The product shown is a difference of squares. What is the missing constant term in the second factor?(–5x – 3)(–5x +?

Answers

Answer 1

Answer: Difference of two squares is of the form (a + b)(a - b) or vice-versa. Here, a = -5x and b = 3.
(-5x - 3)(-5x + 3)
Answer: 3

Answer 2

Answer:

Answer: (–5x – 3)(–5x +3)

Step-by-step explanation:

3 is the answer.

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What's the diameter and radius with the circumference of 40

Answers

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Scientific notation of 0.000105

Answers

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Find Four constructive odd integers whose sum is 224 what is the largest number

Answers

Final answer:

Given 4 consecutive odd numbers with a sum of 224, we can create an equation to solve for the first number (x). After calculating x = 53, we find the largest number to be 59.

Explanation:

This is a problem about consecutive odd integers, which are odd integers that follow each other successively. Let's denote the first odd integer as x, the second as x+2, the third as x+4, and the fourth as x+6. These are all odd because adding 2 to an odd number always results in the next odd number.

The question states that the sum of these four consecutive odd numbers is 224, so we can create the following equation: x + (x+2) + (x+4) + (x+6) = 224.

Simplify this equation to obtain 4x + 12 = 224. Then, solve for x by first subtracting 12 from both sides to get 4x = 212 and then dividing by 4 to get x = 53. Our highest odd number would be x+6 which equals 59.

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Final answer:

The four consecutive odd integers whose sum is 224 are 53, 55, 57, and 59. The largest of these integers is 59.

Explanation:

To find four constructive odd integers whose sum is 224, you first need to understand that consecutive odd integers follow a certain sequence, each increasing by 2 from the previous one. Let's label the first consecutive odd integer as 'n'. So, the four consecutive numbers will be: n, n + 2, n + 4, n + 6.

According to the problem, the sum of these four numbers equals 224:
n + (n+2) + (n+4) + (n+6) = 224.
Solve this equation to find the value of 'n'. You'll get n = 52. Hence, the numbers are 52, 54, 56, 58.

Since we are looking for odd numbers, let's start with 53 (the first odd number greater than 52) and proceed: 53, 55, 57, 59. And these four numbers do sum up to 224. Therefore, the largest number in this series is 59, our final answer.

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(3-2x) divided by (1 divided by x+5) multiplied by 8

Answers

Answer: 8(3-2x)(x+5), -16x^2-56+120, x=-5, or x=3/2.

Step-by-step explanation:

First convert the multi fraction into multiplication: 8(3-2x)(x+5)

Then simplify: -16x^2-56+120

If you want, you can solve for x, which gets you x=-5, or x=3/2.

I hope this helps! :P

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