Answer:
2x+2y=4
Step-by-step explanation:
Taking into account the definition of maximum, minimum and vertex of a quadratic function, it takes 12.5 seconds for the projectile to reach maximum height.
A quadratic function is defined in the form:
y= f (x) = ax² + bx + c
Every quadratic function has a maximum or a minimum, which is the vertex of the parabola. If the parabola has an upward concavity, the vertex corresponds to a minimum of the function; whereas if the parabola has concavity downwards, the vertex will be a maximum.
That is, if the coefficient a is positive the parabola is concave and the vertex will be a minimum of the function, while if a is negative the parabola will be convex and the vertex is a maximum.
The maximum or minimum is reached in
The maximum or minimum value of y is obtained by evaluating the function at xv, this is, f (xv).
In this case, the function is:
h(t)= -16t² + 400t
where t is the time in seconds
Being a = -16 and b = 400, the value of a is negative, so the vertex will be the maximum.
You want to know the time it takes for the projectile to reach the maximum height, that is, the maximum in t. That is, you must calculate t using the expression:
So:
Solving:
t= 12.5 seconds
It takes 12.5 seconds for the projectile to reach maximum height.
Learn more about cuadratic function with this examples:
Answer:
You can find the answer by using the formula x=-b/2a
Step-by-step explanation:
Remember the maximum height will be at the vertex. The x value of the vertex is your time, so use x=-b/2a. Then if it had also asked what the height was, you would plug that answer into your equation to find the y value of the vertex. Pretty sure your teacher is just asking you to find the x though:)
Answer:
Step-by-step explanation:
we know that
The probability of an event is the ratio of the size of the event space to the size of the sample space.
The size of the sample space is the total number of possible outcomes
The event space is the number of outcomes in the event you are interested in.
Let
x---------> size of the event space
y-------> size of the sample space
In this problem we have
(because is only one number to think)
(there are numbers between and )
substitute