Find the simplified form of (t^4/10y^4)^-4
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Related Questions
Shanna attends school for 1 week longer than 3/4 of the year. How many weeks in a year dies Shanna attend school ?
Luis skates 2/3 mile from his home to school. isabella skates 2/4 mile to get to school. who skates farther?
Which conjunction or disjunction is equivalent to |t – 7| > 12?A. t – 7 > 12 or t – 7 < –12B. t – 7 < 12 and t – 7 > –12C. t – 7 < 12 or t – 7 > –12D. t – 7 > 12 and t – 7 < –12
Each month Allison gets a $15 allowance and earns $100 working at the theater. She uses the expression 15x+100y to keep track of her earnings Part A Part B Part C
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Whole numbers are numbers that begin with 0 and go on indefinitely.
Examples of whole numbers.
56
642,000
983
1,000,001
982,344
For exemple: 1, 2, 3, 10, 123, 654, 9988, 10100, 1234567890.
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If the center of the circle is at (h,k)
r² = (h - 0)² + (k - 0)²
r² = (h - 6)² + (k - 0)²
r² = (h - 6)² + (k - 4)²
Equating the equations
h² + k² = (h - 6)² + k²
h = 3
(h - 6)² + k² = (h - 6)² + (k - 4)²
k = 2
Therefore, the center of the circle is at (3,2).
Give your answer in standard form.
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Well, technically, you've only told us the time to travel across
our galaxy, so we don't have enough information to calculate
anything about its length.
Fortunately, some of us are vaguely aware that our galaxy is
roughly round, at least in its plane. So "across" means its diameter,
and that's the same in any direction through the center.
Relieved, we can now proceed to calculate:
(3 x 10⁸ meter/sec) x (8.64 x 10⁴ sec/day)
x (3.65 x 10² day/yr) x (10⁵ years)
= (3 x 8.64 x 3.65 x 10¹⁹) meters
= 94.608 x 10¹⁹ meters
= 946,080,000,000,000,000,000 meters
(about 587,867,000,000,000,000,000 miles) .
2) x³-2x²-19x+20
3) x³-2x²-11x+20
4) x³-8x²-11x+20
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B. 1
C. 32,432,400
D. 1,307,674,368,000
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3x+2y=14
2x-4y=4
6x+4y=28
2x-4y=4
8x = 32
x = 4
2y = 14 - 12 = 2
y = 1
(x , y) = (4 , 1)
Question:How can check your solution by writing the system as a matrix equation and using the inverse matrix?.
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2 −4] = (14
4) The left side can be called your "A" matrix. I gave you the idea so that you may continue with it. Hope this can help
Final answer:
To check the solution, represent the system of equations as a matrix equation, find the inverse of the coefficient matrix, and multiply both sides of the equation by the inverse.
Explanation:
To check the solution by writing the system as a matrix equation and using the inverse matrix, we need to represent the system of equations as a matrix equation. Let's consider the given system of equations:
3x + 2y = 14
2x - 4y = 4
To do this, we can write the coefficients and constants of the system of equations as matrices:
[3 2] [x] = [14]
[2 -4] [y] = [4]
Now, we can write the system of equations as a matrix equation: AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the constant matrix.
Next, we need to find the inverse of matrix A. If the inverse exists, we can multiply both sides of the matrix equation by the inverse of A to find the solution for X.
If we find the inverse of A and multiply both sides of the equation by the inverse, we get:
X = A-1B
Substituting the values of A-1 and B, we can find X, which represents the solution to the system of equations. Therefore, we can check our solution by writing the system as a matrix equation and using the inverse matrix.
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