Frank deposited $4000 into an account with 3% interest, compounded semiannually. Assuming that no withdrawals are made, how much will he have in the account after 5 years?

Answers

Answer 1

Answer:

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \n\n A=P\left(1+(r)/(n)\right)^(nt) \quad \begin{cases} A=\textit{accumulated amount}\n P=\textit{original amount deposited}\dotfill &\$4000\n r=rate\to 3\%\to (3)/(100)\dotfill &0.03\n n= \begin{array}{llll} \textit{times it compounds per year}\n \textit{semiannually, thus twice} \end{array}\dotfill &2\n t=years\dotfill &5 \end{cases} \n\n\n A=4000\left(1+(0.03)/(2)\right)^(2\cdot 5)\implies A=4000(1.015)^(10)\implies A\approx 4642.16$

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How do I solve this?

Answers

1) Multiply out the 2 to the 10, so it will become 3x-5=20 2) Then solve:3x=25 3)x=25/3

3x-5/2=10

The first step, multiply both sides by 2.
3x - 5 = 20

Add 5 to both sides.

3x = 25

Then divide both sides by 3.
x = 25/3 or 8.33333333...

Mrs. Harrison used 16 ounces of dark chocolate while baking. She used 2/5 of the chocolate to make some frosting and used the rest to make brownies. How much more chocolate did Mrs. Harrison use in the brownies than in the frosting

Answers

¹⁶/₅ or 3 ¹/₅ or 3.2 ounces.

Further explanation

Given:

Mrs. Harrison used 16 ounces of dark chocolate while baking.
She used ²/₅ of the chocolate to make some frosting.
She used the rest to make brownies.

Question:

How much more chocolate did Mrs. Harrison use in the brownies than in the frosting?

The Process:

From the information above, we made a suitable diagram as follows:

$\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}\boxed{\cdot} = 16 \ ounces$

Hence, one part equal to $(16)/(5) \ ounces$ .

She used $(2)/(5)$ of the chocolate to make some frosting, meaning two of five parts of the chocolate.

$\boxed{\cdot}\boxed{\cdot}$

And she used the rest, that is, $(3)/(5)$ of the chocolate to make brownies, meaning three of five parts of the chocolate.

$\boxed{\cdot}\boxed{\cdot}\boxed{\cdot}$

Finally, let us find out how much more chocolate did Mrs. Harrison use in the brownies than in the frosting. Before that, prepare in the form of a fraction of the part in question.

$\boxed{ \ = (3)/(5) - (2)/(5) \ }$

$\boxed{\boxed{ \ = (1)/(5) \ }}$ or one of five parts of the chocolate.

We declare this fraction into ounces by multiplying it by 16 ounces.

$\boxed{ \ = (1)/(5) * 16 \ ounces \ }$

$\boxed{\boxed{ \ (16)/(5) \ or \ 3(1)/(5) \ or \ 3.2 \ ounces \ }}$

Thus Mrs. Harrison used 3.2 ounces more chocolate in brownies than in the frosting.

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Keywords: Mrs. Harrison, used 16 ounces, dark chocolate, while baking, she used 2/5, to make some frosting, and used the rest to make brownies. How much more chocolate did Mrs. Harrison use in the brownies than in the frosting

1/5 bc 5/5=total. So u would do 5/5-3/5= 2/5. then 3/5-2/5= 1/5

#1 what is 18 in simplified radical form? Answers: A. 9 and 2 B. 2 and 9 C. 3 and 2 D. 2 and 3

#2 What is 28 in simplified radical form? A. 2 and 5 B. 2 and 7 C. 7 and 2 D. 4 and 7

#3 What is 252 in simplified radical form? A. 21 and 12 B. 12and 21 C. 7 and 6 D. 6 and 7

#4 A square fishpond has an area of 68 square feet. To the nearest tenth, what is the length of one side of the fishpond? A. 8.2 ft B. 9.4 ft C. 17.0 ft D. 34.0 ft

#5 A square-shaped billboard has an area of 295 square feet. Christy wants to put lights around the entire perimeter of the billboard.

Approximately how much frame does she need? A. 12 feet B. 17 feet C. 69 feet D. 74 feet

Answers

1. $√(18)= √(9*2)= 3√(2)$

Answer: C

2. $√(28)=√(4*7)=2√(7)$

Answer: B

3. $√(252)= √(36*7)=6√(7)$

Answer: D

4. $68ft^2=√(68)\approx8,3$

Answer: A

5. $252ft^2=√(252)\approx17,17$

BUT she want it all around so:

$17,17*4=68,68\approx69$

Answer: C

an artist is arranging tiles in rows to decorate a wall. each new row has 2 fewer tiles than the row below it. if the first row has 23 tiles, how many tiles will be in the 7th row?

Answers

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant

This problem is an Arithmetic Sequence

where

the first term is $23$

and

the common difference is $-2$

In general we can write an Arithmetic Sequence as a rule

$an=a1+d*(n-1)$

where

a1 is the first term

d is the common difference

$a1=23\n\n d=-2$

Find the term a7

$an=a1+d*(n-1)\n \n a7=23+(-2)*[7-1]\n \n\n a7=23-12\n \n\n a7=11$

therefore

the answer is

$11\ tiles$

There will be 11 tiles in the 7th row, Hope this helped! :)

What is 834,351 rounded to the nearest ten thousand

Answers

the answer is 830,000 because if the 4 would be above 5 the three would become 4.

What is the scientific notation of 1260000

Answers

1.26X10^6
The decimal in this number is at the end of the last zero. move that so that the non zero digit is less than 10 but greater than 1. which is 1.26, since we moved 6 places to the left, the exponent is 6.

The scientific notation of number $1260000$ would be $1.26 * 10^6$ .