the present of decrease is around 1.92%
Help please..??
The speed of the boat in still water will be 30 miles per hour and the speed of the current will be 6 miles per hour.
The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.
Let the speed of the boat in still water be x and the speed of water be y.
A boat traveled 504 miles downstream and back. The trip downstream took 14 hours. Then the equation will be
x + y = 504 / 14
x + y = 36 ...1
The trip back took 21 hours. Then the equation will be
x - y = 504 / 21
x - y = 24 ...2
Add equations 1 and 2, then the value of x will be
2x = 36 + 24
2x = 60
x = 30 miles per hour
Then the value of y will be
30 - y = 24
y = 6 miles per hour
The speed of the boat in still water will be 30 miles per hour and the speed of the current will be 6 miles per hour.
More about the solution of the equation link is given below.
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Answer:
The speed of the boat in still water is 30 mph, and the speed of the current is 6 mph.
Step-by-step explanation:
Let's say b is the speed of the boat in still water, and c is the speed of the current.
Distance = rate × time
Going downstream:
504 = (b + c) × 14
36 = b + c
Going upstream:
504 = (b − c) × 21
24 = b − c
Two equations, two variables. Solve with substitution or elimination. To use elimination, add the equations together.
60 = 2b
b = 30
Plug into any equation to find c.
36 = b + c
36 = 30 + c
c = 6
The speed of the boat in still water is 30 mph, and the speed of the current is 6 mph.