BIOLOGY HIGH SCHOOL

Which of these processes removes carbon from the atmosphere?A) combustion
B) excretion
C) photosynthesis
D) respiration

Answers

Answer 1
Answer: c because plants  and trees are equal to photosynthesis and they take in carbon and lets out oxygen.
Answer 2
Answer:

Final answer:

Photosynthesis is the process that removes carbon from the atmosphere.

Explanation:

The process that removes carbon from the atmosphere is photosynthesis. During photosynthesis, plants take in carbon dioxide from the atmosphere along with water and sunlight, and convert them into glucose and oxygen. Carbon is stored in plants' tissues and also released back into the atmosphere when plants respire or decompose.

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Protists are a group of organisms that are characterized as eukaryotes (they have cells with nuclei) that are neither plants nor animals nor fungi. They are very diverse, and there are many hypotheses about their classification. The cladogram for protists is constantly changing and, sometimes, there are opposite hypotheses that both have data to support them. What is the implication of a changing hypothesis? It is acceptable because data are still being collected. It is acceptable because everything in science should always change. It is not acceptable because the correct answer needs to be found. It is not acceptable because science never changes.

Answers

It is acceptable because data are still being collected.

Protists obtain food in 3 ways. They produce their own organic molecules, ingest, and absorb.  Ingestive protists ingest food, or engulf bacteria. These protists extend their cell wall and cell membrane forming a food vacuole around the food item. Inside the food vacuole, enzymes digest the food. Absorptive protists on the other hand, absorb food molecules  across their cell membrane which takes place through diffusion. Absorptive protists play a key role in decomposition. They are considered as important decomposers. Major producers  like photosynthetic protists  use light energy to manufacture  their own food. 

The hypothesis is constantly changed because data are still being collected, and due to this, hypotheses are accepted.

Further Explanation:

Protists are considered as first eukaryotes to be identified. They are different from prokaryotes because they have a well-defined cytoskeleton. They consist of different organelles and nuclear envelope. Protists have a varied range of cell surfaces. They can easily stand in an unfavorable environment due to the presence of outer covering. They have flagella for the locomotion. They can either be autotroph and heterotrophs. This is because they ingest food particles by pulling them in the intracellular vesicles referred to as phagosomes or vacuoles. They can produce by means of asexual and also by the sexual method. Protista that produces sexually undergoes meiosis, which is a reductional division resulting in the formation of haploid cells.The progeny that are produced by the union of two haploid cells allowed the formation of new allelic combinations by genetic recombination.  

Cladistics is a process of classifying organisms depends upon their shared traits. The cladogram for Protista is continuously altered, and, at times, there are contradictory theories that together have data to support the hypothesis. It is suitable because facts are still being collected.

Learn more:

1. Learn more about the mitosis brainly.com/question/6462270

2. Learn more about the menstrual cycle brainly.com/question/723944

3. Learn more about the meiosis brainly.com/question/94813

Answer Details:

Grade: High School

Subject: Health

Chapter: Protists

Keywords:

Protists, phagosomes, vacuole, sexual method, asexual, collected, allelic combination, genetic recombination, progeny, hypothesis, cladogram.

A woman who has blood type A positive has a daughter who is type O positive and a son who is type B negative. Rh positive is a trait that shows simple dominance over Rh negative and is designated by the alleles R and r, respectively. A third gene for the MN blood group has codominant alleles M and N. Which of the following is a possible phenotype for the father?
A) A negative
B) O negative
C) B positive
D) AB negative
E) impossible to determine

Answers

The answer is C) B positive.

A mother has either AA or AO genotype. Since her daughter has OO genotype, the one O allele is from a father and one is from the mother.  Thus, mother must have allele O. So mother's genotype is AO.

A mother with AO genotype will pass to her son either A or O allele. Since son is type B negative, it could inherit from mother only O allele. Son's genotype is BO. This means that he inherited from the father B allele.

Father has either BO or BB genotype. Since his daughter has OO genotype, she must inherit one O allele from the father. Thus, the father has BO genotype.

Talking of Rh, her son is type B negative. A negative Rh phenotype contains both recessive alleles r, so the mother must have allele r (she is either Rh+ heterozygous, or Rh- homozygous). The same is with father - he  is either Rh+ heterozygous, or Rh- homozygous.

Differenciate between continental crust and oceanic crust

Answers

continential crust is land and oceanic crust is in the water

the inner mitochondrial membrane is actually a series of discrete, flattened, membrane-enclosed compartments called cristae, similar to what is seen in the golgi apparatus. true false

Answers

True. The given statement 'the inner mitochondrial membrane is actually a series of discrete, flattened, membrane-enclosed compartments called cristae, similar to what is seen in the golgi apparatus' is correct.

The inner mitochondrial membrane is highly folded, forming a series of flattened membrane-enclosed compartments calledcristae, which project into the matrix of the mitochondrion.

These cristae significantly increase the inner membrane's surface area, which is important for the efficient production of ATP by the electron transport chain and ATP synthase located on the cristae membranes.

The analogy to the Golgi apparatus is appropriate because both the cristae and the Golgi apparatus are membrane-bound compartments involved in modifying and transporting proteins and lipids.

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Number the events from earliest (1) to most recent (6) to outline the development of the cell theory.Anton van Leeuwenhoek observed small organisms he called "animalcules."


Robert Hooke was the first to use the word "cell."


Matthias Schleiden theorized that plants are made of cells.


Theodor Schwann theorized that animals are made of cells.


Hans and Zacharias Janssen created the first microscope.


Rudolf Virchow theorized that cells come from other pre-existing cells.

Answers

Answer:

The chronological order of events ealiest to most recent (1-6) are given below:

Explanation:

1. Hans and Zacharias Janssen created the first microscope in the year 1590.

2. Robert Hooke was the first to use the word "cell." In the year 1665

3. Anton van Leeuwenhoek observed small organisms he called "animalcules." In the year 1674  

4. Matthias Schleiden theorized that plants are made of cells in the year 1838

5. Theodor Schwann theorized that animals are made of cells in the year 1839

6. Rudolf Virchow theorized that cells come from other pre-existing cells in the year 1855

Answer:

The chronological order of events ealiest to most recent (1-6) are given below:

Explanation:

1. Hans and Zacharias Janssen created the first microscope in the year 1590.

2. Robert Hooke was the first to use the word "cell." In the year 1665

3. Anton van Leeuwenhoek observed small organisms he called "animalcules." In the year 1674  

4. Matthias Schleiden theorized that plants are made of cells in the year 1838

5. Theodor Schwann theorized that animals are made of cells in the year 1839

6. Rudolf Virchow theorized that cells come from other pre-existing cells in the year 1855

How many moles of oxygen are needed to burn 1.33 moles of methyl alcohol (CH3OH)?2CH3OH + 3O2 2CO2 + 4H2O

Answers

Well, it takes 3 moles of oxygen to completely burn 2 moles of methyl... 

So for every 2 moles of methyl, you need 1.5 times as much oxygen (3 divided by 2) 

That makes your ratio 1 : 1.5 

You need 1.33 moles of methyl so you multiply both sides of the ratio by 1.33 = 1.33 : 1.995 

 1.995 moles of oxygen are needed

Answer:

A.  0.877 moles

B.  0.997 moles

C.  1.330 moles

D.  1.995 moles

E.  2.660 moles
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