MATHEMATICS HIGH SCHOOL

a marching band requires a tuba player to begin at the 50 yard line of a football field perpendicular to the 40 yard line. He then makes a 30 degree turn and marches at a diagonal back to the 50 yard line.Once he reaches the 50 yard line he must march forward until; he reaches his original starting position.If the tuba player travels 18 invhes with each marching pace how many paces must he take to complete the routine?

Answers

Answer 1

Answer:

20/3 paces must he take to complete the routine.

How to find the steps he must take to complete the routine?

The marching band begins at the 50-yard line of a football field and marches perpendicular to the 40-yard line.

Hence,

So when the tuba players travel 18 inches with each marching pace, the paces are:

50+30+40 / 18 = 20 / 3

So, the answer is 20 / 3 paces.

Here, Distance divided by speed equals steps.

Learn more about problem-solving here: brainly.com/question/13818690

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Answer 2

Answer: well yes, i took 50, 40, 18 and added two 50. I then got 238 as the answer but honestly math is like my worse subject. I tried looking like examples on how to do it and in one of my math books but this what i got. I really hope i helped tho :)

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give two examples of items that weigh less than 1 ounce and two examples of items that weigh more than 1 ton

Answers

under an ounce- paper, feather
more than a ton- Elephant, car

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each student can choose two electives. Which expression represents the probability that a student chooses an art elective and a history elective?

Answers

Answer:

$(^3C_1* ^4C_1)/(^(12)C_2)$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1* ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^(12)C_2$

Hence, the probability that a student chooses an art elective and a history elective = $\frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}$

$=(^3C_1* ^4C_1)/(^(12)C_2)$

Which is the required expression.

Answer: Hello!

we have:

3 art electives

4 history electives

5 computer electives

which adds to a total of 12.

If the selection is random, each elective has the same probability.

The probability of selecting an art electives is the quotient between the number of art electives and the total number of electives:

3/12

suppose that this event is true, now we need to see the probability of choosing also a history elective;

We do the same process as before, we have 4 history electives and, because we already selected 1 in the previous step, we have a total of 11 electives:

the probability now is 4/11.

Now we want to calculate the joint probability of bot events is equal to the product of their probabilities; this is:

p= (3/12)*(4/12) = (4*3)/(11*12) = 12/(11*12) = 1/11

But there is also the case where the selection is in the other order (first history and second art) so the probability is equal to

2*1/11 = 2/11

36x^3a+45xa^2=9xa( ) complete the statement.

Answers

9xa is the common factor.

You can complete the statement by dividing the two terms of the expression of the left side by 9xa, and you will get:

36x^3a + 45xa^2 = 9xa ( 4x^2 + 5a)

Which polynomial function f(x) has a leading coefficient of 1, roots –4, 2, and 9 with multiplicity 1, and root –5 with multiplicity 3?f(x) = 3(x + 5)(x + 4)(x – 2)(x – 9)
f(x) = 3(x – 5)(x – 4)(x + 2)(x + 9)
f(x) = (x + 5)(x + 5)(x + 5)(x + 4)(x – 2)(x – 9)
f(x) = (x – 5)(x – 5)(x – 5)(x – 4)(x + 2)(x + 9)

Answers

Answer:

The expression for f(x) is:

f(x) = (x+5)(x+5)(x+5)(x+4)(x-2)(x-9)

Step-by-step explanation:

We know that for any polynomial equation with roots:

$a_1,a_2,a_3,...$ with multiplicity:

$m_1,m_2,...$

the equation for the polynomial is given by:

$f(x)=(x-a_1)^(m_1)(x-a_2)^(m_2)......$

if the leading coefficient is negative we may take '-' sign in the starting of the expression.

Here we are given that :

f(x) has a leading coefficient of 1, roots –4, 2, and 9 with multiplicity 1, and root –5 with multiplicity 3

Hence, f(x) is given by:

$f(x)=(x-(-4))^(1)(x-2)^(1)(x-9)^(1)(x-(-5))^(3)\n\n\ni.e.\n\n\nf(x)=(x+4)(x-2)(x-9)(x+5)^3\n\n\nf(x)=(x+5)(x+5)(x+5)(x+4)(x-2)(x-9)$

Hence, the expression for f(x) is:

$f(x)=(x+5)(x+5)(x+5)(x+4)(x-2)(x-9)$

"polynomial function f(x) has a leading coefficient of 1"

So because of that, we can eliminate A and B.

Now we have "root –5 with multiplicity 3"

That's just product of three factors (x+5)

So D is wrong.

We are left with the only possible correct option C.

60.34 to the nearest tenth a second

Answers

The answer is 60.3 because the number after is not five or higher to be rounded up so it stays the same.

What is the equation of a line that is perpendicular to a line with a slope of 2 and passesthrough the point (-2, 0)?

Answers

To find the equation of a perpendicular line, you first need to find the negative reciprocal of the slope given. The slope is -1/3, so the slope of the perpendicular line will be 3

Now we just need to find the y intercept using the point (3, 2) and you can plug the coordinates in and then solve for b. Let's see what that looks like.

y=3x+b

2=3*(3)+b

2=9+b

-7=b So now we know the y-intercept and slope. We just put them together now

y=3x-7

Look at the broswer my friend you can do it

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Can you guys help me with this math please??I will give Brainliest!!