x-(1/4*(2*x-1))=0
X=1

Which quadratic function has a leading coefficient of 2 and a constant term of –3?f(x) = 2x^3 – 3

f(x) = –3x^2 – 3x + 2

f(x) = –3x^3 + 2

f(x) = 2x^2 + 3x – 3

Answers

quadatic means 2nd degree, means highest exponent of placeholder is 2
leading coefient is the number that is in front of the highest power x
constant term is the one that doesn't have an x witht it

quadratic
2nd and last fn are quadratic

leading coefient of 2 is first and last fn

constant term is -3 for first and last fn


answer is last function

Solve these systems of equations Using the elimination method.a). 3x + y = 13 b) 6x - y = 14
x - 5y = 15 2x + y = 12





c) 3x - 4y = 22
2x + 5y = 7

Answers

a. 3x + y = 13 → 15x + 5y = 65
    x -  5y = 15 →     x -  5y = 15
                                     16x = 80
                                      16     16
                                        x = 5
                                 x - 5y = 15
                                 5 - 5y = 15
                               - 5          - 5
                                     -5y = 10
                                      -5     -5
                                        y = -2
                                 (x, y) = (5, -2)

b.    6x - y = 14
      2x + y = 12
            8x = 26
             8      8
              x = 3¹/₄
       6x - y = 14
6(3¹/₄) - y = 14
   19¹/₂ - y = 14
 - 19¹/₂       - 19¹/₂
             -y = -5¹/₂
             -1      -1
               y = 5¹/₂
        (x, y) = (3¹/₄, 5¹/₂)

c. 3x -  4y = 22 → 15x - 20y = 110
    2x + 5y =   7 →  8x + 20y =   28
                                        23x = 138
                                         23       23
                                            x = 6
                                   3x - 4y = 22
                                3(6) - 4y = 22
                                   18 - 4y = 22
                                 - 18         - 18
                                         -4y = 4
                                          -4    -4
                                            y = -1
                                     (x, y) = (6, -1)
a). 3x + y = 13 
x - 5y = 15 
multiplier equation 1 by 5
15x+5y=65
DSA
15x+5y=65
x - 5y = 15 
remaining
16x=80
x=5
5-5y=15
-5y=15-5
-5y=10
y=
10 ÷ -5
y=-2
x,y
5,-2

PLEASE HELP, BEING TIMED, WILL GIVE BRAINLIEST!!!! Mr. Romero attached a ramp to the base of a window sill so that the family cat could more easily climb onto it. The ramp is 84 inches long. The window sill is 50 inches above the floor. What is the distance from the base of the ramp to the base of the wall?

Answers

The distance from the base of the ramp to the base of the wall will be 67.5 inches.

What is the Pythagorean theorem?

Pythagorean theorem states that in the right angle triangle the hypotenuse square is equal to the square of the sum of the other two sides.

By using Pythagoras' theorem

D²  =   84²  -    50²

D   =   √   84²  -    50²

D  =  √4556

D   =  67.5 inches

Therefore the distance from the base of the ramp to the base of the wall will be 67.5 inches.

To know more about the Pythagorean theorem follow

brainly.com/question/343682

#SPJ5

Answer:

x=\sqrt{84^(2)-50^(2) } =√(7056-2500) =67.5 inches



An open box is to be made from a rectangular piece of tin by cutting 3-inch squares out of the corners and folding up the sides. The length of the piece of tin is twice the width. The volume of the box will be 60 cubic inches. Find the dimensions of the original rectangular piece of tin

Answers

Answer:

Width of the Rectangular Tin=8 inch

Length of the Rectangular Tin= 16 inch

Step-by-step explanation:

Let the Width of the Rectangle=W

The length of the piece of tin is twice the width, Length = 2W

Since Squares of 3 inch are cut from all four corners of the rectangle

Length of the box = 2W-(3+3)=(2W-6) inches

Breadth of the Box = W-(3+3)=(W-6) inches

Height = 3 inches

Volume of the box = 60 cubic inches

Now, Volume of a cuboid=lbh

3(2W-6)(W-6)=60

Divide both sides by 3

(2W-6)(W-6)=20

Expanding the brackets

(2W-6)(W-6)=20\n2W^2-12W-6W+36=20\n2W^2-18W+36-20=0\n2W^2-18W+16=0

Factorizing

2W^2-16W-2W+16=0\n2W(W-8)-2(W-8)=0\n(W-8)(2W-2)=0\nW-8=0 ,  2W-2=0\nW=8,  1

Since the Width cannot be less than 6,

Width of the Rectangular Tin=8 inch

Length= 2 X 8 = 16 inch