Answer:
Work being done on the object = 766.04J
Explanation:
Work done by a force is calculated by finding dot product of force and displacement.
W = F . s
F = 25 N
s = 50 m
θ = 40.0°
W = F . s = Fs cosθ = 25 x 40 x cos 40 = 766.04J
Work being done on the object = 766.04J
B) tanks that hold less than 200 gallons.
C) farm and residential tanks that hold 2,000 gallons or less of motor fuel used for noncommercial purposes.
D) all of these.
Some types of storage tanks are exempt from the federal regulations on USTs, including: A) tanks that store heating oil burned on the premises.
Underground Storage Tank systems are tanks along with the underground piping that has at least 10% of their total volume underground.
Some of the storage tanks that are exempt from the federal regulations on USTs are;
Learn more about Underground Storage Tank systems here:
The federal UST regulations typically do not cover tanks that store heating oil used on site, tanks that hold less than 200 gallons, and farm and residential tanks that hold 2,000 gallons or less of motor fuel for noncommercial uses.
The question pertains to certain types of storage tanks that are exempt from federal regulations called USTs (Underground Storage Tanks). These tanks are used to store regulated substances, typically petroleum and hazardous substance. However, not all tanks fall under these regulations. For instance, tanks that store heating oil used on the premises where it is stored, tanks that hold less than 200 gallons, and farm and residential tanks that hold 2,000 gallons or less of motor fuel for noncommercial uses, are not governed by these federal UST regulations. Hence, the correct answer is D) all of these.
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Answer:
radio waves microwaves x-rays gamma rays
Explanation
(Physics question)
which substance is uniquely a product of incomplete combustion of a fossil fuel?
carbon monoxide
A. 440.00 Hz
B. 493.88 Hz
C. 523.25 Hz
D. 587.33 Hz
E. 659.26 Hz
F. 698.46 Hz
G. 783.99 Hz
Answer:
C
Explanation:
Given that a note has a wavelength of 0.65551 m. If the speed of sound is 343.00 m/s, the pitch of the note is the same as the frequency.
Sound Velocity = product of frequency and wavelength.
Substitute wave speed and wavelength into the formula
343 = f × 0.65551
Make f the subject of formula
F = 343 / 0.65551
F = 523.58 Henz
Therefore, the pitch of the note is 523.52 Hz approximately
The correct answer is option C