D. CIF3
got it correct on test <3
2. ClO3-
3. ClO2-
4. ClO-
Answer:
4 ClO-
Explanation:
Bond length ∝ 1/ Bond order
Bond order of ClO − =1,
Bond order of ClO 2− =1.5,
Bond order of ClO 3− =1.66 ,
Bond order of ClO 4− =1.75.
Thus the order of bond length is
ClO 4− <ClO3− <ClO2−
<ClO −
Answer:
3,495.02
Explanation: TRY THAT FOR AN ANSWER
The density of Argon gas at a pressure of 753 mmHg and a temperature of 35 °C is equal to 1.59 g/L.
The state of a quantity of gas is calculated by its pressure, volume, and temperature. The ideal gas law can be explained as the product of the volume and pressure of gas is equal to the multiplication of the universal gas constant and absolute temperature.
The mathematical equation for an ideal gas can be written as follows:
PV = nRT
PV =(m/M) RT
PM/RT = m/V
d = PM/RT
Where n is the moles of gas, T is the temperature of the gas, V is the volume of the gas, and R is the gas constant.
Given, the temperature of argon gas, T = 35 °C = 35 +273 = 308 K
The pressure of the argon gas, P = 753 mmHg = 1.01 atm
The molar mass of the Argon gas, M = 40 g/mol
Substitute V, R, P, and T in the ideal gas equation, we get:
The density of Argon gas, d = PM/RT
d= 1.01 ×40/(0.082 × 308)
d = 1.59 g/L
Therefore, the density of Ar gas is 1.59 g/L.
Learn more about ideal gas equation, here:
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