x = 3
y = 5
3x^2 – 2y
= 3(3)^2 - 2(5)
=> 3(9) - 10 = 17
And 2x^2– 3y
=> 2(3)^2 - 3(5)
=> 2(9) - 15 = 3
17 - 3 = 14
This gives 3x^2 – 2y exceeding 2x^2– 3y by 17 - 3 = 14
Answer: The distance between 15 yards to 18 yards is 3 yards.
Step-by-step explanation:
Answer:
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Step-by-step explanation:
msade rekfflg.g
O s(x) × t(6)
Os(6) × t(6)
O 6 × S(x) × t(x)
Hello!
Answer:
Step-by-step explanation:
→ We want an expression wich is equivalent with (st)(6).
→ Let's develop this expression:
Conclusion:
So an equivalent expression of (st)(6) is s((t)(6)).
The term (st)(6) in mathematics signifies that 's' and 't' are multiplied together, and the result is then multiplied by '6'. Using the associative property of multiplication, the equivalent expression is s(t(6)).
In mathematics, the expression (st)(6) signifies multiplication. The presence of parentheses indicates that the variables 's' and 't' should be multiplied together first, and then the product should be multiplied by '6'. This principle is known as the associative property of multiplication, which states that the way in which factors are grouped in a multiplication problem does not change the product. Therefore, the equivalent expression to (st)(6) is s(t(6)), which means 's' multiplied by the product of 't' and '6'.
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Answer:
The volume of water that remains on the cone is 523.6 cm³
Step-by-step explanation:
To solve this problem you have to keep in mind the formules that describes the volume of a cone and the volume of a sphere.
Volume of a cone = (πr²h)/3
Volume of a sphere = (4/3)πr³
So, if the base of the cone has a diameter of 10 cm, its radius is 5 cm. Its altitude is 10 cm. ⇒Volume = (πr²h)/3 ⇒ Volume = [π(5²)10) ⇒
Volume = 785.4 cm³. This is the initial volume of water.
Now if the sphere fits in the cone and half of it remains out of the water, the other half is inside the cone. Estimating the volume of the sphere and dividing it by two, you find the volume of water that was displaced.
Volume of a sphere = (4/3)πr³, here the radius is the same of the base of the cone (5 cm).
⇒ Volume = (4/3)π(5³) ⇒ Volume = 523.6 cm³ ⇒ The half of this volume is 261.8 cm³. This is the volume of water displaced.
⇒ The volume of water that remains on the cone is 523.6 cm³ (785.4 cm³- 261.8 cm³)
The value of 23 squared is 529
A square number or perfect square is an integer that is the square of an integer; in other words, it is the product of some integer with itself.
For example, the 3² is 3 × 3 i.e the product of the 3 by itself , which is 9
Similarly, the square of 23 is 23² which is the same as the 23 × 23
= 529
Therefore the square of 23 is 529. this means that 23² = 529 and the square root of 529 is 23.
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