we know that
To Round a number
a) Decide which is the last digit to keep
b) Leave it the same if the next digit is less than (this is called rounding down)
c) But increase it by if the next digit is or more (this is called rounding up)
In this problem we have
We want to keep the digit
The next digit is which is less than , so no change is needed to
therefore
the answer is
1. Two consecutive integers means that the values are whole numbers and they are located right after the other (eg. 2, 3).
Now, let us call the smaller value x. The consecutive value will be one greater than x, thus the larger value may be written as x + 1.
2. We know that the product of the two values is 420. Given that the smaller value is x and the larger value is x + 1, we can write this as:
x(x + 1) = 420
3. Now we can expand to get:
x^(2) + x = 420
4. Now subtract 420 from both sides to get:
x^(2) + x - 420 = 0
Therefor, the constant of the quadratic expression is -420.
Answer:
y/2
Step-by-step explanation:
(x+3)/3 = (y+2)/2
x/3 + 1 = (y+2)/2
x/3 = (y+2)/2 – 1
= (y+2-2)/2
= y/2