If the sixth term of a sequence is 128 and the common ratio is 2, then what is the first term?1
2
4

Answers

Answer 1
Answer:

Answer: The first term of the sequence is 4.

Step-by-step explanation:

Let a be the first term of the sequence,

Here, the common ratio of the sequence is 2,

Thus, the sequence is,

a, 2a, 4a, 8a, 16a, 32a, .............., so on,...

Since, the sixth term of the sequence = 32a

According to the question,

32 a = 128

⇒ a = 4

Thus, the first term of the sequence is 4.

Answer 2
Answer: Hello,

Answer C: 4

u_(6)=128
u_(5)=64
u_(4)=32
u_(3)=16
u_(2)=8
u_(1)=4









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What is the sum of a number and 37?

Answers

Answer: 18 and 19

Step-by-step explanation:

If you are wondering what two numbers equal 37, it would be 18 and 19. However, if this is not what you were asking, please elaborate and I will answer.

Deanna collected data on the favorite sports of the students of two grades. The table shows the relative frequencies of rows for the data collected: Favorite Sport Swimming Running Volleyball Row totals Grade 8 0. 14 0. 18 0. 22 0. 54 Grade 9 0. 17 0. 24 0. 05 0. 46 Column totals 0. 31 0. 42 0. 27 1 Based on the data, which statement is most likely correct? In Grade 8, 14 students liked swimming. In Grade 9, 31% of students liked swimming. In Grade 8, 22% of students liked volleyball. In Grade 9, 5 students liked volleyball.

Answers

Answer:

In Grade 8, 22% of students liked volleyball.

Step-by-step explanation:

Given:

The table representing the relative frequencies of different sports in different grades among the students.

                          Swimming      Running    Volleyball                   Row totals

Grade 8                        0.14           0.18         0.22                          0.54

Grade 9                        0.17           0.24        0.05                          0.46

Column totals              0.31           0.42        0.27                             1

Relative frequency gives the ratio of the number of quantities of a particular kind and the total number of quantities.

From the above table, we can conclude the following points:

Grade 8:

14% liked swimming, 18% liked running and 22% liked volleyball. So, a total of 54% students liked playing sports.

Grade 9:

17% liked swimming, 24% liked running and 5% liked volleyball. So, a total of 46% students liked playing sports.

Combining students of grade 8 and 9:

31% liked swimming, 42% liked running and 27% liked volleyball.

From all the options available, we observe that, third option is only correct.

In Grade 8, 22% of students liked volleyball.

A quadrilateral PQRS is inscribed in a circle, as shown belowWhat is the measure of arc PQR?
190
265
275
340

Answers

Answer:

Option A is correct.

The measure of Arc PQR is 190 degree

Step-by-step explanation:

Given a cyclic quadrilateral PQRS is inscribed in a circle as shown in figure.

Given: \angle PQR = 85^(\circ)

An intercepted arc measures twice the intercepted angle.

The intercepted angle in the given figure is Arc PQR =2 \cdot \angle PSR                    ......[1]

First find the \angle PSR;

A quadrilateral is cyclic if and only if opposite angles sum to 180°.

then;

\angle PQR+\angle PSR =180^(\circ)

Substitute the value of \angle PQR = 85^(\circ) in above equation we get;

85^(\circ)+\angle PSR =180^(\circ)

Simplify:

\angle PSR =180^(\circ)-85^(\circ) =95^(\circ)

Now; to find the measure of arc PQR ;

[1] ⇒ Arc PQR =2 \cdot \angle PSR = 2 \cdot 95 =190^(\circ)

Therefore, the measure of arc PQR is 190 degree.



Hello,

mes Angle PSR= 180°-85°=95°
mes Arc PQR= 2* 95°=190°

Answer A

suppose a and b give the population of two states where a > b. compare expressions and tell which of the given pair is greater or if the expressions are equal. 1. b/a+b and 0.52. a+13c and b+13c is the population of a third state3. a-b/2 and a-b/24. a+b and 2b5. 5(a+b) and (a+b)5

Answers

Answer:

We are given that a>b.

1)(b)/(a+b) and 0.5

we know that a>b

⇒ a+b>b+b

⇒a+b>2b

⇒  (b)/(a+b)<(1)/(2)=0.5

2) a+13c and b+13c is the population of a third state.

so, a+13c>b+13c

3) both the given expressions are same i.e.

(a-b)/(2)

4) a+b and 2b

we know that a>b

⇒ a+b>b+b

a+b>2b.

5) both the given expressions are same i.e. 5(a+b) or (a+b)5 since we have to multiply (a+b) and 5.



Find b for the following right angled triange where a=5 and c=13

Answers

You would use the Pythagorean there on which is a^2+b^2=c^2, from there you plug int what they gave you and solve for b, and b=12

12. The square and rectangle shown below have the same perimeter length Show that the length of the rectangle (3x + 1) centimetres

Answers

Lets call the perimeter P and the length of the rectangle l.  The first figure is a square with side length 2x + 2 so P = 4(2x + 2) = 8x + 8.  For the rectangle, P = 2l + 2(x + 3) = 2l + 2x + 6.  These values both equal P so they must equal each other.  8x + 8 = 2l + 2x + 6.  Now we have to solve for l.  

8x + 8 = 2l + 2x + 6  
8x + 2 = 2l + 2x
6x + 2 = 2l
3x + 1 = l