The charges of ions that Sulfur (S), Potassium (K), Boron (B), Iodine (I), and Bromine (Br) are most likely to form are -2, +1, +3, -1, and -1, respectively. This is determined by their positions on the periodic table.
The charge of an ion that a certain atom is most likely to form is dependent on its position on the periodic table. Elements on the left side of the periodic table (like potassium) tend to lose electrons and form positive ions, while elements on the right side (like sulfur, iodine, bromine) tend to gain electrons and form negative ions.
The charge of a sulfur (S) ion is usually -2 because sulfur, being in Group 16, tends to gain two electrons to reach a stable electronic configuration. The charge of a potassium (K) ion is usually +1. This is because potassium, which is in Group 1, usually loses one electron to achieve a stable electron configuration. The charge of a boron (B) ion is usually +3 because boron, being in Group 13, tends to lose three electrons in order to reach stability. The charge of an iodine (I) ion is usually -1 because iodine, which is in Group 17, tends to gain one electron to reach stability. Lastly, the charge of a bromine (Br) ion is usually -1, because bromine, also in Group 17, tends to gain one electron to attain a stable electronic configuration.
#SPJ6
Answer:
Sulfur (S) is
-2
Potassium (K) is +1
Boron (B) is +3
Iodine (I) is -1
Bromine (Br) is -1
Explanation:
Answer: I believe the answer is 112.
Explanation:
b. The oxygen atom of a water molecule is more electronegative than a hydrogen atom.
c. The hydrogen atoms of a water molecule have a partial negative charge.
d. The hydrogen atom of one water molecule is attracted to the oxygen atom of a different water molecule.
e. The hydrogen atom of a water molecule is attracted to the oxygen atom of the same water molecule.
f. The oxygen atom of a water molecule has a partial positive charge.
g The oxygen atom of a water molecule has a partial negative charge.
Answer:
The answer to your question is below
Explanation:
a. The hydrogen atoms of a water molecule have a partial positive charge. True.
b. The oxygen atom of a water molecule is more electronegative than a hydrogen atom. True
c. The hydrogen atoms of a water molecule have a partial negative charge. False
d. The hydrogen atom of one water molecule is attracted to the oxygen atom of a different water molecule. True
e. The hydrogen atom of a water molecule is attracted to the oxygen atom of the same water molecule. False,
f. The oxygen atom of a water molecule has a partial positive charge. True
g The oxygen atom of a water molecule has a partial negative charge. True
B. 0.20 m FeI3
C. 0.20 m K2SO4
D. 0.20 m C2H5OH
Answer:- D. 0.20 m
Explanations:- When a on volatile solute is added to a solvent then the boiling point of the solution increases(elevated) and we call it elevation in boiling point.
Elevation in boiling point is directly proportional to the molality of the solution and the Van't Hoff factor "i" which is the number of ions we get on dissociation.
The equation is written as:
where is the boiling point elevation constant.
We have all the aqueous solutions, so the boiling point elevation constant value will remain same for all of them. The molality for all the solutions is also same. So, elevation in boiling point will depend only on the value of Van't Hoff factor.
Lower is the value of "i", lower will be the boiling point and vice versa.
The question asks, which aqueous solution has the lowest boiling point. So, we nede to choose the one with the lowest value of "i".
i = 3
i = 4
i = 3
is a covalent molecule and so it does not dissociate to give the ions and hence the value of "i" for this is 1.
Comparing the "i" values for all the solutions, the least value is for ethyl alcohol means the boiling point of 0.20 m ethyl alcohol solution will be lowest.
So, the correct answer is D. 0.20 m .