Answer is "0.05 mol".
Explanation;
We can do calculation by using a simple formula as
n = m/M
Where, n is the number of moles of the substance (mol), m is the mass of the substance (g) and M is the molar mass of the substance (g/mol).
Here,
n = ?
m = 2.80 g
M = 56.08 g/mol
By substitution,
n = 2.80 g /56.08 g/mol
n = 0.0499 mol ≈ 0.05 mol
the reaction between aqueous solutions of cobalt(III) nitrate and sodium hydroxide to form aqueous sodium nitrate and solid cobalt(III) hydroxide.
the reaction between solid zinc and aqueous hydrochloric acid in a single replacement reaction.
classify the reactions in (a) and (b).
Synthesis Reaction
6Li(s) + N₂(g) ⇒ 2Li₃N(s)
Double Replacement Reaction
Co(NO₃)₃(aq) + 3NaOH(aq) ⇒ 3NaNO₃(aq) + Co(OH)₃(s)
Zn(s) + 2HCl(aq) ⇒ ZnCl₂(aq) + H₂(g)
To learn more about double replacement reaction, refer
#SPJ2
Taking into account the reaction stoichiometry, 51.84 grams of HCl is required to react completely with 12.8 g of aluminum to produce aluminum chloride and hydrogen gas.
In first place, the balanced reaction is:
2 Al + 6 HCl → 2 AlCl₃ + 3 H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The molar mass of the compounds is:
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
The following rule of three can be applied: If by reaction stoichiometry 54 grams of Al react with 218.7 grams of HCl, 12.8 grams of Al react with how much mass of HCl?
mass of HCl= 51.84 grams
Finally, 51.84 grams of HCl is required to react completely with 12.8 g of aluminum to produce aluminum chloride and hydrogen gas.
Learn more about the reaction stoichiometry:
B) polar covalent
C) ionic
D) metallic
(2) at the cathode in an electrolytic cell and at the anode in a voltaic cell
(3) at the anode in both an electrolytic cell and a voltaic cell
(4) at the anode in an electrolytic cell and at the cathode in a voltaic cell
Answer : The correct option is, (3) at the anode in both an electrolytic cell and a voltaic cell.
Explanation :
As we know that there are two types of cell which are, electrolytic cell and electrochemical cell or galvanic cell.
Electrolytic cell : It is defined as the cell in which the chemical reaction occurs by passing of the current from external source.
In this electrolytic cell, the oxidation occurs at anode which is a positive electrode and reduction occurs at cathode which is a negative electrode.
Electrochemical cell : It is defined as the cell in which the chemical reaction occurs with the production of electric potential difference between the two electrodes. It is also known as voltaic cell.
In this cell, the oxidation occurs at anode which is a negative electrode and reduction occurs at cathode which is a positive electrode.
From this we conclude that, the oxidation occurs at the anode in both an electrolytic cell and a voltaic cell.
Hence, the correct option is, (3) at the anode in both an electrolytic cell and a voltaic cell.
Answer: A is correct
Explanation: sorry if its wrong